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A= [(1+101)x101:2]-(102-103)
A= 5151+1
A=5152
B= [1+(-3)]+[4+(-5)]+.......[101+(-103)]+105
B= (-2)+(-2)...........+(-2)+105
=> A>B
B=(-2)x26+105
B=(-56)+105
B= 49
cái => A>B nó nằm ở dưới cùng ấy. Nãy gõ chứ nó bị nhảy phím
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\(\text{1+2+3+4+5+...+100-101-102-103-...-200}\)
\(\text{=1+2+3+4+5+...+100-(100+1)-(100+2)-(100+3)-...-(100+100)}\)
\(\text{=1+2+3+4+5+...+100-100-1-100-2-100-3-...-100-100}\)
\(\text{=(1+2+3+4+5+...+100-1-2-3-...-100)-100-100-100-...-100}\)(có 100 số 100)
\(=0-100-100-100-...-100\)(có 100 số 100)
\(=-10000\)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(B=\frac{101}{102}+\frac{102}{103}+\frac{103}{101}\)
\(B=1\)
B < 3
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1 + ( -2 ) + (-3 ) + 4 + 5 + ( -6 ) + ..... + 99 - 100 - 101 + 102 + 103
[ 1 + ( -2 )] + [(-3 ) + 4] + [5 + ( -6 )] + ..... +[-98+ 99 ]- 100 - 101 + 102 + 103
= ( -1 ) + 1 + ( -1 ) + ..... + (-1 ) +....+ (-1 )- 100 -101 + 102 + 103
= 0 + 50 - 100 - 101 + 102 + 103
= 54
Mình không chắc
1+(-2)+(-3)+4+5+(-6)+(-7)+8+.....+99-100-101+102+103
= 1 + ( 2 - 3 - 4 + 5 ) + (6 - 7 - 8 + 9 ) + ... ( 98 - 99 -100 + 101 ) +102
= 1 + 0 + 0 + 0 + .... + 102
=103
![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
1 + 2 - 3 - 4 + 5 + 6 -7 -8 + 9+...+101 + 102 - 103 - 104
= (1+2 - 3 - 4) + (5 + 6 -7 - 8) +...+ (101 + 102 - 103 - 104)
= -4.24
= -96
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\(3\times10^3+2\times10^2+5\times10^1\\ =3\times1000+2\times100+5\times10\\ =3000+200+50\\ =3250\)
`@` `\text {Ans}`
`\downarrow`
\(3\cdot10^3+2\cdot10^2+5\cdot10^1\)
\(=10\cdot\left(3\cdot10^2+2\cdot10+5\right)\)
\(=10\cdot\left[10\left(3\cdot10+2\right)+5\right]\)
\(=10\cdot\left[10\left(30+2\right)+5\right]\)
\(=10\cdot\left(320+5\right)\)
\(=10\cdot325\)
\(=3250\)