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65 - 4x + 2 = 20150
65 - 4x + 2 = 1
4x + 2 = 65 - 1 = 64
4x + 2 = 44
=> x + 2 = 4
=> x = 2
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ta có /x/ =\(\int^{x;x>0}_{-x;x<0}\); /y/ =\(\int^{y;y>0}_{-y;y<0}\)
+ Nếu x >0;y>0 => x+y =2015
+Nếu x<0 ;y<0 => -x -y =2015 => x+y = -2015
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=> x+2015=0 hoặc x-2016=0
=>x=0-2015 hoặc x=0+2016
=>x=-2015 hoặc x=2016
Vậy x=-2015 hoặc x=2016
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\(b,\Leftrightarrow\left(x-5\right)\left(x-4\right)\left(x+4\right)=0\\ \Leftrightarrow\left[{}\begin{matrix}x=5\\x=4\\x=-4\end{matrix}\right.\\ c,\Leftrightarrow x-2015>0\Leftrightarrow x>2015\\ d,\Leftrightarrow\left[{}\begin{matrix}\left\{{}\begin{matrix}3-x>0\\x+6>0\end{matrix}\right.\\\left\{{}\begin{matrix}3-x< 0\\x+6< 0\end{matrix}\right.\end{matrix}\right.\Leftrightarrow-6< x< 3\)
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