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sắp ăn nội quy oy đó babe
chúc may mắn
( trẩu oy tặng nó nội quy ik ♥)
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\(\frac{x+73}{27}+1+\frac{x+74}{26}+1=\frac{x+27}{73}+1+\frac{x+26}{74}+1\)
\(\frac{x+73+27}{27}+\frac{x+74+26}{26}=\frac{x+27+73}{73}+\frac{x+26+74}{74}\)
\(\frac{x+100}{27}+\frac{x+100}{26}=\frac{x+100}{73}+\frac{x+100}{74}\)
\(\left(x+100\right)\left(\frac{1}{27}+\frac{1}{26}-\frac{1}{73}-\frac{1}{74}\right)=0\)
mà \(\frac{1}{27}+\frac{1}{26}-\frac{1}{73}-\frac{1}{74}\ne0\)
\(\Rightarrow x+100=0\Rightarrow x=-100\)
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x^2+x^2=x*x+x*x=x*(x+x).
Ko biết có phải ko mk ms lớp 6.
Ủng hộ nhá!
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Ta có : \(\frac{x-12}{77}+\frac{x-11}{78}=\frac{x-74}{15}+\frac{x-73}{16}\)
\(\Rightarrow\frac{x-12}{77}-1+\frac{x-11}{78}-1=\frac{x-74}{15}-1+\frac{x-73}{16}-1\)
\(\Rightarrow\frac{x-89}{77}+\frac{x-89}{78}=\frac{x-89}{15}+\frac{x-89}{16}\Rightarrow\left(x-89\right).\left(\frac{1}{77}+\frac{1}{78}\right)=\left(x-89\right).\left(\frac{1}{15}+\frac{1}{16}\right)\)
=> \(\left(x-89\right).\left(\frac{1}{77}+\frac{1}{78}\right)-\left(x-89\right)\left(\frac{1}{15}+\frac{1}{16}\right)=0\)
=> \(\left(x-89\right).\left[\left(\frac{1}{77}+\frac{1}{78}-\frac{1}{15}-\frac{1}{16}\right)\right]=0\Rightarrow x-89=0\left(\text{vì }\frac{1}{77}+\frac{1}{78}-\frac{1}{15}-\frac{1}{16}\ne0\right)\)
=> x = 89
Vậy x = 89
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\(\dfrac{x-12}{77}+\dfrac{x-11}{78}=\dfrac{x-74}{15}+\dfrac{x-73}{16}\)
\(\Rightarrow\dfrac{x-12}{77}+\dfrac{x-11}{78}-\dfrac{x-74}{15}-\dfrac{x-73}{16}=0\)
\(\Rightarrow\dfrac{x-12}{77}-1+\dfrac{x-11}{78}-1-\dfrac{x-74}{15}+1-\dfrac{x-73}{16}+1=0+1+1-1-1\)
\(\Rightarrow\left(\dfrac{x-12}{77}-1\right)+\left(\dfrac{x-11}{78}-1\right)-\left(\dfrac{x-74}{15}-1\right)-\left(\dfrac{x-73}{16}-1\right)=0\)
\(\Rightarrow\dfrac{x-89}{77}+\dfrac{x-89}{78}-\dfrac{x-89}{15}-\dfrac{x-89}{16}=0\)
\(\Rightarrow\left(x-89\right)\left(\dfrac{1}{77}+\dfrac{1}{78}-\dfrac{1}{15}-\dfrac{1}{16}\right)=0\)
\(\Rightarrow\left[{}\begin{matrix}x-89=0\\\dfrac{1}{77}+\dfrac{1}{78}-\dfrac{1}{15}-\dfrac{1}{16}=0\end{matrix}\right.\)
\(x-89=0\\ \Rightarrow x=89\)
\(\dfrac{1}{77}+\dfrac{1}{78}-\dfrac{1}{15}-\dfrac{1}{16}=0\)(vô lí)
Vậy \(x=89\)
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\(x^2+3y^2+2xy-18\left(x+y\right)=73\)
\(\Leftrightarrow x^2+3y^2+2xy-18x-18y-73=0\)
\(\Leftrightarrow x^2-2\left(9-y\right)x+3y^2-18y-73=0\)
\(\Delta'=\left(9-y\right)^2-\left(3y^2-18y-73\right)\)
\(=81-18y+y^2-3y^2+18y+73\)
\(=-2y^2+154\)
\(=-2\left(y^2-77\right)\)
Phương trình có nghiệm khi \(\)
\(\Delta'\ge0\Leftrightarrow-2\left(y^2-77\right)\ge0\Leftrightarrow y^2-77\le0\)
\(\Leftrightarrow y^2\le77\Leftrightarrow-\sqrt[]{77}\le y\le\sqrt[]{77}\)
Phương trình có 2 nghiệm là
\(\left[{}\begin{matrix}x_1=9-y+\sqrt[]{-2\left(y^2-77\right)}\\x_2=9-y-\sqrt[]{-2\left(y^2-77\right)}\end{matrix}\right.\) \(\left(-\sqrt[]{77}\le y\le\sqrt[]{77}\right)\)
406
mik kb rồi chỉ cần bạn chấp nhận thôi nha !
x + 73 = 479
x = 479 - 73
x = 406