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a, (-25) + 276 - (276 - 25)
= (-25) + 276 - 276 + 25
= [ (-25) + 25] - (276 - 276)
= 0 - 0
= 0
b, 24 x 46 + 24 x 53 + 24
= 24 x ( 46 + 53 + 1)
= 24 x 100
= 2400
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2:
1: =>36x+14x=69+81=150
=>50x=150
=>x=3
2: 3^x=81
=>3^x=3^4
=>x=4
3: 3(2x+1)^2=75
=>(2x+1)^2=25
=>2x+1=5 hoặc 2x+1=-5
=>x=-3 hoặc x=2
1:
1: \(\dfrac{13\cdot17^4+4\cdot17^4}{17^3}-\dfrac{14\cdot3^3-14\cdot3^2}{9}\)
\(=\dfrac{17^4\cdot\left(13+4\right)}{17^3}-\dfrac{14\cdot3^2\left(3-1\right)}{9}\)
\(=17\cdot17-14\cdot2\)
=289-28
=261
2:
\(2^3\cdot5^2-\left[131-\left(23-2^3\right)^2\right]\)
\(=8\cdot25-131+\left(-1\right)^2\)
=69+1
=70
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276 + ( 56 - x ) = 1339 - 13
276 + ( 56 - x ) = 1326
56 - x = 1326 - 276
56 - x = 1050
x = 56 - 1050
x = ( - 994 )
k mình nha
Chúc bạn học giỏi
Mình cảm ơn bạn nhiều
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Hình như để như này :
\(\frac{x+1}{2014}+\frac{x+2}{2013}+\frac{x+3}{2012}+3=0\)
\(\left(\frac{x+1}{2014}+1\right)+\left(\frac{x+2}{2013}+1\right)+\left(\frac{x+3}{2012}+1\right)=0\)
\(\Leftrightarrow\frac{x+2015}{2014}+\frac{x+2015}{2013}+\frac{x+2015}{2012}=0\)
\(\Leftrightarrow\left(x+2015\right)\left(\frac{1}{2014}+\frac{1}{2013}+\frac{1}{2012}\right)=0\)
Do \(\frac{1}{2014}+\frac{1}{2013}+\frac{1}{2012}>0\Rightarrow x+2015=0\)
\(\Leftrightarrow x=-2015\)
Vậy \(x=-2015\)
![](https://rs.olm.vn/images/avt/0.png?1311)
a) – 1 < x < 49 18 => x ∈ {0;1;2}
b) − 1 24 < x 24 < 1 14 => x = 0
c) 2 3 ≤ x ≤ 26 5 => x ∈ {1;2;3;4;5}
d) 0 < x ≤ 1 => x = 1
1 + 2 + 3 + ... + x = 276
\(\frac{x\cdot\left(x+1\right)}{2}=276\)
\(x\cdot\left(x+1\right)=276\cdot2\)
\(x\cdot\left(x+1\right)=552\)
\(x\cdot\left(x+1\right)=23\cdot24\)
\(x=23\)
Vậy \(x=23\)
1+2+3+...+x=276
=>\(\frac{x.\left(x+1\right)}{2}=276\)
=>\(x.\left(x+1\right)=276.2=552\)
=> \(x.\left(x+1\right)=23.24\)
=> x = 23