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19 tháng 3 2023

Tìm x:

\(a.\dfrac{35}{28}-x=\dfrac{5}{14}\\ x=\dfrac{35}{28}-\dfrac{5}{14}\\ x=\dfrac{25}{28}\\ b.\dfrac{6}{7}\times x=\dfrac{2}{3}\\ x=\dfrac{2}{3}:\dfrac{6}{7}\\ x=\dfrac{7}{9}\\ c.x\times7=\dfrac{3}{4}\\ x=\dfrac{3}{4}:7\\ x=\dfrac{3}{28}\\ d.2:x-\dfrac{1}{3}=\dfrac{2}{5}\\ 2:x=\dfrac{2}{5}+\dfrac{1}{3}\\ 2:x=\dfrac{11}{15}\\ x=2:\dfrac{11}{15}\\ x=\dfrac{30}{11}.\)

19 tháng 3 2023

\(a,\dfrac{35}{28}-x=\dfrac{5}{14}\)

\(x=\dfrac{35}{28}-\dfrac{5}{14}\)

\(x=\dfrac{25}{28}\)

 

\(b,\dfrac{6}{7}\times x=\dfrac{2}{3}\)

\(x=\dfrac{2}{3}:\dfrac{6}{7}\)

\(x=\dfrac{7}{9}\)

 

\(c,x\times7=\dfrac{3}{4}\)

\(x=\dfrac{3}{4}:7\)

\(x=\dfrac{3}{28}\)

 

\(d,2:x-\dfrac{1}{3}=\dfrac{2}{5}\)

\(2:x=\dfrac{2}{5}+\dfrac{1}{3}\)

\(2:x=\dfrac{11}{15}\)

\(x=2:\dfrac{11}{15}\)

\(x=\dfrac{30}{11}\)

#YVA

a: =>x=5/4-5/14=25/28

b: =>x=6/7:2/3=6/7*3/2=18/14=9/7

12 tháng 3 2023

a) \(\dfrac{35}{28}-x=\dfrac{5}{14}\)

\(\dfrac{35}{28}-x=\dfrac{10}{28}\)

\(x=\dfrac{35}{28}-\dfrac{10}{28}\)

\(x=\dfrac{25}{28}\)

b) \(\dfrac{6}{7}:x=\dfrac{2}{3}\)

\(x=\dfrac{6}{7}:\dfrac{2}{3}=\dfrac{6}{7}\times\dfrac{3}{2}\)

\(x=\dfrac{9}{7}\)

18 tháng 3 2021

a)\(x+\frac{15}{16}+\frac{7}{8}=\frac{15}{4}\)

\(x+\frac{29}{16}=\frac{15}{4}\)

\(x=\frac{15}{4}-\frac{29}{16}\)

\(x=\frac{31}{16}\)

b)\(x-\frac{27}{28}-\frac{9}{14}=\frac{13}{7}\)

\(x-\frac{45}{28}=\frac{13}{7}\)

\(x=\frac{13}{7}+\frac{45}{28}\)

\(x=\frac{97}{28}\)

c)\(x\times\frac{1}{5}+x+\frac{1}{6}=\frac{2}{3}\)

\(x\times\frac{1}{5}+x=\frac{2}{3}-\frac{1}{6}\)

\(x\times\left(\frac{1}{5}+1\right)=\frac{1}{2}\)

\(x\times\frac{6}{5}=\frac{1}{2}\)

\(x=\frac{1}{2}:\frac{6}{5}\)

\(x=\frac{5}{12}\)

d)\(x:14=\frac{1}{4}+\frac{2}{9}+\frac{3}{4}\)

\(x:14=\frac{11}{9}\)

\(x=\frac{11}{9}\times14\)

\(x=\frac{154}{9}\)

#H

18 tháng 3 2021
a.x+15/16+7/8=15/4 X+29/16=15/4 X=15/4-29/16 X=31/16
27 tháng 7 2020

a, \(\frac{2}{3}:\frac{5}{7}:\frac{x}{9}=\frac{2}{7}:\frac{3}{5}:\frac{10}{9}\Leftrightarrow\frac{2\times7\times9}{3\times5\times x}=\frac{2\times5\times9}{7\times3\times10}\Leftrightarrow\frac{42}{5\times x}=\frac{3}{7}\Leftrightarrow294=15\times x\Leftrightarrow x=19,6\)

Các phần sau tương tự.

