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1,
2Cu + O2 → 2CuO
CuO + H2SO4 → CuSO4 + H2O
CuSO4 + BaCl2 → CuCl2 + BaSO4
CuCl2 + 2AgNO3 → 2AgCl + Cu(NO3)2
Cu(NO3)2 + 2NaOH → Cu(OH)2 + 2NaNO3
Cu(OH)2 → CuO + H2O
2,
C + O2 → CO2
CO2 + C → 2CO
2CO + O2 → 2CO2
CO2 + NaOH → NaHCO3
2NaHCO3 → Na2CO3 + CO2 + H2O2
Na2CO3 + CaCl2 → 2NaCl + CaCO3
CaCO3 → CaO + CO2
3,
Cl2 + 2H2 → 2HCl
2HCl → 2H2 + Cl2
Cl2 + 2Na → 2NaCl
2NaCl → 2Na + Cl2
Cl2 + 2NaOH → NaClO + NaCl + H2O
NaClO + 2HCl → NaCl + Cl2 + H2O
4,
2H2O → 2H2 + O2
2H2 + O2 → 2H2O
2H2O + Cl2 → 2HClO + 2HCl
2HClO + 2HCl → Cl2 + 2H2O
Cl2 + 2KOH → KCl + KClO
KClO + 2HCl→ 2KCl + H2O
1,
\(4HCl+MnO_2\rightarrow MnCl_2+2H_2O+Cl_2\\ 2Fe+3Cl_2\underrightarrow{t^o}2FeCl_3\\ FeCl_3+3NaOH\rightarrow Fe\left(OH\right)_3\downarrow+3NaCl\\ 2NaCl+H_2SO_4\rightarrow Na_2SO_4+2HCl\uparrow\\ CuO+2HCl\rightarrow CuCl_2+H_2O\\ CuCl_2+2AgNO_3\rightarrow2AgCl\downarrow+Cu\left(NO_3\right)_2\)
2,
\(2KMnO_4+16HCl\rightarrow2KCl+8H_2O+5Cl_2+2MnCl_2\\ Cl_2+H_2\underrightarrow{as}2HCl\\ 6HCl+Fe_2O_3\rightarrow2FeCl_3+3H_2O\\ FeCl_3+3AgNO_3\rightarrow3AgCl\downarrow+Fe\left(NO_3\right)_3\\ 2AgCl\underrightarrow{as}2Ag+Cl_2\\ Cl_2+2NaBr\rightarrow2NaCl+Br_2\\ Br_2+2NaI\rightarrow2NaBr+I_2\)
3,
2 pthh đầu giống ở 2
\(Fe+2HCl\rightarrow FeCl_2+H_2\\ FeCl_2+2AgNO_3\rightarrow2AgCl\downarrow+Fe\left(NO_3\right)_2\\ 2AgCl\underrightarrow{as}2Ag+Cl_2\)
4, 2 pthh đầu gióng ở 1
\(FeCl_3+3NaOH\rightarrow Fe\left(OH\right)_3\downarrow+3NaCl\\ 2Fe\left(OH\right)_3+3H_2SO_4\rightarrow Fe_2\left(SO_4\right)_3+6H_2O\)
a) HCl(đ) + MnO2 -t0-> Cl2 + MnCl2 + H2O
b) CuO + 2HCl - > CuCl2 + H2O
c) 2HCl + Na2Co3 -> CO2 + 2NaCl + H2O
d) HCl + AgNO3 - > AgCl + HNO3
e) 2KCl + 2H2O \(\xrightarrow[cmn]{đpdd}\) 2KOH + Cl2 + H2
f) Cl2 + H2O - > HCl + HClO
Cl2 + NaOH - > NaCl + NaClo
g Cl2 + Ca(OH)2 -t0->CaoCl2 + H2O
h) 2CaOCl2+ H2O + CO2 - > CaCO3 + CaCl2 +2HClO
NaClo + CO2 + H2O - > NaHCO3 + HClO
Câu 1:
\(C+O_2\xrightarrow{t^o}CO_2\\ CO_2+H_2O\buildrel{{}}\over\rightleftharpoons H_2CO_3\\ H_2CO_3+2NaOH\to Na_2CO_3+2H_2O\\ Na_2CO_3+H_2SO_4\to Na_2SO_4+H_2O+CO_2\uparrow\\ Na_2SO_4+BaCl_2\to 2NaCl+BaSO_4\downarrow\)
a: 4Al+3O2->2Al2O3
b: Mg+CuSO4->MgSO4+Cu
c: Cu(OH)2+2HCl->CuCl2+2H2O
d: 2Fe(OH)3->Fe2O3+3H2O
MnO2 + 4HCL ==to=> MnCl2 + Cl2 + 2H2O
H2 + CL2 ==to==> 2HCl\(\uparrow\)
HCL\(\uparrow\) + H2O ===> HCL loãng
8HCL + Fe3O4 ====> FeCl2 + 2FeCl3 + 4H2O
Fe2O3 + H2O
? ........... + ? ...........
(1) 2Na + Cl2 → 2NaCl
(2) Cl2 + H2 → 2HCl
(3) 3HCl + Fe(OH)3 → FeCl3 + 3H2O
(4) FeCl3 + Cu → CuCl2 + FeCl2
\(\left(1\right)Cl_2+2NaOH\rightarrow NaCl+NaClO+H_2O\)
\(\left(2\right)NaClO+2HCl\rightarrow NaCl+H_2O+Cl_2\)
\(\left(3\right)NaClO+CO_2+H_2O\rightarrow NaHCO_3+HClO\)
\(\left(4\right)HClO\underrightarrow{\text{as}}HCl+\frac{1}{2}O_2\)
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