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![](https://rs.olm.vn/images/avt/0.png?1311)
a) \(\dfrac{2}{5}\cdot x=\dfrac{1}{2}+\dfrac{6}{8}\)
\(\dfrac{2}{5}\cdot x=\dfrac{5}{4}\)
\(x=\dfrac{5}{4}\div\dfrac{2}{5}\)
\(x=\dfrac{25}{8}\)
b) \(\dfrac{20}{7}-x=\dfrac{19}{7}\div\dfrac{3}{2}\)
\(\dfrac{20}{7}-x=\dfrac{19}{7}\cdot\dfrac{2}{3}\)
\(\dfrac{20}{7}-x=\dfrac{38}{21}\)
\(x=\dfrac{20}{7}-\dfrac{28}{21}\)
\(x=\dfrac{22}{21}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(\left(x+2\right)-2=0\)
\(\Rightarrow x+2-2=0\)
\(\Rightarrow x=0\)
\(\left(x+3\right)+1=7\)
\(\Rightarrow x+3+1=7\)
\(\Rightarrow x+4=7\)
\(\Rightarrow x=3\)
\(\left(3x-4\right)+4=12\)
\(\Rightarrow3x-4+4=12\)
\(\Rightarrow3x=12\)
\(\Rightarrow x=4\)
\(\left(5x+4\right)-1=13\)
\(\Rightarrow5x+4-1=13\)
\(\Rightarrow5x+3=13\)
\(\Rightarrow5x=10\)
\(\Rightarrow x=2\)
\(\left(4x-8\right)-3=5\)
\(\Rightarrow4x-8-3=5\)
\(\Rightarrow4x-11=5\)
\(\Rightarrow4x=16\)
\(\Rightarrow x=4\)
\(8-\left(2x+4\right)=2\)
\(\Rightarrow8-2x-4=2\)
\(\Rightarrow4-2x=2\)
\(\Rightarrow2x=2\)
\(\Rightarrow x=1\)
\(7+\left(5x+2\right)=14\)
\(\Rightarrow7+5x+2=14\)
\(\Rightarrow9+5x=14\)
\(\Rightarrow5x=5\)
\(\Rightarrow x=1\)
\(5-\left(3x-11\right)=1\)
\(\Rightarrow5-3x+11=1\)
\(\Rightarrow16-3x=1\)
\(\Rightarrow3x=15\)
\(\Rightarrow x=5\)
![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
1) -x - 3 = 7
-x = 7 + 3
-x = 10
x = -10
2) x + 5 = -10
x = -10 - 5
x = -15
3) 2x - 7 = 713
2x = 713 + 7
2x = 720
x = 720 : 2
x = 360
4) -129 - (35 - x) = 55
35 - x = -129 - 55
35 - x = -184
x = 35 - (-184)
x = 219
5) 103 - x = 16 - (13 - 8)
103 - x = 16 - 5
103 - x = 11
x = 103 - 11
x = 192
![](https://rs.olm.vn/images/avt/0.png?1311)
a) \(\dfrac{13}{20}+\dfrac{3}{5}+x=\dfrac{5}{6}\)
\(\Rightarrow\dfrac{5}{4}+x=\dfrac{5}{6}\)
\(\Rightarrow x=\dfrac{5}{6}-\dfrac{5}{4}\)
\(\Rightarrow x=\dfrac{-5}{12}\)
b) \(x+\dfrac{1}{3}=\dfrac{2}{5}-\dfrac{-1}{3}\)
\(\Rightarrow x+\dfrac{1}{3}=\dfrac{11}{15}\)
\(\Rightarrow x=\dfrac{11}{15}-\dfrac{1}{3}\)
\(\Rightarrow x=\dfrac{2}{5}\)
c)\(\dfrac{-5}{8}-x=\dfrac{-3}{20}-\dfrac{-1}{6}\)
\(\dfrac{-5}{8}-x=\dfrac{1}{60}\)
\(\Rightarrow x=\dfrac{-5}{8}-\dfrac{1}{60}\)
