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(14678:2+2476)*(2576-2575)
=9815*1
=9815
(195-13*15):(1954+1014)
=(195-195):2959
=0:2959
=0
\(\frac{x-28-124}{2011}+\frac{x-124-2011}{28}+\frac{x-2011-28}{124}\)\(=3\)
\(\Leftrightarrow\frac{x-152}{2011}+\frac{x-2135}{28}+\frac{x-2039}{124}=3\)\(\Leftrightarrow\left(\frac{x-152}{2011}-1\right)+\left(\frac{x-2135}{28}-1\right)+\left(\frac{x-2039}{124}-1\right)=3-1-1-1\)
\(\Leftrightarrow\frac{x-2163}{2011}+\frac{x-2163}{28}+\frac{x-2163}{124}=0\)
\(\Leftrightarrow\left(x-2163\right)\left(\frac{1}{2011}+\frac{1}{28}+\frac{1}{124}\right)=0\)
Vì \(\left(\frac{1}{2011}+\frac{1}{28}+\frac{1}{124}\right)>0\)
\(\Rightarrow x-2163=0\)
\(\Leftrightarrow x=2163\)
Vậy \(x=2163\)
x : (123 - 124) = -13
123 - 124 = x : ( -13)
-1 = x : (-13)
x = ( -13) . ( -1)
x = 13
\(x\div\left(123-124\right)=-13\)
\(x\div\left(-1\right)=-13\)
\(x=-13\cdot\left(-1\right)\)
\(x=13\)
Vậy x = 13
Ta có: 5=2+3; 9=4+5;...; x=y+(y+1)
Do đó: 1+5+9+13+...+x = 1+2+3+4+5+6+7+...+y+(y+1) = 4950
Hay (ý+2)(ý+1) : 2 = 4950
=> (y+2)(y+1) = 9900
=> (y+2)(y+1) = 100.99
=> y+1 = 99
=> y = 98
=> x = y+(y+1) = 98 + 99 = 197
x^2+12x-13=0
= x2 + 13x - x - 13 = 0
= x ( x + 13 ) - ( x + 13 ) = 0
= ( x - 1 ) ( x + 13 )
= 0
= x = 1
= x = -13
Hok tốt
x2+12x=13
xx+12x=13
x.(12+x)=13
x=0
hoặc x+12=0=> x= -12
Vậy, x = 0 hoặc x =-12
Thêm mỗi vế 13 đơn vị, ta có:
2x-13+13=5-x+13
2x=18-x
3x=18
x=18:3
x=6
Học tốt nha em.
\(2x-13=5-x\)
\(\Rightarrow2x+x=5+13\)
\(\Rightarrow3x=18\)
\(\Rightarrow x=6\)
1014 : ( 124 - x ) = 13
124 - x = 1014 : 13
124 - x = 78
x = 124 - 78
x = 46
1014:(124-x)=13
124-x=1014:13=78
x=124-78
x=46