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1.
7x(2x-1)=14x2-7x
2
a. x2+2x=x(x+2)
b.x2-xy+3x-3y
=x(x-y)+3(x-y)
=(x+3)(x-y)
Câu 2:
1. 2x/2x-5 - 5/2x-5
=2x-5/2x-5
=1
2. (6x3-7x2-x+2) : (x-1)=6x2-x-2
![](https://rs.olm.vn/images/avt/0.png?1311)
(x2– y2 + 6x + 9) : (x + y + 3) = (x2 + 6x+ 9) – y2 : (x + y + 3)
=(x + 3)2 – y2 : (x + y + 3) = (x + 3 – y) (x + 3 + y) : (x + y + 3) = (x – y + 3)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(\left(6x^3-7x^2-x+2\right):\left(2x+1\right)\)
\(=\left(x+\frac{1}{2}\right)\left(x-1\right)\left(x-\frac{2}{3}\right):\left(x+\frac{1}{2}\right)\)
\(=\left(x-1\right)\left(x-\frac{2}{3}\right)\)
a) Ta có: 6x^3 - 7x2 - x+2 = 6x3+3x2-10x2-5x+4x+2
= 3x2 ( 2x+1) - 5x(2x+1) + 2(2x+1)
= (2x+1)(3x2-5x+2)
Suy ra: (6x3-7x2-x+2): (2x+1)= 3x2-5x+2
b) Ta có: x2 -y2+6x+9= (x2+6x+9) - y2
= (x+3)2 - y2
= (x+3-y)(x+3+y)
Suy ra: (x2-y2+6x+9): (x+y+3)= x-y+3
Làm vậy nha pạn :)
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câu 1:
x3-1+3x2-3x =(x-1)(x^2+x+1)+3x(x-1)=(x-1)(x^2+x+1+3x)=(x-1)(x^2+4x=1)
Câu 2 :
a) \(\left(x^4-2x^3+2x-1\right):\left(x^2-1\right)\)
\(=\left(x^4-x^2-2x^3+2x+x^2-1\right):\left(x^2-1\right)\)
\(=\left[x^2\left(x^2-1\right)-2x\left(x^2-1\right)+\left(x^2-1\right)\right]:\left(x^2-1\right)\)
\(=\left(x^2-1\right)\left(x^2-2x+1\right):\left(x^2-1\right)\)
\(=x^2-2x+1\)
b) \(\left(x^6-2x^5+2x^4+6x^3-4x^2\right):6x^2\)
\(=\frac{1}{6}x^4-\frac{1}{3}x^3+\frac{1}{3}x^2+x-\frac{2}{3}\)
Câu 3 :
Sửa đề :
\(\frac{3x^2+6x+12}{x^3-8}=\frac{3\left(x^2+2x+4\right)}{\left(x-2\right)\left(x^2+2x+4\right)}=\frac{3}{x-2}\)
6x3 - 7x2 - x + 2 |_2x + 1_
- 6x3 + 3x2 | 3x2 - 5x + 2
--------------------------
-10x2 - x + 2
- -10x2 - 5x
--------------------------
4x + 2
- 4x + 2
--------------------------
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