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Khoảng cách : `5`
Số số hạng là :
\(\dfrac{526-11}{5}+1=104\)
Tổng dãy là :
\(\dfrac{\left(526+11\right)\times104}{2}=27924\)
h=11+16+...+526=\(\dfrac{\left(526-11\right):5+1\cdot\left(11+526\right)}{2}\)=\(\dfrac{104\cdot537}{2}\)=27924.
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a ) \(2x-\left(-17\right)=15\)
\(\Leftrightarrow2x+17=15\)
\(\Leftrightarrow2x=15-17\)
\(\Leftrightarrow2x=-2\)
\(\Leftrightarrow x=-2\div2\)
\(\Leftrightarrow x=-1\)
b ) \(-2x-8=72\)
\(\Leftrightarrow-2x=72+8\)
\(\Leftrightarrow-2x=80\)
\(\Leftrightarrow x=-40\)
a) 2x - ( -17 ) = 15
-> 2x + 17 = 15
2x = 15 - 17
2x = -2
x = \(\frac{-2}{2}\)
x = -1
b) -2x - 8 = 72
-2x = 72 + 8
-2x = 80
x = 80 : ( -2 )
x = -40
c) 3 . \([x-1]\)= 27
x - 1 = \(\frac{27}{3}\)
x - 1 = 9
x = 9 + 1
x = 10
d) \([-2x+5]\)+ 8 = 21
-2x + 5 = 21 - 8
-2x + 5 = 13
-2x = 13 - 5
-2x = 8
x = \(\frac{8}{-2}\)
x = - 4
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`@` `\text {Ans}`
`\downarrow`
`135 - 21.x = 72`
`\Rightarrow 21x = 135 - 72`
`\Rightarrow 21x = 63`
`\Rightarrow x = 63 \div 21`
`\Rightarrow x = 3`
Vậy, `x = 3.`
135−21.x=72
⇒21�=135−72⇒21x=135−72
⇒21�=63⇒21x=63
⇒�=63÷21⇒x=63÷21
⇒�=3⇒x=3
Vậy, �=3.x=3