![](https://rs.olm.vn/images/avt/0.png?1311)
Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
a)34000 và 92000
34000 = 34.1000 =(34)1000 = 811000
92000 = 92.1000 = (92)1000 = 811000
Vì 811000 = 811000 nên 34000 = 92000
Câu b tương tự, do ko có thời gian nên bạn tự làm nhé
K nha
92000=(32)2000=32.2000=3400
Vậy 34000=92000
b) 2323=2300.223
3223=3200.323
Trước hết so sánh 2300 và 3200
2300=(23)100=8100
3200=(32)100=9100
Do đó 3200 lớn hơn 2300
Còn 323 dĩ nhiên lớn hơn 223 vì cơ số lớn hơn
Do đó 3223 lớn hơn 2323
![](https://rs.olm.vn/images/avt/0.png?1311)
\(a,\frac{8}{9}< \frac{108}{109}\)
\(b,\frac{97}{100}< \frac{98}{99}\)
\(c,\frac{19}{18}>\frac{2017}{2016}\)
\(d,\frac{15}{16}>\frac{515}{616}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
e) \(\frac{15}{16}=\frac{15.1010}{16.1010}=\frac{15150}{16160}=1-\frac{1010}{16160}\)
\(\frac{15151}{16161}=1-\frac{1010}{16161}\)
Vì \(16160< 16161\)\(\Rightarrow\frac{1}{16160}>\frac{1}{16161}\)
\(\Rightarrow\frac{1010}{16160}>\frac{1010}{16161}\)\(\Rightarrow1-\frac{1010}{16160}< 1-\frac{1010}{16161}\)
hay \(\frac{15}{16}< \frac{15151}{16161}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
a, 277 + 113 + 323 + 87
= ( 277 + 323 ) + ( 113 + 87 )
= 600 + 200
= 800
b, 185 + 434 + 515 + 266 + 155
= ( 185 + 515 ) + ( 434 + 266 ) + 155
= 700 + 700 + 155
= 1400 + 155
= 1555
c, 8 . 12 . 125 . 2
= ( 125 . 8 ) . ( 12 . 2 )
= 1000 . 24
= 24000
d, 4 . 36 . 25 . 50
= ( 4 . 25 ) . ( 36 . 50 )
= 100 . 1800
= 180000
a, 277 + 113 + 323 + 87
= ( 277 + 323 ) + ( 113 + 87 )
= 600 + 200
= 800
b, 185 + 434 + 515 + 266 + 155
= ( 185 + 515 ) + ( 434 + 266 ) + 155
= 700 + 700 + 155
= 1400 + 155
= 1555
c, 8 . 12 . 125 . 2
= ( 125 . 8 ) . ( 12 . 2 )
= 1000 . 24
= 24000
d, 4 . 36 . 25 . 50
= ( 4 . 25 ) . ( 36 . 50 )
= 100 . 1800
= 180000
![](https://rs.olm.vn/images/avt/0.png?1311)
515+[72+(-515)+(-32)]
=[515+(-515)]+[72+(-32)]
=0+40
=40
![](https://rs.olm.vn/images/avt/0.png?1311)
\(515.\left(2-128.128\right).\left(-515\right)\)
\(=515.\left(2-16384\right).\left(-515\right)\)
\(=515.\left(-16382\right).\left(-515\right)\)
\(=\left(-8436730\right).\left(-515\right)\)
\(=4344915950\)
![](https://rs.olm.vn/images/avt/0.png?1311)
a: 43/52>26/52=1/2=60/120
b: 17/68=1/4<1/3=35/105<35/103
c: \(\dfrac{2018\cdot2019-1}{2018\cdot2019}=1-\dfrac{1}{2018\cdot2019}\)
\(\dfrac{2019\cdot2020-1}{2019\cdot2020}=1-\dfrac{1}{2019\cdot2020}\)
2018*2019<2019*2020
=>-1/2018*2019<-1/2019*2020
=>\(\dfrac{2018\cdot2019-1}{2018\cdot2019}< \dfrac{2019\cdot2020-1}{2019\cdot2020}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(\dfrac{19}{19}\) = 1 < \(\dfrac{2005}{2004}\) vậy \(\dfrac{19}{19}\) < \(\dfrac{2005}{2004}\)
\(\dfrac{72}{73}\) = 1 - \(\dfrac{1}{73}\)
\(\dfrac{98}{99}\) = 1 - \(\dfrac{1}{99}\)
Vì \(\dfrac{1}{73}\) > \(\dfrac{1}{99}\) nên \(\dfrac{72}{73}\) < \(\dfrac{98}{99}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
a) ta có: \(1-\frac{2012}{2013}=\frac{1}{2013}\)
\(1-\frac{2013}{2014}=\frac{1}{2014}\)
mà \(\frac{1}{2013}>\frac{1}{2014}\) nên \(\frac{2013}{2014}>\frac{2012}{2013}\)