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a) DK de P xác dinh : \(\hept{\begin{cases}x\ge0\\x\ne1\end{cases}}\)
b) \(P=\frac{\sqrt{x}\left(\sqrt{x}+1\right)}{1-x}+\frac{\left(\sqrt{x}-2\right)^2+3\sqrt{x}-x}{1-\sqrt{x}}\)
\(=\frac{\sqrt{x}}{1-\sqrt{x}}+\frac{-\sqrt{x}+4}{1-\sqrt{x}}\)
\(=\frac{4}{1-\sqrt{x}}\)
c) de P > o thì \(1-\sqrt{x}>0\Rightarrow\sqrt{x}< 1\Rightarrow0< x< 1\)
\(a,x>0;x\ne4,9\)
\(b,Q=\left(\frac{1}{\sqrt{x}-3}-\frac{1}{\sqrt{x}}\right):\left(\frac{\sqrt{x}+3}{\sqrt{x}-2}-\frac{\sqrt{x}+2}{\sqrt{x}-3}\right)\)
\(Q=\left(\frac{\sqrt{x}-\sqrt{x}+3}{x-3\sqrt{x}}\right):\left(\frac{x-9-x+4}{\left(\sqrt{x}-2\right)\left(\sqrt{x}-3\right)}\right)\)
\(Q=\frac{3}{x-3\sqrt{x}}:\frac{-5}{\left(\sqrt{x}-2\right)\left(\sqrt{x}-3\right)}\)
\(Q=\frac{3}{\sqrt{x}\left(\sqrt{x}-3\right)}.\frac{\left(\sqrt{x}-2\right)\left(\sqrt{x}-3\right)}{-5}\)
\(Q=\frac{3\sqrt{x}-6}{-5\sqrt{x}}\)
\(c,Q< 0< =>\frac{3\sqrt{x}-6}{-5\sqrt{x}}\)
\(-5\sqrt{x}< 0\)
\(< =>3\sqrt{x}-6>0\)
\(\sqrt{x}>2\)
\(x>4\)
a,
\(A\Leftrightarrow\)\(\left(\frac{1}{\sqrt{x}-1}-\frac{\sqrt{x}+1}{\left(\sqrt{x}\right)^2+2\sqrt{x}+1}\right)\)\(\times\frac{x-1}{\sqrt{x}-3}\)
\(\Leftrightarrow\left(\frac{1}{\sqrt{x}-1}-\frac{\sqrt{x}+1}{\left(\sqrt{x}+1\right)^2}\right)\)\(\times\frac{x-1}{\sqrt{x}-3}\)(1)
Để A xđ <=> \(\hept{\begin{cases}x\ge0\\\sqrt{x}-1\ne0\\\sqrt{x}-3\ne0\end{cases}}\Leftrightarrow\hept{\begin{cases}x\ge0\\x\ne1\\x\ne9\end{cases}}\)
b , (1) <=> \(\left(\frac{\left(\sqrt{x}+1\right)^2-\left(\sqrt{x}+1\right)\left(\sqrt{x}-1\right)}{\left(\sqrt{x}-1\right)\left(\sqrt{x}+1\right)^2}\right)\)\(\times\frac{x-1}{\sqrt{x}-3}\)
<=> \(\left(\frac{\left(\sqrt{x}+1\right)\left(\sqrt{x}+1-\sqrt{x}+1\right)}{\left(\sqrt{x}-1\right)\left(\sqrt{x}+1\right)^2}\right)\)\(\times\frac{x-1}{\sqrt{x}-3}\)
<=> \(\frac{2}{x-1}\times\frac{x-1}{\sqrt{x}-3}\)
<=> \(\frac{2}{\sqrt{x}-3}\)
