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\(2Al+3S\underrightarrow{t^0}Al_2S_3\)
\(Fe+S\underrightarrow{t^0}FeS\)
\(Pb+S\underrightarrow{t^0}PbS\)
\(2Na+S\underrightarrow{t^0}Na_2S\)
a) 2 Al + 3 S -to-> Al2S3
b) Fe + S -to-> FeS
c) Pb + S -to-> PbS
d) 2 Na + S -to-> Na2S
\(Mg+S\rightarrow\left(t^o\right)MgS\)
\(Zn+S\rightarrow\left(t^o\right)ZnS\)
\(Fe+S\rightarrow\left(t^o\right)FeS\)
\(2Al+3S\rightarrow\left(t^o\right)Al_2S_3\)
Phương trình hóa học:
Mg + S → MgS
Fe + S → FeS
Zn + S → ZnS
2Al + 3S → Al2S3
\(Mg+S\underrightarrow{t^o}MgS\\ Zn+S\underrightarrow{t^o}ZnS\\ Fe+S\underrightarrow{t^o}FeS\\ 2Al+3S\underrightarrow{t^o}Al_2S_3\)
Câu 1 :
a,
\(K+O_2\underrightarrow{^{to}}K_2O\)
\(2Ca+O_2\underrightarrow{^{to}}2CaO\)
\(3Fe+2O_2\underrightarrow{^{to}}Fe_3O_4\)
\(C+O_2\underrightarrow{^{to}}CO_2\)
\(S+O_2\underrightarrow{^{to}}SO_2\)
b,
\(CH_4+2O_2\underrightarrow{^{to}}CO_2+2H_2O\)
\(C_2H_4+3O_2\underrightarrow{^{to}}2CO_2+2H_2O\)
\(C_2H_2+\frac{5}{2}O_2\underrightarrow{^{to}}2CO_2+H_2O\)
\(2CO+O_2\underrightarrow{^{to}}2CO_2\)
Câu 2 :
\(S+Zn\underrightarrow{^{to}}ZnS\)
\(3S+2Al\underrightarrow{^{to}}Al_2S_3\)
\(S+Mg\underrightarrow{^{to}}MgS\)
\(S+Cu\underrightarrow{^{to}}CuS\)
\(S+Fe\underrightarrow{^{to}}FeS\)
Bài 1 :
\(d_{A/H2}=17\Leftrightarrow M_A=17.2=34\left(\frac{g}{mol}\right)\)
\(d_{A/kk}=0,55\Leftrightarrow M_A=0,55.29=15,95\left(\frac{g}{mol}\right)\)
\(d_{A/H2S}=0,425\Leftrightarrow M_A==0,425.34=14,45\left(\frac{g}{mol}\right)\)
Bài 2:
\(S+Zn\underrightarrow{^{to}}ZnS\)
\(3S+2Al\rightarrow Al_2S_3\)
\(S+Mg\underrightarrow{^{to}}MgS\)
\(S+Cu\underrightarrow{^{to}}CuS\)
\(S+Fe\underrightarrow{^{to}}FeS\)
Phương trình hóa học:
\(Mg+S\rightarrow MgS\)
\(Fe+S\rightarrow FeS\)
\(Zn+S\rightarrow ZnS\)
\(2Al+3S\rightarrow Al_2S_3\)
Bàu 1
a) 4P+5O2--->2P2O5
S+O2--->SO2
3Fe+2O2--->Fe3O4
C2H4+3O2-->2CO2+2H2O
4Na+O2--->2Na2O
trừ phản ứng C2H4 thì tất cả đề là phản ứng hóa hợp
Bài 2
2H2+O2--->2H2O
2Mg+O2--->2MgO
2Cu+O2--->2CuO
S+O2--->SO2
4Al+3O2--->2Al2O3
C+O2---->CO2
4P+5O2--->2P2O5
Bài 1 :
a,
\(4P+5O_2\underrightarrow{^{to}}2P_2O_5\) (1)
\(S+O_2\underrightarrow{^{to}}SO_2\)(2)
\(3Fe+2O_2\underrightarrow{^{to}}Fe_3O_4\)(3)
\(C_2H_4+3O_2\underrightarrow{^{to}}2CO_2\uparrow+2H_2O\)(4)
\(4Na+O_2\underrightarrow{^{to}}2Na_2O\)(5)
\(2Ca+O_2\underrightarrow{^{to}}2CaO\)(6)
b, PHản ứng hóa hợp : (1) ; (2) ; (3) ;(5) ; (6)
Bài 2 :
\(2H_2+O_2\underrightarrow{^{to}}2H_2O\)
\(2Mg+O_2\underrightarrow{^{to}}2MgO\)
\(2Cu+O_2\underrightarrow{^{to}}2CuO\)
\(S+O_2\underrightarrow{^{to}}SO_2\)
\(4Al+3O_2\underrightarrow{^{to}}2Al_3O_3\)
\(C+O_2\underrightarrow{^{to}}CO_2\)
\(4P+5O_2\underrightarrow{^{to}}2P_2O_5\)
a)
4Na + O2 -to--> 2Na2O (1)
3Fe + 2O2 --to--> Fe3O4 (2)
S + O2 --to--> SO2 (3)
CH4 +2O2 --to--> CO2 + 2H2O (4)
b) Pư hóa hợp: (1), (2), (3)
a/ 2Al + 3S -to-> Al2S3
b/ Fe + S -to-> FeS
c/ Pb + S -to-> PbS
d/ 2Na + S -to-> Na2S
a/ 2Al + 3S -to-> Al2S3
b/ Fe + S -to-> FeS
c/ Pb + S -to-> PbS
d/ 2Na + S -to-> Na2S