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2*(5*42-20)
=2*(5*42-5*4)
=2*[5*(42-4)]
=2*(5*38)
=2*5*38
=10*38
=380
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\(=36:4\cdot3+104+210-\dfrac{18}{32}=341-\dfrac{9}{16}=\dfrac{5447}{16}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
a) \(2.7.12+49.53=7.\left(24+7.53\right)=7.395=2765\)
b) \(5.4^2-36:3^2=5.16-36:9=80-4-76\)
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`@` `\text {Ans}`
`\downarrow`
`12 \div 6 + 2. 7`
`= 2 + 2.7`
`= 2.(1 + 7)`
`= 2.8`
`= 16`
`5. 4^2 - 36 \div 3^2`
`= 5. 16 - 36 \div 9`
`= 80 - 4`
`= 76`
![](https://rs.olm.vn/images/avt/0.png?1311)
c) 3⁴ - 5.42
= 81 - 210
= -129
d) 120 : {54 - [50 : 2 - (3² - 2.4)]}
= 120 : {54 - [25 - (9 - 8)]}
= 120 : [54 - (25 - 1)]
= 120 : (54 - 24)
= 120 : 30
= 4
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`#3107.101107`
a,
$2014^{15} . (2x - 60) = 2014^{16}$
$\Rightarrow 2x - 60 = 2014^{16} \div 2014^{15}$
$\Rightarrow 2x - 60 = 2014$
$\Rightarrow 2x = 2074$
$\Rightarrow x = 1037$
Vậy, `x = 1037`
b,
`x + 18 \div 3^2 = 5.4^2`
`\Rightarrow x + 18 \div 9 = 5.16`
`\Rightarrow x + 9 = 80`
`\Rightarrow x = 80 - 9`
`\Rightarrow x = 71`
Vậy, `x = 71`
c,
`7.(42 - x) = 5^3 + 134`
`\Rightarrow 7.(42 - x) = 125 + 134`
`\Rightarrow 7(42 - x) = 259`
`\Rightarrow 42 - x = 259 \div 7`
`\Rightarrow 42 - x = 37`
`\Rightarrow x = 42 - 37`
`\Rightarrow x = 5`
Vậy, `x = 5.`
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a: \(\left[600-\left(40:2^3+3\cdot5^3\right)\right]:5\)
\(=\left[600-5-375\right]:5\)
\(=44\)
b: \(16\cdot12^2-\left(4\cdot23^2-59\cdot4\right)\)
\(=16\cdot144-4\cdot\left(23^2-59\right)\)
\(=2304-4\cdot470\)
\(=424\)
c: Ta có: \(2^{100}-\left(1+2+2^2+2^3+...+2^{99}\right)\)
\(=2^{100}-2^{100}+1\)
=1
d: Ta có: \(169\cdot2011^0-17\cdot\left(83-1702:23+1^{2012}\right)+2^7:2^4\)
\(=169-17\cdot\left(83-74+1\right)+2^3\)
\(=177-17\cdot10\)
=7
3.53-5.42
= 3 . 125 - 5 . 16
= 375 - 80
= 295
3x53-5x42= 3x125-5x16
=375-80
=295