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\(b.\frac{1}{3}+\frac{3}{35}< \frac{x}{210}< \frac{4}{7}+\frac{3}{5}+\frac{1}{3}\)
\(\Leftrightarrow\frac{35+9}{105}< \frac{x}{210}< \frac{60+63+35}{105}\)
\(\Leftrightarrow\frac{44}{105}< \frac{x}{210}< \frac{158}{105}\)
\(\Leftrightarrow\frac{88}{210}< \frac{x}{210}< \frac{316}{210}\)
Suy ra \(x\in\left\{89;90;100;...;313;314;315\right\}\)
\(c.\left(\frac{2}{11.13}+\frac{2}{13.15}+...+\frac{2}{19.21}\right)-x+\frac{221}{231}=\frac{4}{3}\)
\(\Leftrightarrow\left(\frac{1}{11}-\frac{1}{13}+\frac{1}{13}-\frac{1}{15}+...+\frac{1}{19}-\frac{1}{21}\right)-x+\frac{221}{231}=\frac{4}{3}\)
\(\Leftrightarrow\frac{1}{11}-\frac{1}{21}-x+\frac{221}{231}=\frac{4}{3}\)
\(\Leftrightarrow\frac{21-11-231x+221}{231}=\frac{308}{231}\)
\(\Leftrightarrow-231x=308-21+11-221\)
\(\Leftrightarrow-231x=77\)
\(\Leftrightarrow x=-\frac{77}{231}=-\frac{1}{3}\)
^^
mk chỉ làm được câu a thôi :
a) gọi A= \(\frac{2}{11.13}+\frac{2}{13.15}+......+\frac{2}{19.21}\)
A= \(\frac{1}{11}-\frac{1}{13}+\frac{1}{13}-\frac{1}{15}+......+\frac{1}{19}-\frac{1}{21}\)
\(\frac{1}{11}-\frac{1}{21}\)
\(\frac{21}{231}-\frac{11}{231}\)= \(\frac{10}{231}\)
\(\Rightarrow\frac{10}{231}.462-[2,04:\left(x+1,05\right)]:0,12=19\)
20,08 - \([2,04:\left(x+1,05\right)]:0,12=19\)
\(.........\)
\(\Leftrightarrow\left(\frac{1}{11}-\frac{1}{13}+\frac{1}{13}-\frac{1}{15}+...+\frac{1}{19}-\frac{1}{21}\right).462-\frac{17}{x+1,05}=19.\)
\(\Leftrightarrow\left(\frac{1}{11}-\frac{1}{21}\right)462-\frac{17}{x+1,05}=19\)
\(\Leftrightarrow20-\frac{17}{x+1,05}=19\)
\(\Leftrightarrow1-\frac{17}{x+1,05}=0\)
\(\Leftrightarrow x+1,05=17\)
\(\Leftrightarrow x=15,95\)
Đặt \(A=\frac{2}{11.13}+\frac{2}{13.15}+...+\frac{2}{19.21}\)
\(A=\frac{1}{11}-\frac{1}{13}+\frac{1}{13}-\frac{1}{14}+...+\frac{1}{19}-\frac{1}{21}\)
\(A=\frac{1}{11}-\frac{1}{21}=\frac{10}{231}\)
thay A vào ta được:
\(\frac{10}{231}-x+\frac{23}{231}=\frac{5}{77}\)
\(x+\frac{23}{231}=\frac{10}{231}-\frac{5}{77}=-\frac{5}{231}\)
\(x=-\frac{5}{231}-\frac{23}{231}=\frac{-4}{33}\)
\(\frac{1}{11}-\frac{1}{13}+\frac{1}{13}-\frac{1}{15}+...+\frac{1}{19}-\frac{1}{21}-x+\frac{23}{231}=\frac{5}{77}\)\(\frac{5}{77}\)
=>\(\frac{1}{11}-\frac{1}{21}-x+\frac{23}{231}=\frac{5}{77}\)
=>\(\frac{10}{231}+\frac{23}{231}-x=\frac{5}{77}\)
=>\(\frac{33}{231}-x=\frac{5}{77}\)
=>\(\frac{1}{7}-x=\frac{5}{77}\)
=>\(\frac{11}{77}-x=\frac{5}{77}\)
=>\(x=\frac{11}{77}-\frac{5}{77}=\frac{6}{77}\)
Vậy \(x=\frac{6}{77}\)
a, |x-6|=( 2/11.13 + 2/13.15 +... + 2/19.21 ) . 462/5
|x-6|=2.( 1/11.13 + 1/13.15+...+ 1/19.21 ) . 462/5
|x-6|=2.1/2.( 1/11 - 1/13 + 1/13 - 1/15 +...+ 1/19 - 1/21 ) .462/5
|x-6|= ( 1/11 - 1/21) . 462/5
|x-6|= 10/231 . 462/5
|x-6|= 4
x-6= 4 suy ra x=10
x-6= -4 suy ra x=2
b,2/a + 1/30 = b/6
=) 2/a= b/6 - 1/30
=) 2/a= 5b/30 - 1/30
=) 2/a= 5b - 1/30
=) 5b-1 thuộc Ư(30)
Ư(30)={+-1;+-2;+-3;+-5;+-6;+-10;+-15;+-30)
=) ta có bảng sau:
-0.2
vì b thuộc Z =) b=0
với b=0 thay vào ta đc :
2/a = 5.0-1/30
=) 2/a = -1/30
=) -1.a = 2.30
=) -a = 60
=) a = -60
vậy a= -60 ; b= 0