Dùng phương pháp nhân chéo và kiểm tra trình độ tính toán, khả năng rút gọn.

Thay kết quả vào x để kiểm tra lại bài.

a: =>x+7/4=6:2/3=9

=>x=29/4

b: =>x:5/3=7/5

=>x=7/5*5/3=7/3

c:=>x+1/6=5/3

=>x=10/6-1/6=3/2

d: =>x+4/5=4/5+3/7+3/5

=>x=3/7+3/5=36/35

e: =>x/35=4/5-5/7=3/35

=>x=3

f: =>13/28+x=1/2

=>x=1/28

g: =>1/3-x=1/9

=>x=2/9

a: =>x=3/7+3/5=15/35+21/35=36/35

b: =>x/35=4/5-5/7=28/35-25/35=3/35

=>x=3

c: =>x<3/4+8/4=11/4

=>\(x\in\left\{0;1;2;3\right\}\)

d: =>5/3<x<5/6+24/6=29/6

=>\(x\in\left\{2;3;4\right\}\)

e: =>x<10/12-9/12=1/12

=>x=0

f: =>2/3<x<12/6-5/6=7/6

=>x=1

18 tháng 4 2023

a) x - 3/2 = 4/3 

    x = 4/3 + 3/2

    x = 8/6 + 9/6 = 17/6

b) 2/5 * x = 1/3

    x = 1/3 : 2/5

    x = 1/3 x 5/2 = 5/6

c) x - 4/9 = 3/7 : 9/14

    x - 4/9 = 2/3

    x = 2/3 + 4/9

    x = 6/9 + 4/9 = 10/9

d) 3/5 * x - 1/2 = 1/5

    3/5 * x = 1/5 + 1/2 = 7/10

    x = 7/10 : 3/5

    x = 7/10 * 5/3 = 7/6

18 tháng 4 2023

a/\(x-\dfrac{3}{2}=\dfrac{4}{3}\)
\(x=\dfrac{4}{3}+\dfrac{3}{2}\)
\(x=\dfrac{17}{6}\)
b/\(\dfrac{2}{5}\times x=\dfrac{1}{3}\)
\(x=\dfrac{1}{3}:\dfrac{2}{5}\)
\(x=\dfrac{5}{6}\)
c/\(x-\dfrac{4}{9}=\dfrac{3}{7}:\dfrac{9}{14}\)
\(x-\dfrac{4}{9}=\dfrac{2}{3}\)
\(x=\dfrac{2}{3}+\dfrac{4}{9}\)
\(x=\dfrac{10}{9}\)
d/\(\dfrac{3}{5}\times x-\dfrac{1}{2}=\dfrac{1}{5}\)
\(\dfrac{3}{5}\times x=\dfrac{1}{5}+\dfrac{1}{2}\)
\(\dfrac{3}{5}\times x=\dfrac{7}{10}\)
\(x=\dfrac{7}{10}:\dfrac{3}{5}\)
\(x=\dfrac{7}{6}\)

16 tháng 4 2022

Giúp

16 tháng 4 2022

\(\dfrac{3}{7}\times x=\dfrac{1}{3}\)

\(x=\dfrac{1}{3}:\dfrac{3}{7}\)

\(x=\dfrac{7}{9}\)

 

\(x:\dfrac{6}{8}=\dfrac{2}{5}\)

\(x=\dfrac{2}{5}\times\dfrac{6}{8}\)

\(x=\dfrac{6}{20}=\dfrac{3}{10}\)

 

\(x-\dfrac{2}{3}=\dfrac{5}{6}\)

\(x=\dfrac{5}{6}+\dfrac{2}{3}\)

\(x=\dfrac{9}{6}=\dfrac{3}{2}\)

 

\(x-\dfrac{2}{5}-\dfrac{4}{35}=\dfrac{1}{7}\)

\(x=\dfrac{1}{7}+\dfrac{4}{35}+\dfrac{2}{5}\)

\(x=\dfrac{23}{35}\)

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