Câu hỏi của đâu lém phiêu lưu kí

Question

so sanh2^5+2^6+2^7+2^82^9+2^10+2^11+2^12 va 16

l҉o҉n҉g҉ d҉z҉ · Accepted Answer

$\frac{2^5+2^6+2^7+2^8}{2^9+2^{10}+2^{11}+2^{12}}$$=\frac{1\left(2^5+2^6+2^7+2^8\right)}{2^4\left(2^5+2^6+2^7+2^8\right)}$$=\frac{1}{2^4}=\frac{1}{16}$Ta có $\frac{1}{16}< \frac{1}{6}$=> $\frac{2^5+2^6+2^7+2^8}{2^9+2^{10}+2^{11}+2^{12}}< \frac{1}{6}$Câu trả lời: $\frac{2^5+2^6+2^7+2^8}{2^9+2^{10}+2^{11}+2^{12}}$$=\frac{1\left(2^5+2^6+2^7+2^8\right)}{2^4\left(2^5+2^6+2^7+2^8\right)}$$=\frac{1}{2^4}=\frac{1}{16}$Ta có $\frac{1}{16}< \frac{1}{6}$=> $\frac{2^5+2^6+2^7+2^8}{2^9+2^{10}+2^{11}+2^{12}}< \frac{1}{6}$

Ngô Chi Lan · Answer

So sánh $\frac{2^5+2^6+2^7+2^8}{2^9+2^{10}+2^{11}+2^{12}}$ với $\frac{1}{6}$ ?Ta có: $\frac{2^5+2^6+2^7+2^8}{2^9+2^{10}+2^{11}+2^{12}}=\frac{2^5.\left(1+2+2^2+2^3\right)}{2^9.\left(1+2+2^2+2^3\right)}$$=\frac{1}{2^4}=\frac{1}{16}< \frac{1}{6}$Vậy $\frac{2^5+2^6+2^7+2^8}{2^9+2^{10}+2^{11}+2^{12}}< \frac{1}{6}$Câu trả lời: So sánh $\frac{2^5+2^6+2^7+2^8}{2^9+2^{10}+2^{11}+2^{12}}$ với $\frac{1}{6}$ ?Ta có: $\frac{2^5+2^6+2^7+2^8}{2^9+2^{10}+2^{11}+2^{12}}=\frac{2^5.\left(1+2+2^2+2^3\right)}{2^9.\left(1+2+2^2+2^3\right)}$$=\frac{1}{2^4}=\frac{1}{16}< \frac{1}{6}$Vậy $\frac{2^5+2^6+2^7+2^8}{2^9+2^{10}+2^{11}+2^{12}}< \frac{1}{6}$

Giá trị (x)	1	2	4	5	6	7	8	9	10	11	12	13	14	15	16	17	18	19
Tần số (n)	2	1	2	4	6	8	9	10	13	11	8	8	4	6	3	2	3	1	N=100

Chúng tôi đề xuất

Tài nguyên

Ứng dụng mobile

Bảng xếp hạng

Các khóa học có thể bạn quan tâm

Yêu cầu VIP