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(x +1) + (x+2) +...+(x+8) + (x+9) = 54
x +1 + x+2 +...+x+8 + x+9 = 54
9x + (1+9) + (2+8) + (3+7) + (4+6) + 5 = 54
9x + 45 = 54
9x = 9
x = 1
Khoang cach cua day so tren la 5
So cac so hang la:
[54-4]:5+1=11[so]
Tong day so tu 4 den 54 la
[54+4]x11:2=319
=>x x 11+319=1430
x x 11 =1430-319
x x 11 =1111
x =1111:11
x =101
Bài 1:
a) 43+45+47+...+565 [có (565-43)/2+1= 262 số hạng)
= [(565+43)*262]/2
= 79648
b) 21+24+27+...+318 [có (318-21)/3+1= 100 số hạng]
= [(318+21)*100]/2
= 16950
\(\text{(x+1)+(x+2)+(x+3)+(x+4)+(x+5)+(x+6)+(x+7)+(x+8)+(x+9)=54}\)
\(\text{x+1+x+2+x+3+x+4+x+5+x+6+x+7+x+8+x+9=54}\)
\(9x+\left(1+2+3+4+5+6+7+8+9\right)=54\)
\(9x-45=54\)
\(9x=99\)
\(x=11\)
\(\text{(x+1)+(x+2)+(x+3)+(x+4)+(x+5)+(x+6)+(x+7)+(x+8)+(x+9)=54}\)
\(\text{x+1+x+2+x+3+x+4+x+5+x+6+x+7+x+8+x+9=54}\)
\(\text{9x + 1 + 2 + 3 + 4 + 5 + 6 + 7 + 8 + 9 = 54 }\)
\(\text{9x − 45 = 54 }\)
\(\text{9x = 99 }\)
\(\text{x = 11}\)
a)\(x\times17,7-7,7\times x=177\)
\(x\times\left(17,7-7,7\right)=177\)
\(x\times10=177\)
\(x=177\div10\)
\(x=17,7\)
b) \(9\times\left(12-2\times x\right)=54\)
\(12-2\times x=54\div9\)
\(12-2\times x=6\)
\(2\times x=12-6\)
\(2\times x=6\)
\(x=6\div2\)
\(x=3\)
c) \(x\times3,9+x\times0,1=16\)
\(x\times\left(3,9+0,1\right)=16\)
\(x\times4=16\)
\(x=16\div4\)
\(x=4\)
a) \(x\times17,7-7,7\times x=177\)
\(x\times\left(17,7-7,7\right)=177\)
\(x\times10=177\)
\(x=177:10\)
\(x=17,7\)
b) \(9\times\left(12-2\times x\right)=54\)
\(12-2\times x=54:9\)
\(12-2\times x=6\)
\(2\times x=12-6\)
\(2\times x=6\)
\(x=6:2\)
\(x=4\)
c) \(x\times3,9+x\times0,1=16\)
\(x\times\left(3,9+0,1\right)=16\)
\(x\times4=16\)
\(x=16:4\)
\(x=4\)
\(#Nulc`\)
a) (x + 1) + (x + 2) + (x + 3) + ... + (x + 9) = 54
(x + x + x + ... + x) + (1 + 2 + 3 + ... + 9) = 54
9x + 45 = 54
9x = 54 - 45
9x = 9
x = 1
b) (x + 1) + (x + 2) + (x + 3) + ... + (x + 10) = 2010
(x + x + x + ... + x) + (1 + 2 + 3 + ... + 10) = 2010
10x + 55 = 2010
10x = 2010 - 55
10x = 1955
x = 391/2.
1)\(\left(x+1\right)+\left(x+2\right)+\left(x+3\right)+....+\left(x+9\right)=54\)
\(\Rightarrow x+1+x+2+x+3+.....+x+9=54\)
\(\Rightarrow\left(x+x+x+....+x\right)+\left(1+2+3+....+9\right)=54\)
\(\Rightarrow9x+45=54\)\(\Rightarrow9x=9\Rightarrow x=1\)
2)\(\left(x+1\right)+\left(x+2\right)+\left(x+3\right)+....+\left(x+10\right)=2010\)
\(\Rightarrow x+1+x+2+x+3+.....+x+10=2010\)
\(\Rightarrow\left(x+x+x+....+x\right)+\left(1+2+3+....+10\right)=2010\)
\(\Rightarrow10x+55=2010\Rightarrow10x=1995\Rightarrow x=195,5\)
#)Giải :
\(\frac{2}{9}.\frac{5}{17}+\frac{2}{9}.\frac{13}{17}-\frac{2}{9}.\frac{1}{17}+2018\frac{7}{9}\)
\(=\frac{2}{9}\left(\frac{5}{17}+\frac{13}{17}-\frac{1}{17}\right)+2018\frac{7}{9}\)
\(=\frac{2}{9}.1+2018\frac{7}{9}\)
\(=\frac{2}{9}+2018\frac{7}{9}\)
\(=2018\frac{9}{9}=2019\)
#~Will~be~Pens~#
x * 17 + x - 9 = 54
x * 17 + x = 54 + 9
x * ( 17 + 1 ) = 63
x * 18 = 63
x = 63 : 18
x = 3.5
\(x\times17+x-9=54\)
\(\Rightarrow x\times\left(17+1\right)-9=54\)
\(\Rightarrow x\times18=54+9\)
\(\Rightarrow x\times18=63\)
\(\Rightarrow x=\frac{63}{18}\)
\(\Rightarrow x=\frac{7}{2}\)
Vậy \(x=\frac{7}{2}\)