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a) 12 - 6 = 6
b) 23 - (-35) = 58
c) = 109
Bài 2: a) = 1
b) -3
c) = 8
a.12-6=6
b.23-(-35)=23-35=-12
c.(-145)-(-254)= - (145+254)=-399
a. 12-6 =6
b. 23-(-35)=23+35=58
c.(-145)-(-254)=(-145)+254=254-145=109
a) 23 - ( - 35 ) = 23 + 35 = 58
b) ( - 145 ) - ( - 254 ) = ( - 145) + 254 = 109
c) \([\left(-3\right)-4]+8=\left(-7\right)+8=1\)
d) 0 - ( - 2 ) + 6 = 2 + 6 = 8
c) Ta có: \(\dfrac{3}{5}+\dfrac{-5}{20}+\dfrac{30}{75}+\dfrac{-7}{4}\)
\(=\dfrac{3}{5}+\dfrac{2}{5}+\dfrac{-1}{4}+\dfrac{-7}{4}\)
\(=1-2=-1\)
Giải:
a)-1/12+4/3=-1/12+16/12=15/12=5/4
b)(-4/14-3/15)-(1/5-20/35-(-1)).7
=-17/35-22/35.7
=-17/35-22/5
=-171/35
c)3/5+-5/20+30/75+-7/4
=3/5+-1/4+2/5+-7/4
=(3/5+2/5)+(-1/4+-7/4)
=1+-2
=-1
d)5/6.-12/14+7/13
=-5/7+7/13
=-16/91
e)2/-9-5/-36-1/4
=-1/12-1/4
=-1/3
f)2/23+-5/12+7/18+21/23+-7/12
=(2/23+21/23)+(-5/12+-7/12)+7/18
=1+-1+7/18
=7/18
a) 17.(-183)+17.83
= 17.(-183+83)
= 17.100=1700
b) (-27).145+27.45
= 27.(-145)+27.45
= 27.(-145+45)
= 27.100=2700
c) -38.(25-4)+25.(-4+38)
= -38.25-(-38).4+25.(-4)+25.38
= -38.25+25.38+38.4+25.(-4)
= 0+38.4+(-25).4
= 4.(-25+38)
= 4.13=52
d) 23.(145-17)-145.(23-37)
= (23.145-23.17)-(145.23+145.37)
= [23.(145-17)]-[145.(23+37)]
= (23.128)-(145.60)
= 2944-8700=-5756
A)\(\frac{254\cdot399-145}{254+399\cdot253}\)
\(=\frac{\left(253+1\right)\cdot399-145}{254+399\cdot253}\)
\(=\frac{253\cdot399+1\cdot399-145}{254+399\cdot253}\)
\(=\frac{253\cdot399+399-145}{254+399\cdot253}\)
\(=\frac{253\cdot399+254}{254+399\cdot253}\Rightarrow=1\)
B) X x X - 1/6 = 5/18
x2 = 5/18 + 1/6
x2 = 8/18 = 4/9
x= \(\sqrt{\frac{4}{9}}\) \(=\frac{2}{3}\)
1.73.(8-59)-59.(8-73)
=73.8-73.59-59.8-59.73
=73.(59-59)-8.(73-59)
=73.0-8.14
=0-112
=-112
2.159.(18-59)-59.(18 - 159)
=159.18-59.159-59.18-59.159
=159.(59-59)-18.(159-59)
=159.0-18.100
=0-1800
=-1800
A)6. B) -12. C ) -399
Tich cho mik nha