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`#3107.101107`
\(3\left(x-32\right)-7=23\cdot5-50\)
\(\Rightarrow3\left(x-32\right)-7=115-50\)
\(\Rightarrow3\left(x-32\right)-7=65\)
\(\Rightarrow3\left(x-32\right)=65+7\)
\(\Rightarrow3\left(x-32\right)=72\)
\(\Rightarrow x-32=72\div3\)
\(\Rightarrow x-32=24\)
\(\Rightarrow x=24+32\)
\(\Rightarrow x=56\)
Vậy, `x = 56.`
\(3\left(x-32\right)-7=23.5-50\)
\(3\left(x-32\right)-7=115-50\)
\(3\left(x-32\right)-7=65\)
\(3\left(x-32\right)=65+7\)
\(3\left(x-32\right)=72\)
\(x-32=72:3\)
\(x-32=24\)
\(x=24+32\)
\(x=56\)
![](https://rs.olm.vn/images/avt/0.png?1311)
Ta có: 23.5 ⋮ 5 ; 70 ⋮ 5 .
Để x + 23.5 + 70 ⋮ 5 thì x phải chia hết cho 5 .
Trong các đáp án có 75 ⋮ 5 .
Vậy 75 là đáp án đúng.
![](https://rs.olm.vn/images/avt/0.png?1311)
a: =>41-(2x-5)=720:40=18
=>2x-5=23
=>2x=28
=>x=14
b: =>100x+5050=5750
=>100x=700
=>x=7
a: =>41-(2x-5)=720:40=18
=>2x-5=23
=>2x=28
=>x=14
b: =>100x+5050=5750
=>100x=700
=>x=7
![](https://rs.olm.vn/images/avt/0.png?1311)
\(\left(25\cdot21+25\cdot51\right):36\\ =\left[25\cdot\left(21+51\right)\right]:36\\ =\left(25\cdot72\right):36\\ =1800:36\\ =50\\ \left\{188-\left[33+\left(6^2-7\cdot3\right)\right]\right\}:70\\ =\left\{188-\left[33+\left(36-21\right)\right]\right\}:70\\ =\left[188-\left(33+15\right)\right]:70\\ =\left(188-48\right):70\\ =140:70\\ =2\)
\(\left(x-1\right)\left(15-3x\right)=0\\ \Rightarrow\left[{}\begin{matrix}x-1=0\\15-3x=0\end{matrix}\right.\\ \Rightarrow\left[{}\begin{matrix}x=1\\3x=15\end{matrix}\right.\\ \Leftrightarrow\left[{}\begin{matrix}x=1\\x=5\end{matrix}\right.\)
\(720:\left[41-\left(2x+5\right)\right]=2^3\cdot5=8\cdot5\\ \Rightarrow720:\left[41-\left(2x+5\right)\right]=40\\ \Rightarrow41-\left(2x+5\right)=720:40\\ \Rightarrow41-\left(2x+5\right)=18\\ \Rightarrow2x+5=41-18\\ \Rightarrow2x+5=23\\ \Rightarrow2x=23-5\\ \Rightarrow2x=18\\ \Rightarrow x=18:2\\ \Rightarrow x=9\)
![](https://rs.olm.vn/images/avt/0.png?1311)
5( x+7) -10 = 23 . 5
=> 5x + 35 - 10 = 8 .5
=> 5x + 25 = 40
=> 5x = 40 - 25 =15
=> x = 15 : 5 = 3
Vậy x = 3
\(5.\left(x+7\right)-10=2^3.5\)
\(5.\left(x+7\right)-10=8.5=40\)
\(5.\left(x+7\right)=40+10=50\)
\(x+7=50:5=10\)
\(x=10-7=3\)