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a: =(5/7+2/7)+(4/3+5/3)=3+1=4
b: =(17/12+7/12)+(29/7-8/7)
=2+3=5
c: =(2/5+3/5)+(6/9+1/3)+(7/4+1/4)
=1+2+1
=4
d: =(1/3+2/3)+(13/17+4/17)+(29/11+4/11)
=1+1+3=5
Làm 1 câu
10/3...>...1/3
Mấy câu ssu tự quy đồng hay gì gì đấy!
\(a,\frac{2}{5}+\frac{3}{4}=\frac{8}{20}+\frac{15}{20}=\frac{23}{20}\)
\(\frac{5}{8}+\frac{7}{2}=\frac{5}{8}+\frac{28}{8}=\frac{33}{8}\)
\(\frac{4}{9}+\frac{5}{18}=\frac{8}{18}+\frac{5}{18}=\frac{13}{18}\)
\(\frac{5}{8}+\frac{9}{16}=\frac{10}{16}+\frac{9}{16}=\frac{19}{16}\)
\(b,\frac{9}{5}-\frac{5}{9}=\frac{81}{45}-\frac{25}{45}=\frac{56}{45}\)
\(\frac{12}{7}-\frac{17}{2}=\frac{24}{14}-\frac{119}{14}=-\frac{95}{14}\)
\(\frac{11}{8}-\frac{8}{11}=\frac{121}{88}-\frac{64}{88}=\frac{57}{88}\)
\(\frac{17}{6}-\frac{6}{17}=\frac{289}{102}-\frac{36}{102}=\frac{253}{102}\)
\(\dfrac{1}{2}-\dfrac{3}{8}=\dfrac{4}{2\times4}-\dfrac{3}{8}=\dfrac{4}{8}-\dfrac{3}{8}=\dfrac{1}{8}\)
\(\dfrac{4}{3}-\dfrac{8}{15}=\dfrac{4\times5}{3\times5}-\dfrac{8}{15}=\dfrac{20}{15}-\dfrac{8}{15}=\dfrac{12}{15}=\dfrac{4}{5}\)
\(\dfrac{5}{6}-\dfrac{7}{12}=\dfrac{5\times2}{6\times2}-\dfrac{7}{12}=\dfrac{10}{12}-\dfrac{7}{12}=\dfrac{3}{12}=\dfrac{1}{4}\)
\(\dfrac{11}{4}-\dfrac{9}{8}=\dfrac{11\times2}{4\times2}-\dfrac{9}{8}=\dfrac{22}{8}-\dfrac{9}{8}=\dfrac{13}{8}\)
\(\dfrac{17}{16}-\dfrac{3}{4}=\dfrac{17}{16}-\dfrac{3\times4}{4\times4}=\dfrac{17}{16}-\dfrac{12}{16}=\dfrac{5}{16}\)
\(\dfrac{31}{36}-\dfrac{5}{6}=\dfrac{31}{36}-\dfrac{5\times6}{6\times6}=\dfrac{31}{36}-\dfrac{30}{36}=\dfrac{1}{36}\)
ta thay day so tren la day so tu nhien lien tiep bat dau tu 1 va ket thuc la 100 nen co 100 so hang
tong la (100+1) x 100 :2=5050
Công thức tính tổng: ( số đầu + số cuối) x ( số cuối - số đầu + 1) : 2
Bạn tự thay các số vào mà tính.
1 + 2 - 3 - 4 + 5 + 6 - 7 - 8 + 9 + ... + 301 + 302 (có 302 số; 302 chia 4 dư 2)
= 1 + (2 - 3 - 4 + 5) + (6 - 7 - 8 + 9) + ... + (288 - 299 - 300 + 301) + 302
= 1 + 0 + 0 + ... + 0 + 302
= 1 + 302
= 303
1 + 2 - 3 - 4 + 5 + 6 - 7 - 8 + 9 + ....... +301 + 302 ( có 302 số : 302 chia 4 dư 2 )
= 1 + ( 2 - 3 - 4 + 5 ) + ( 6 - 7 - 8 + 9 ) + ..... + ( 288 - 299 -300 + 301 ) + 302
= 1 + 0 + 0 + ......... + 0 + 302
= 1 + 302
= 303
a: \(\dfrac{5}{3}\cdot\dfrac{7}{10}=\dfrac{5}{10}\cdot\dfrac{7}{3}=\dfrac{14}{3}>2\)
\(\dfrac{5}{7}:\dfrac{7}{10}=\dfrac{5}{7}\cdot\dfrac{10}{7}=\dfrac{50}{49}< 2\)
=>\(\dfrac{5}{3}\cdot\dfrac{7}{10}>\dfrac{5}{7}:\dfrac{7}{10}\)
b: \(\dfrac{4}{5}\cdot\dfrac{5}{6}=\dfrac{4}{6}=\dfrac{2}{3}\)
\(\dfrac{8}{9}:\dfrac{4}{3}=\dfrac{8}{9}\cdot\dfrac{3}{4}=\dfrac{8}{4}\cdot\dfrac{3}{9}=\dfrac{2}{3}\)
Do đó: \(\dfrac{4}{5}\cdot\dfrac{5}{6}=\dfrac{8}{9}:\dfrac{4}{3}\)
c: \(\dfrac{5}{11}\cdot\dfrac{33}{15}=\dfrac{5}{15}\cdot\dfrac{33}{11}=\dfrac{3}{3}=1\)
\(\dfrac{6}{17}\cdot\dfrac{34}{25}=\dfrac{34}{17}\cdot\dfrac{6}{25}=2\cdot\dfrac{6}{25}=\dfrac{12}{25}< 1\)
=>\(\dfrac{5}{11}\cdot\dfrac{33}{15}>\dfrac{6}{17}\cdot\dfrac{34}{25}\)
d: \(\dfrac{15}{19}\cdot\dfrac{38}{5}=\dfrac{15}{5}\cdot\dfrac{38}{19}=3\cdot2=6\)
\(\dfrac{15}{16}:\dfrac{3}{8}=\dfrac{15}{16}\cdot\dfrac{8}{3}=\dfrac{15}{3}\cdot\dfrac{8}{16}=\dfrac{5}{2}\)<6
=>\(\dfrac{15}{19}\cdot\dfrac{38}{5}>\dfrac{15}{16}:\dfrac{3}{8}\)
