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\(\frac{1}{11.16}+\frac{1}{16.21}+\frac{1}{21.26}+...+\frac{1}{61.66}\)
=\(\frac{1}{5}.\frac{5}{11.16}+\frac{1}{5}.\frac{5}{16.21}+\frac{1}{5}.\frac{5}{21.26}+...+\frac{1}{5}.\frac{5}{61.66}\)
=\(\frac{1}{5}.\left(\frac{5}{11.16}+\frac{5}{16.21}+\frac{5}{21.26}+...+\frac{5}{61.66}\right)\)
=\(\frac{1}{5}.\left(\frac{1}{11}-\frac{1}{16}+\frac{1}{16}-\frac{1}{21}+...+\frac{1}{61}-\frac{1}{66}\right)\)
=\(\frac{1}{5}.\left(\frac{1}{11}-\frac{1}{66}\right)\)
=\(\frac{1}{5}.\left(\frac{6}{66}-\frac{1}{66}\right)=\frac{1}{5}.\frac{5}{66}=\frac{1}{66}\)
Đặt A = \(\frac{1}{11.16}+...+\frac{1}{61.66}\)
5A = \(\frac{5}{11.16}+..+\frac{5}{61.66}\)
5a = \(\frac{1}{11}-\frac{1}{16}+\frac{1}{16}-\frac{1}{21}+...+\frac{1}{61}-\frac{1}{66}\)
5a = \(\frac{1}{11}-\frac{1}{61}\)
5a = 50/671
a = \(\frac{50}{671}:5=\frac{10}{671}\)
Ta có :
\(S=\frac{5^2}{1.6}+\frac{5^2}{6.11}+\frac{5^2}{11.16}+\frac{5^2}{16.21}+\frac{5^2}{21.26}\)
\(S=5\left(\frac{5}{1.6}+\frac{5}{6.11}+\frac{5}{11.16}+\frac{5}{16.21}+\frac{5}{21.26}\right)\)
\(S=5\left(\frac{1}{1}-\frac{1}{6}+\frac{1}{6}-\frac{1}{11}+\frac{1}{11}-\frac{1}{16}+\frac{1}{16}-\frac{1}{21}+\frac{1}{21}-\frac{1}{26}\right)\)
\(S=5\left(1-\frac{1}{26}\right)\)
\(S=5.\frac{25}{26}\)
\(S=\frac{125}{26}\)
Vậy \(S=\frac{125}{26}\)
Chúc bạn học tốt ~
Bài tập 1:
S=2/15+2/35+2/63+2/99+2/143
\(\Rightarrow\)S=2/3x5 +2/5x 7 +2/7x9 +2/9x11 +2/11x13
\(\Rightarrow\)S=1/3 -1/5 +1/5 - 1/7 +1/7 -1/9 +1/9 -1/11 +1/11 -1/13
\(\Rightarrow\)S=1/3 -1/13
\(\Rightarrow\)S=13/39 -3/39
\(\Rightarrow\)S=10/39
S=3/1.4 +3/4.7+3/7.11 ..........sai đề rồi
Bài 2
A=5/11.16+5/16.21+5/21.26+...+5/61.66
\(\Rightarrow\)A=1/11+1/16+1/16-1/21+1/21-1/26+....+1/61-1/66
\(\Rightarrow\)A=1/11-1/66
\(\Rightarrow\)A=6/66-1/66
\(\Rightarrow\)A=5/66
Bài 1 mik học xong quên hết òi (mấy bài kia là hok biết luôn :V)
4/5+3/7.x=1/3
3/7.x=1/3-4/5
3/7.x= -7/15
x= -7/15:3/7
x= -49/45
vay x= -49/45
\(\frac{3}{7}.x=\frac{1}{3}-\frac{4}{5}=-\frac{7}{15}\)
\(x=-\frac{7}{15}:\frac{3}{7}=-\frac{49}{75}\)
Đặt tử A là T ta có:
5T=5(1+5+52+...+59)
5T=5+52+...+510
5T-T=(5+52+...+510)-(1+5+52+...+59)
T=(510-1)/4
Mẫu A là H tính tương tự đc:(59-1)/4.Thay vào ta có:\(A=\frac{\frac{5^{10}-1}{4}}{\frac{5^9-1}{4}}=\frac{5^{10}-1}{5^9-1}\)
B tính tương tự A được \(\frac{3^{10}-1}{3^9-1}\) tới đây sao nx
Giải:
Ta có:
\(\frac{x}{2}=\frac{y}{3};\frac{y}{2}=\frac{z}{5}\)
\(\Rightarrow\frac{x}{4}=\frac{y}{6};\frac{y}{6}=\frac{z}{15}\)
\(\Rightarrow\frac{x}{4}=\frac{y}{6}=\frac{z}{15}\)
Theo tính chất dãy tỉ số bằng nhau, ta có:
\(\frac{x}{4}=\frac{y}{6}=\frac{z}{15}=\frac{x+y+z}{4+6+15}=\frac{50}{25}=2\)
+) \(\frac{x}{4}=2\Rightarrow x=8\)
+) \(\frac{y}{6}=2\Rightarrow y=12\)
+) \(\frac{z}{15}=2\Rightarrow z=30\)
Vậy x = 8
y = 12
z = 30
\(\frac{x}{2}=\frac{y}{3};\frac{y}{2}=\frac{z}{5}\) và x + y + z =50
\(\frac{x}{4}=\frac{y}{6};\frac{y}{6}=\frac{z}{15}\)
\(\Rightarrow\frac{x}{4}=\frac{y}{6}=\frac{z}{15}\)
Áp dụng dãy tỉ số bằng nhau ta có :
\(\frac{x}{4}+\frac{y}{6}+\frac{z}{15}=\frac{50}{25}=2\)
=> x = 2.4 = 8
=> y = 2.6 = 12
=> z = 2.15 = 30
Vậy x = 8;y = 12;z = 30.
a) 4/3 - x = 3/5 + 1/2
=> 4/3 - x= 0,8
=> x = 4/3 + 0/8
=> x = 5/8
1) \(\frac{3^{2014}.8^{19}}{6^{60}.3^{1955}}=\frac{3^{2014}.\left(2^3\right)^{19}}{\left(2.3\right)^{60}.3^{1955}}=\frac{3^{2014}.2^{57}}{2^{60}.3^{2015}}=\frac{1}{2^3.3}=\frac{1}{24}\)
2) \(5^x+5^{x+1}=150\)
=> 5x(1 + 5) = 150
=> 5x.6 = 150
=> 5x = 25
=> \(x=\pm2\)
3) \(\frac{3}{11.16}+\frac{3}{16.21}+...+\frac{3}{61.66}=\frac{3}{5}\left(\frac{5}{11.16}+\frac{5}{16.21}+...+\frac{5}{61.66}\right)\)
\(=\frac{3}{5}\left(\frac{1}{11}-\frac{1}{16}+\frac{1}{16}-\frac{1}{21}+...+\frac{1}{61}-\frac{1}{66}\right)=\frac{3}{5}.\left(\frac{1}{11}-\frac{1}{66}\right)=\frac{3}{5}.\frac{5}{66}=\frac{1}{22}\)
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