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a: \(3\cdot3\cdot3\cdot3\cdot3=3^5\)
b: \(y\cdot y\cdot y\cdot y=y^4\)
a, 4 8 . 4 10 = 4 18
b, 2 20 . 2 7 = 2 27
c, 5 12 . 5 5 . 5 4 = 5 21
d, 4 3 . 4 5 . 4 5 = 4 13
e, 8 6 . 8 5 . 8 5 = 8 16
f, x 7 . x 4 . x 3 = x 14
\(a,5\cdot5\cdot5\cdot5=5^4\\b,9\cdot9\cdot9\cdot9\cdot9\cdot9\cdot9=9^7\\c,7\cdot7\cdot7\cdot7\cdot7=7^5\\d,a\cdot a\cdot a\cdot a\cdot a\cdot a\cdot a\cdot a=a^8\)
a) \(2.2.2.2.3.3.3.3=2^4.3^4\)
b) \(2.33.5555=2^1.3^2.5^4\)
c) \(5.5.5.5.4.4.4=5^4.4^3\)
d) \(8.8.10.25.16=2^3.2^3.2.5.5^2.2^4=2^{11}.5^3\)
a) 5.5.5.5.5 = 5 5
b) ( − 3 ) . ( − 3 ) . ( − 3 ) .3.3 = ( − 3 ) . ( − 3 ) . ( − 3 ) . ( − 3 ) . ( − 3 ) = ( − 3 ) 5
c) 2.2.2. ( − 5 ) . ( − 5 ) . ( − 5 ) = 2. ( − 5 ) . 2. ( − 5 ) . 2. ( − 5 ) = ( − 10 ) . ( − 10 ) . ( − 10 ) = ( − 10 ) 3
d) ( − 8 ) . ( − 5 ) 3 .64 = ( − 2 ) 3 . ( − 5 ) 3 .4 3 = ( − 2 ) . ( − 5 ) .4 3 = 40 3
Ta có:
12 . 12 . 12 . 2. 6 = 12 . 12 . 12 . 12 = 124
25 . 5 . 4 . 2 . 10 = 25 . 4 . 2 . 10 . 5 = 100 . 100 = 1002
2. 10 . 10 . 3 . 5. 10 = 10 . 10 . 10 . 2 . 5 . 3 = 10 . 10 . 10 . 10 . 3 = 104 . 3
a,12.12.2.12.6=12.12.12.(2.6)=12.12.12.12=124
b,25.5.4.2.10=(25.4)(5.2.10)=100.100=1002
c,2.10.10.3.5.10=10.10.10.2.5.3=10.10.10.10.3=104.3
a) \(...=10^5.10^2.10^2=10^9\)
b) \(...=\left(2^2.3\right).\left(2^2.3\right).\left(2^2.3\right).2.3=2^7.3^4\)
c) \(...=5^2.5.2^2.2.2.5=2^4.5^4\)
d) \(...=7.3.2.5.2.5.3.5.2.5=2^33^2.5^4.7\)
a/
\(100000.100.10.10=10^5.10^2.10.10=10^9=2^9.5^9\)
b/
\(12.12.12.6=2^2.3.2^2.3.2^2.3.2.3=2^7.3^4\)
c/
\(25.5.4.2.10=5^2.5.2^2.2.2.5=2^4.5^4\)
d/
\(210.10.3.5.10=21.10.10.3.5.10=3.7.2.5.2.5.3.5.2.5=2^3.3^2.5^4.7\)