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10 tháng 9 2020

\(=\frac{2^{15}\cdot\left(3^2\right)^4}{2^7\cdot3^7\cdot\left(2^3\right)^3}\) 

\(=\frac{2^{15}\cdot3^8}{2^7\cdot3^7\cdot2^9}\) 

\(=\frac{2^{15}\cdot3^8}{2^{16}\cdot3^7}\) 

\(=\frac{3}{2}\)

Bài làm :

\(\frac{2^{15}.9^4}{6^7.8^3}\)

\(=\frac{2^{15}.\left(3^2\right)^4}{\left(2.3\right)^7.(2^3)^3}\)

\(=\frac{2^{15}.3^8}{2^7.3^7.2^9}\)

\(=\frac{3}{2}\)

Học tốt nhé

9 tháng 9 2020

            Bài làm :

Ta có :

\(\frac{2^{15}.9^4}{6^7.8^3}=\frac{2^{15}.\left(3^2\right)^4}{\left(2.3\right)^7.\left(2^3\right)^3}=\frac{2^{15}.3^8}{2^7.3^72^9}=\frac{3}{2}\)

Bài làm :

\(\frac{2^{15}.9^4}{6^7.8^3}\)

\(=\frac{2^{15}.\left(3^2\right)^4}{\left(2.3\right)^7.\left(2^3\right)^3}\)

\(=\frac{2^{15}.3^8}{2^7.3^7.2^9}\)

\(=\frac{3}{2}\)

Học tốt nhé

25 tháng 2 2018

\(\frac{2^{19}.27^3+15.4^9.9^4}{6^9.2^{10}+12^{10}}\)

\(=\frac{2^{19}.\left(3^3\right)^3+15.\left(2^2\right)^9.\left(3^2\right)^4}{\left(2.3\right)^9.2^{10}+\left(2^2.3\right)^{10}}\)

\(=\frac{2^{19}.3^9+15.2^{18}.3^8}{2^9.3^9.2^{10}+2^{20}.3^{10}}\)

\(=\frac{2^{19}.3^9+15.2^{18}.3^8}{2^{19}.3^9+2^{20}.3^{10}}\)

\(=\frac{2^{18}.3^8\left(2.3+15\right)}{2^{19}.3^9\left(1+2.3\right)}\)

\(=\frac{6+15}{2.3\left(1+6\right)}\)

\(=\frac{21}{6.7}\)

\(=\frac{21}{42}\)

\(=\frac{1}{2}\)

16 tháng 8 2017

có bạn nào ko giúp mình với 

26 tháng 6 2016

\(=\frac{2^{19}3^9+3\cdot5\cdot2^{18}\cdot3^8}{2^9\cdot3^9\cdot2^{10}+4^{10}\cdot3^{10}}=\frac{2^{19}\cdot3^9+5\cdot2^{18}\cdot3^9}{2^{19}\cdot3^9+2^{20}\cdot3^{10}}=\frac{2^{18}\cdot3^9\cdot\left(2+5\right)}{2^{19}\cdot3^9\left(1+6\right)}=\frac{1}{2}\)

16 tháng 2 2021

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9 tháng 10 2016

\(P=\frac{3^{2010}-6^{2010}+9^{2010}-12^{2010}+15^{2010}-18^{2010}}{-1+2^{2010}-3^{2010}+4^{2010}-5^{2010}+6^{2010}}\)

\(P=\frac{-3^{2010}.\left(-1+2^{2010}-3^{2010}+4^{2010}-5^{2010}+6^{2010}\right)}{-1+2^{2010}-3^{2010}+4^{2010}-5^{2010}+6^{2010}}\)

\(P=-3^{2010}\)

13 tháng 7 2017

b) \(\frac{36^7}{2^{15}.27^5}=\frac{\left(2^2.3^2\right)^7}{2^{15}.\left(3^3\right)^5}=\frac{2^{14}.3^{14}}{2^{15}.3^{15}}=\frac{1.1}{2.3}=\frac{1}{6}\)

h) \(\frac{2^{18}.9^4}{6^6.8^4}=\frac{2^{18}.\left(3^2\right)^4}{\left(2.3\right)^6.\left(2^3\right)^4}=\frac{2^{18}.3^8}{2^6.3^6.2^{12}}=\frac{2^{18}.3^8}{2^{18}.3^6}=\frac{1.3^2}{1.1}=9\)

o) \(\frac{3^3+3.6^2+6^3}{13}=\frac{3^3+6^2\left(3+6\right)}{13}=\frac{3^3+6^2.3^2}{13}\)

\(=\frac{3^2\left(3+6^2\right)}{13}=\frac{9.3.13}{13}=\frac{9.3.1}{1}=27\)