\(\Rightarrow x=\dfrac{-77}{120}\)
d) \(\dfrac{3}{5}-x=\dfrac{1}{4}+\dfrac{7}{10}\)
\(\Rightarrow\dfrac{3}{5}-x=\dfrac{19}{20}\)
\(\Rightarrow x=\dfrac{3}{5}-\dfrac{19}{20}\)
\(\Rightarrow x=\dfrac{-7}{20}\)
e) \(\dfrac{-3}{7}-x=\dfrac{4}{5}+\dfrac{-2}{3}\)
\(\Rightarrow\dfrac{-3}{7}-x=\dfrac{2}{15}\)
\(\Rightarrow x=\dfrac{-3}{7}-\dfrac{2}{15}\)
\(\Rightarrow x=\dfrac{-59}{105}\)
g) \(\dfrac{-5}{6}-x=\dfrac{7}{12}+\dfrac{-1}{3}\)
\(\Rightarrow\dfrac{-5}{6}-x=\dfrac{1}{4}\)
\(\Rightarrow x=\dfrac{-5}{6}-\dfrac{1}{4}\)
\(\Rightarrow x=\dfrac{-13}{12}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
a: =>x=-7/6+5/8=-13/24
b: =>x=-14/25-3/4=-131/100
c: \(x=\dfrac{-33}{26}:\dfrac{-9}{13}=\dfrac{33}{26}\cdot\dfrac{13}{9}=\dfrac{11}{3}\cdot\dfrac{1}{2}=\dfrac{11}{6}\)
d: \(x=\dfrac{4}{9}:\dfrac{5}{3}=\dfrac{4}{9}\cdot\dfrac{3}{5}=\dfrac{12}{45}=\dfrac{4}{15}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
a ) 5x=2y
b) 7x = 3y
c ) 3+x /7+y= 3/7
=> (3+x).7= (7+y).3
21 + 7x = 21 + 3y
=> 7x = 3y
=> x/y = 3/7 => x= 20:(7+3).3=6
=> y = 20 - 6 = 14
Vậy (x;y) thuộc {(6;14)}
![](https://rs.olm.vn/images/avt/0.png?1311)
a)\(\left(x+8\right)-11=20-15\)
\(\left(x+8\right)-11=5\)
\( x+8=5+11\)
\(x+8=16\)
\(x=8\)
b) \(2x-\left(3+x\right)=5-7\)
\(2x-\left(3+x\right)=-2\)
\(2x-3-x=-2\)
\(x=1\)
c) \( \left(3x-2^4\right)\times7^5=2\times7^6\)
\(3x-2^4=2\times\left(7^6:7^5\right) \)
\(\left(3x-2^4\right)=2\times7^2\)
\(3x-2^4=2\times49\)
\(3x-16=98\)
\(3x=114\)
\(x=38\)
dấu / / là giá trị tuyệt đối
a) / x + 3 / = 15
=> x + 3 = 15 hay x + 3 = -15
TH1 : x + 3 = 15
x =15 - 3
x = 12
TH2 : x + 3 = -5
x = -5 - 3
x = -8
VẬy : x thuộc { 12;-8 }
b ) /x-7/ + 13 = 25
/ x - 7 / = 25 - 13
/ x - 7 / = 12
=> x - 7 = 12 hay x - 7 = -12
TH1 : x - 7 = 12
x = 12 + 7
x =19
TH2: x - 7 = -12
x = -12 + 7
x = -5
Vậy : x thuộc { 19; -5 }
c) 3 ( x + 3 )2 = 27
( x + 3 )2 = 27 : 3
( x + 3 ) 2 = 9
x + 3 = 3 hay x + 3 = -3 ( lũy thừa bậc chẵn )
Th1 : x + 3 = 3
x = 3 -3
x = 0
TH2 : x + 3 = -3
x = -3-3
x = -6
Vậy : x thuộc { 0 ; -6 }
d) 20 - 2 ( 1-x )3 = 4
2 ( 1 - x )3 = 20 - 4
2 ( 1 - x )3 = 16
( 1 - x )3 = 16 : 2
( 1 -x )3 = 8
( 1 - x )3 = 23
=> 1 - x = 2
x = 1 - 2
x = -1
VẬy : x = -1