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\(\frac{\left(3.4.2^{16}\right)^2}{11.2^{13}.4^{11}-16^9}\)
\(=\frac{3^2.4^2.2^{32}}{11.2^{13}.2^{22}-2^{36}}\)
\(=\frac{3^2.2^4.2^{32}}{11.2^{35}-2^{35}.2}\)
\(=\frac{3^2.2^{36}}{2^{35}.\left(11-2\right)}\)
\(=\frac{9.2^{35}.2}{2^{35}.9}\)
\(=2\)
\(\frac{\left(3.4.2^{16}\right)^2}{11.2^{13}.4^{11}-16^9}\)
= \(\frac{3^2.4^2.2^{32}}{11.2^{13}.2^{22}-2^{36}}\)
= \(\frac{3^2.4^2.2^{32}}{11.2^{35}-2^{35}.2}\)
= \(\frac{3^2.2^4.2^{32}}{2^{35}.\left(11-2\right)}\)
= \(\frac{3^2.2^{36}}{2^{35}.9}\)
= \(\frac{9.2^{35}.2}{2^{35}.9}\)
= \(2\)
\(B=\dfrac{3^2.4^2.2^{18}}{11.2^{13}.2^{22}-2^{36}}\)
\(B=\dfrac{3^2.2^{22}}{2^{35}\left(11-2\right)}\)
\(B=\dfrac{3^2}{2^{13}.9}\)
\(B=\dfrac{1}{2^{13}}=\dfrac{1}{8129}\)
= 3^2 . 2^4 . 2^32 / 11.2^13 .2^22 - 2^36
=3^2 . 2^36 / 11.2^35 - 2^36
=3^2 . 2^36 / 2^35 . ( 11+2)
= 9 . 2^36 / 2^35 . 13
= 9 . 2 / 13 = 18/13
\(\frac{\left(3.4.2^{16}\right)^2}{11.2^{13}.4^{11}-16^9}=\frac{3^2.2^4.2^{32}}{11.2^{13}.2^{22}-2^{36}}=\frac{3^2.2^{36}}{11.2^{35}-2^{36}}=\frac{2^{35}\left(9+2\right)}{2^{35}\left(11-2\right)}=\frac{11}{9}\)
a) =\(\left[\left(12+1\right)^2+\left(12+2\right)^2\right]:\left(13^2+14^2\right)\)
=1
b)=(1.2.3....8).(9-1-8)
=(1.2.3....8).0
=0
mik chỉ giải được zậy thôi.
t mik nha.
