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a) 2 x 3 x 4 x 8 x 50 x 25 x 125
= (2 x 50) x ( 4 x 25 ) x (8 x 125) x 3 = 100 x 100 x 1000 x 3
= 30 000 000
không lo cho thần tượng bị bệnh hay sao mà lại học toán thế?
a)1999*2000-1:1998+1999*2000=[(1999*2000)-(1999*2000)] va 1:1998
=0 + 1998
=1998
a ) 11 x 62 - 12 x 11 + 50 x 11
= 11 x ( 62 - 12 + 50 )
= 11 x 100
= 1100
b ) 1996 + 3992 + 5988 + 7984
= ( 1996 + 7984 ) + ( 3992 + 5988 )
= 9980 + 9980
= 9980 x 2
= 19 960
a, 11 x 62 - 12 x 11 + 50 x 11
= 11 x ( 62 - 11 + 50 )
= 11 x 101
= 1111
b, 1996 + 3992 + 5988 + 7984
=( 1996 + 7984 ) + ( 3992 + 5988 )
= 9980 + 9980
= 19960
\(\frac{x}{3\frac{1}{2}.2\frac{2}{3}}=\frac{9}{56}\Rightarrow\frac{x}{\frac{7}{2}.\frac{8}{3}}=\frac{9}{56}\Rightarrow x=\frac{9}{56}.\frac{28}{3}=\frac{3}{2}\)
\(x:\left(3\frac{1}{2}.2\frac{2}{3}\right)=\frac{9}{56}\)
\(x:\left(\frac{7}{2}.\frac{8}{3}\right)=\frac{9}{56}\)
\(x:\left(\frac{7.4}{3}\right)=\frac{9}{56}\)
\(x.\frac{3}{28}=\frac{9}{56}\)
\(x=\frac{9}{56}.\frac{28}{3}=\frac{3}{2}\)
Vậy \(x=\frac{3}{2}\)
a, 2 x 3 x 4 x 8 x 50 x 25 x 125 b, 45 x 128 - 90 x 64
= ( 2 x 50 ) x ( 4 x 25 ) x ( 8 x 125 ) x 3 = 45 x ( 128 - 2 x 64 )
= 100 x 100 x 1000 x 3 = 45 x 0
= 30000000 = 0
c, 0,48 x 500 - 2,4 x 40 x 2
= 0,48 x 100 x 5 - 2,4 x 10 x 4 x 2
= 48 x 5 - 24 x 8
= 24 x ( 2 x 5 - 8 )
= 24 x 2
= 48
d, \(\frac{1998\times1996+1997\times11+1985}{1997\times1996-1995\times1996}\)
\(=\frac{1998\times1996+\left(1996+1\right)\times11+1985}{1996\times\left(1997-1995\right)}\)
\(=\frac{1998\times1996+1996\times11+11+1985}{1996\times2}\)
\(=\frac{1998\times1996+1996\times11+1996}{1996\times2}\)
\(=\frac{1996\times\left(1998+11+1\right)}{1996\times2}\)
\(=\frac{1996\times2010}{1996\times2}\)
\(=\frac{2010}{2}\)
\(=1005\)
a, \(2.3.4.8.50.25.125\)
\(=\left(2.50\right)\left(4.25\right)\left(8.125\right).3\)
\(=100.100.1000.3\)
\(=10000000.3\)
\(=30000000\)
b, \(45.128-90.64\)
\(=45.2.64-90.4\)
\(=90.64-90.64\)
\(=0\)
c, \(0,48.500-2,4.40.2\)
\(=0,48.100.5-2,4.2.10.4\)
\(=48.5-4,8.10.4\)
\(=48.5-48.4\)
\(=48\left(5-4\right)\)
\(=48.1\)
\(=48\)
d, \(\frac{1998.1996+1997.11+1985}{1997.1996-1995.1996}\) \(\)
\(=\frac{1998.1996+\left(1996+1\right).11+1985}{1996\left(1997-1995\right)}\)
\(=\frac{1998.1996+1996.11+11+1985}{1996.2}\)
\(=\frac{1998.1996+1996.11+1996}{1996.2}\)
\(=\frac{1996\left(1998+11+1\right)}{1996.2}\)
\(=\frac{1998+11+1}{2}\)
\(=\frac{2010}{2}\)
\(=1005\)