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b: =>15-x=-10
hay x=25
a: =>-2x+17=9
=>-2x=-8
hay x=4
d: \(\Leftrightarrow9x^2=81\)
hay \(x\in\left\{3;-3\right\}\)
e: \(\Leftrightarrow\left[{}\begin{matrix}2x-4=0\\3-x=0\end{matrix}\right.\Leftrightarrow x\in\left\{2;3\right\}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
a: =>-2x+17=9
=>-2x=-8
hay x=4
b: =>15-x=-10
hay x=25
c: =>7x=-4
hay x=-4/7
d: =>\(9x^2=81\)
hay \(x\in\left\{3;-3\right\}\)
g: \(\Leftrightarrow2x-4+5⋮x-2\)
\(\Leftrightarrow x-2\in\left\{1;-1;5;-5\right\}\)
hay \(x\in\left\{3;1;7;-3\right\}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
a: =>-2x=9-17=-8
hay x=4
b: =>15-x=-10
hay x=25
d: \(\Leftrightarrow9x^2=81\)
hay \(x\in\left\{3;-3\right\}\)
e: \(\Leftrightarrow\left[{}\begin{matrix}2x-4=0\\3-x=0\end{matrix}\right.\Leftrightarrow x\in\left\{2;3\right\}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
a)\(29.\left(-13\right)-27.\left(-29\right)-14.\left(-29\right)\)
\(=13\left(-29\right)-27.\left(-29\right)-14.\left(-29\right)\)
\(=-29.\left(13-27-14\right)\)
\(=\left(-28\right).\left(-29\right)\)
\(=812\)
![](https://rs.olm.vn/images/avt/0.png?1311)
Giải:
a) \(2\dfrac{17}{20}-1\dfrac{15}{11}+6\dfrac{9}{20}:3\)
\(=\dfrac{57}{20}-\dfrac{26}{11}+\dfrac{129}{20}:3\)
\(=\dfrac{107}{220}+\dfrac{43}{20}\)
\(=\dfrac{29}{11}\)
b) \(4\dfrac{3}{7}:\left(\dfrac{7}{5}.4\dfrac{3}{7}\right)\)
\(=\dfrac{31}{7}:\left(\dfrac{7}{5}.\dfrac{31}{7}\right)\)
\(=\dfrac{31}{7}:\dfrac{31}{5}\)
\(=\dfrac{5}{7}\)
c) \(\left(3\dfrac{2}{9}.\dfrac{15}{23}.1\dfrac{7}{29}\right):\dfrac{5}{23}\)
\(=\left(\dfrac{29}{9}.\dfrac{15}{23}.\dfrac{36}{29}\right):\dfrac{5}{23}\)
\(=\dfrac{60}{23}:\dfrac{5}{23}\)
\(=12\)
![](https://rs.olm.vn/images/avt/0.png?1311)
29 - [ 3 ( x - 2 ) + 15 ] = 2
[ 3 ( x - 2 ) + 15 ] = 29 - 2
[ 3 ( x - 2 ) + 15 ] = 27
3 ( x - 2 ) = 27 - 15
3 ( x - 2 ) = 12
( x - 2 ) = 12 : 3
( x - 2 ) = 4
x = 4 + 2
x = 6
29 - [ 3 ( x - 2 ) + 15 ] = 2
[ 3 ( x - 2 ) + 15 ] = 29 - 2
[ 3 ( x - 2 ) + 15 ] = 27
3 ( x - 2 ) = 27 - 15
3 ( x - 2 ) = 12
( x - 2 ) = 12 : 3
( x - 2 ) = 4
x = 4 + 2
x = 6
Ủng hộ nhé!
![](https://rs.olm.vn/images/avt/0.png?1311)
\(a.-14-x=-8\)
\(x=-6\)
\(b.11+x+20=32\)
\(31+x=32\)
\(x=1\)
\(c.5-\left(x-8\right)=63\)
\(x-8=-58\)
\(x=-50\)
a,\(\left(-14-x\right)+13=5\)
\(\Rightarrow-x+1=5\)
\(\Rightarrow-x=4\)
\(\Rightarrow x=-4\)
b,\(\left(11+x\right)-\left(-11-9\right)=32\)
\(\Rightarrow11+x+11+9=32\)
\(\Rightarrow x+31=32\)
\(\Rightarrow x=1\)
c,\(5-\left(x-8\right)+\left(-21\right)=42\)
\(\Rightarrow5-x+8-21=42\)
\(\Rightarrow-x-8=42\)
\(\Rightarrow x=-50\)
=>11-15 -11 = x - 20
-15+20 =x
5=x
hay x =5