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a.(-2)+(-6)+2+(-15)+6
=[(-2)+2]+[(-6)+6]+(-15)
= 0 + 0 + (-15)
= -15
b.|x| =60 => x∈{60;-60}
![](https://rs.olm.vn/images/avt/0.png?1311)
a) x = 64 : 8 = 8
b) x = 60 : − 15 = − 4
c)
12 x = 30 − 6 12 x = 24 x = 24 : 12 x = 2
d)
− 11 . x = 130 − 9 − 11 . x = 121 x = 121 : − 11 x = − 11
![](https://rs.olm.vn/images/avt/0.png?1311)
a) x = 64 : 8 = 8
b) x = 60 : − 15 = − 4
c)
12 x = 30 − 6 12 x = 24 x = 24 : 12 x = 2
d)
− 11 . x = 130 − 9 − 11 . x = 121 x = 121 : − 11 x = − 11
![](https://rs.olm.vn/images/avt/0.png?1311)
\(a,\dfrac{x}{10}=\dfrac{-11}{5}\Rightarrow x.5=10.\left(-11\right)=-110\\ \Rightarrow-22\\ b,\dfrac{-6}{x}=\dfrac{30}{60}\Rightarrow-6.60=x.30=-120\\ \Rightarrow x=-4\)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(a.\frac{x}{-15}=\frac{60}{2}\)
\(\Rightarrow2x=60\times\left(-15\right)\)
\(\Rightarrow2x=-900\)
\(\Rightarrow x=-900\div2\)
\(\Rightarrow x=-450\)
![](https://rs.olm.vn/images/avt/0.png?1311)
a) Ta có: Ư(40) = {1;2;4;5;8;10;20;40}
Do đó: A = {8; 10; 20; 40}
b) Ta có: B(12) = {0;12;24;36;48;60;72;...}
Do đó: B = {24; 36; 48; 60}
x=0;6;12;18;24;30;36;42;48;54
B ( 6 ) = { 0 ; 6 ; 12 ; 18 ; 24 ; 30 ; 36 ; 42 ; 48 ; 54 ; 60 ; 66 ; ... }
Vì x < 60 nên x ϵ { 0 ; 6 ; 12 ; 18 ; 24 ; 30 ; 36 ; 42 ; 48 ; 54 }