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Đặt A= 1.2+2.3 +.......+99.100
3A= 1.2.3+2.3.4+3.4.3 +......+ 99.100.3
3A= 1.2. (3 - 0) + 2.3.(4 - 1) +3.4. (5 - 2)....... . 99.100. (101 - 98)
3A = (1.2.3 + 2.3.4 + 3.4.5 +...... + 99.100.101) - (0.1.2 + 1.2.3 + 2.3.4 +.......+ 98.99.100)
3A = 99.100.101 - 0.1.2
3A = 999900 - 0
3A= 999900
A= 999900 : 3
A = 333300
A=1.2+2.3+3.4+…+99.100
3A = 1.2.3 + 2.3.3 + ... + 99.100.3
3A = 1.2.3 + 2.3.(4-1) + ... + 99.100.(101-98)
3A = 1.2.3 + 2.3.4 - 1.2.3 + ... + 99.100.101 - 98.99.100
3A = 99.100.101
=> A = \(\frac{99.100.101}{3}\)= 333 300
Ta có:
3S = 1.2.3 + 2.3.4 + 3.4.3 + ... + 99.100.3
3S = 1.2 ( 3 - 0 ) + 2.3. ( 4 - 1 ) + 3.4 . ( 5 - 2 )............... 99.100 . ( 101 - 98 )
3S = ( 1.2.3 + 2.3.4 + 3.4.5 + ... + 99.100.101 ) - ( 0.1.2 + 1.2.3 + 2.3.4 + ... + 98.99.100 )
3S = 99.100.101 - 0.1.2
3S = 999900 - 0
3S = 999900
S = 999900 : 3
S = 333300
Gọi A là biểu thức ta có:
A = 1.2+2.3+3.4+......+99.100
Gấp A lên 3 lần ta có:
A . 3 = 1.2.3 + 2.3.3 + 3.4.3 + … + 99.100.3
A . 3 = 1.2.3 + 2.3.(4 - 1) + 3.4.( 5 - 2) + … + 99.100. (101 - 98)
A . 3 = 1.2.3 + 2.3.4 - 1.2.3 + 3.4.5 - 2.3.4 + … + 99.100.101 - 98.99.100
A . 3 = 99.100.101
A = 99.100.101 : 3
A = 33.100.101
A = 333 300
Đặt S=1.2+2.3+.........+2011.2012
3S=1.2.3+2.3.(4-1)+...........+2011.2012.(2013-2010)
3S=1.2.3+2.3.4-1.2.3+...........+2011.2012.2013-2010.2011.2012
3S=2011.2012.2013
S=2011.2012.2013:3
S=2714954572
Đặt A = 1.2 + 2.3 + 3.4 + ... + 2011.2012
=> 3A = 1.2.3 + 2.3.3 + 3.4.3 + ... + 2011.2012.3
=> 3A = 1.2.(3 - 0) + 2.3.(4 - 1) + 3.4.(5 - 2) + ... + 2011.2012.(2013 - 2010)
=> 3A = 1.2.3 - 0 + 2.3.4 - 1.2.3 + 3.4.5 - 2.3.4 + ... + 2011.2012.2013 - 2010.2011.2012
=> 3A = 2011.2012.2013
=> A = \(\frac{2011.2012.2013}{3}=2714954572\).
Ta có: A=1.2+2.3+...+198.199+199.200
=>3A=1.2.3+2.3.3+...+198.199.3
+199.200.3
=>3A=1.2.3+2.3(4-1)+...+
198.199(200-197)+199.200(201-198)
=>3A=1.2.3+2.3.4-1.2.3+...+198.199.200
-197.198.199+199.200.201-198.199.200
=>3A=199.200.201
=>A=199.200.67
A=39800.67
A=2666600
Ta có : A = 1.2 + 2.3 + 3.4 + ..... + 49.50
=> 3A = 1.2.3 - 1.2.3 + 2.3.4 - 2.3.4 + .... + 49.50.51
=> 3A = 49.50.51
= >A = 49.50.51/3 = 41650
Ta có : A=1.2+2.3+3.4+....+2015.2016
=>3A= 1.2.3 + 2.3.3 + 3.4.3 + 4.5.3 + ... + 2017.2018.3
=>3A= 1.2.3 + 2.3.( 4 - 1 ) + 3.4.( 5-2 ) + 4.5.( 6-3 ) + ... 2017 . 2018 . ( 2019 - 2016 )
=>3A=-1.2.3 + 2.3.4 - 2.3.1 + 3.4.5 - 3.4.2 + 4.5.6 - 4.5.3 +.....+ 2017 . 2018 .2019 - 2017 . 2018 . 2016
=>A= 2017 . 2018 . 2019
333...3x666...6=333...3x(3x222...2)=999...9x222...2=(1000...0-1)x222...2=1000...0x222...2-222...2=222...2000...0-222...22
A = 1.2 + 2.3 + 3.4 + ... + 2013.2014
3A = 1.2.3 + 2.3.3 + 3.4.3 + ... + 2013.2014.3
Mà :
1.2.3 = 1.2.3
2.3.3 = 2.3.4 - 2.3.1
3.4.3 = 3.4.5 - 3.4.2
2012.2013.3 = 2012.2013.2014 - 2012.2013.2011
2013.2014.3 = 2013.2014.2015 - 2013.2014.2012
Cộng tất cả, vế theo vế ---> 3S = 2013.2014.2015
=> A = 2013.2014.2015 / 3 = 2723058910
S=1.2+2.3+3.4+4.5+...+98.99+99.100
suy ra :3S=1.2.3+2.3.3+3.4.3+4.5.3+...+98.99.3+99.100.3
3S=1.2.(3-0)+2.3.(4-1)+3.4.(5-2)+4.5.(6-3)+...+98.99.(100-97)+99.100.(101-98)
3S=1.2.3.0+2.3.4-1.2.3+3.4.5-2.3.4+4.5.6-3.4.5+...+98.99.100-97.98.99+99.100.101-98.99.100
3S=99.100.101
Suy ra :S=99.100.10:3=333300
vậy S=333300
=> 3A = 1.2.3 + 2.3.3 + 3.4.3 + .... + 49.50.3
=> 3A = 1.2.3 + 2.3.( 4 - 1 ) + 3.4.( 5 - 2 ) + .... + 49.50.( 51 - 48 )
=> 3A = 1.2.3 + 2.3.4 - 1.2.3 + 3.4.5 - 2.3.4 + .... + 49.50.51 - 48.49.50
=> 3A = ( 1.2.3 - 1.2.3 ) + ( 2.3.4 - 2.3.4 ) + .... + ( 48.49.50 - 48.49.50 ) + 49.50.51
=> 3A = 49.50.51
=> A = ( 49.50.51 ) : 3
=> A = 41650
A = 1.2 + 2.3 + 3.4 + ..... + 49.50
3A=1.2.3+2.3.3+3.4.3+...+49.50.3
3A=1.2.3+2.3.(4-1)+3.4.(5-2)+...+48.49.(50-47)+49.50.(51-48)
3A=1.2.3+2.3.4-1.2.3+3.4.5-2.3.4+...+48.49.50-47.48.49+49.50.51-48.49.50
3A=(1.2.3-1.2.3)+(2.3.4-2.3.4)+...(47.48.49-47.48.49)-(48.49.50-48.49.50)+49.50.51
3A=0+0+...+0+0+49.50.51
3A=49.50.51
A=\(\frac{49.50.51}{3}\)
A=41650
Đáp số: A=41650