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\(\frac{3}{1.4}+\frac{3}{4.7}+\frac{3}{7.10}\)
\(=\frac{1}{1}-\frac{1}{4}+\frac{1}{4}-\frac{1}{7}+\frac{1}{7}-\frac{1}{10}\)
\(=\frac{1}{1}-\frac{1}{10}=\frac{9}{10}\)
1 \(A=\left(1+\frac{1}{2}\right)\times\left(1+\frac{1}{3}\right)\times\left(1+\frac{1}{4}\right)\times.........\times\left(1+\frac{1}{2016}\right)\times\left(1+\frac{1}{2017}\right)\)
\(A=\frac{3}{2}\times\frac{4}{3}\times\frac{5}{4}\times......\times\frac{2016}{2017}\times\frac{2018}{2017}\)
\(A=\frac{2018}{2}=1009\)
\(B=\frac{2}{3.5}+\frac{2}{5.7}+\frac{2}{7.9}+.......+\frac{2}{43.45}\)
\(B=\frac{1}{3}-\frac{1}{5}+\frac{1}{5}-\frac{1}{7}+\frac{1}{7}-......+\frac{1}{43}-\frac{1}{45}\)
\(B=\frac{1}{3}-\frac{1}{45}\)
\(B=\frac{14}{45}\)
2 \(\frac{2017}{2018}\times\frac{23}{47}+\frac{24}{2018}\times\frac{2017}{47}\)
\(=\frac{2017}{2018}\times\frac{23}{47}+\frac{24}{47}\times\frac{2017}{2018}\)
\(=\frac{2017}{2018}\times\left(\frac{23}{47}+\frac{24}{47}\right)\)
\(=\frac{2017}{2018}\times1\)
=\(\frac{2017}{2018}\)
bạn nào xem giải thế có đúng ko
Bài 1:
a) \(x.\dfrac{3}{4}=\dfrac{9}{14}\)
\(\Rightarrow x=\dfrac{9}{14}:\dfrac{3}{4}\)
\(\Rightarrow x=\dfrac{6}{7}\)
b) \(x:\dfrac{5}{9}=\dfrac{3}{10}\)
\(\Rightarrow x=\dfrac{3}{10}.\dfrac{5}{9}\)
\(\Rightarrow x=\dfrac{1}{6}\)
a) 2/3 + 3/4 = 8/12 + 9/12 = 17/12.
b) 2/3 x 9/5 = 18/15.
c) 2/3 : 3/4 = 2/3 x 4/3 = 8/9
d) 4/5 - 1/3 = 12/15 - 5/15 = 7/15
a 2/3 + 3/4 = 8/12 + 9/12 = 17/12
b 5/6 - 1/3= 5/6 - 2/6 = 3/6 = 1/2
c 4/5 chia 3/4 = 4/5 x 4/3 = 16/15
d 2/5 x 15/8 = 30/40 = 3/4
a)2/5+3/4
=23/20
b)2/5 + 3/10-1/2
=7/10-1/2
=1/5
c)8/11+8/33x3/4
=8/11 + 2/11
=10/11
tick cho mik nha mik cháy đen túi r
hok tốt
a) \(\frac{2}{7}\div\frac{2}{3}-\frac{1}{7}\)
\(=\frac{2}{7}\times\frac{3}{2}-\frac{1}{7}\)
\(=\frac{2\times3}{7\times2}\)
\(=\frac{3}{7}-\frac{1}{7}\)
\(=\frac{2}{7}\)
b) \(\frac{2}{5}\times\frac{4}{3}\div\frac{2}{3}\)
\(=\frac{2}{5}\times\frac{4}{3}\times\frac{3}{2}\)
\(=\frac{2\times4\times3}{5\times3\times2}\)
\(=\frac{4}{5}\)
a) \(A=\frac{2}{3.5}+\frac{2}{5.7}+\frac{2}{7.9}+...+\frac{2}{37.39}\)
\(A=\frac{1}{3}-\frac{1}{5}+\frac{1}{5}-\frac{1}{7}+\frac{1}{7}-\frac{1}{9}+...+\frac{1}{37}-\frac{1}{39}\)
\(A=\frac{1}{3}-\frac{1}{39}\)
\(A=\frac{13}{39}-\frac{1}{39}=\frac{12}{39}\)
b) \(B=\frac{3}{4.7}+\frac{3}{7.10}+\frac{3}{10.13}+...+\frac{3}{73.76}\)
\(B=\frac{1}{4}-\frac{1}{7}+\frac{1}{7}-\frac{1}{10}+\frac{1}{10}-\frac{1}{13}+...+\frac{1}{73}-\frac{1}{76}\)
\(B=\frac{1}{4}-\frac{1}{76}\)
\(B=\frac{19}{76}-\frac{1}{76}=\frac{18}{76}=\frac{9}{38}\)