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\(\left(1+\dfrac{2}{3}\right).\left(1+\dfrac{2}{4}\right).\left(1+\dfrac{2}{5}\right)....\left(1+\dfrac{2}{2020}\right).\left(1+\dfrac{2}{2021}\right)\)
= \(\dfrac{5}{3}.\dfrac{6}{4}.\dfrac{7}{5}.\dfrac{8}{6}.\dfrac{9}{7}....\dfrac{2022}{2020}.\dfrac{2023}{2021}\)
= \(\dfrac{1}{3}.\dfrac{1}{4}.2022.2023\)
= \(\dfrac{337.2023}{2}\)
= \(\dfrac{\text{681751}}{2}\)
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c: Ta có: \(\dfrac{2}{5}\cdot\left[\left(\dfrac{3}{5}\right)^2:\left(-\dfrac{1}{5}\right)^2-7\right]\cdot\left(1000\right)^0\cdot\left|-\dfrac{11}{15}\right|\)
\(=\dfrac{2}{5}\cdot\left(\dfrac{9}{25}:\dfrac{1}{25}-7\right)\cdot1\cdot\dfrac{11}{15}\)
\(=\dfrac{2}{5}\cdot\dfrac{11}{15}\cdot2\)
\(=\dfrac{44}{75}\)
hellu cả lò nhà mik ạ giải giúp mik vs cả lò nhà mik ui
-5/7-(-5/67)+13/30+1/2+(-1 5/6)+1 3/14-(-2/5)
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=13/30-1-5/6+2/5+17/14+1/2-5/7+5/67
=-1+17/14-3/14+5/67
=-1+1+5/67
=5/67
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| x-2/3| = 1/3+2/5
= 11/15
=> x-2/3=11/15 hoặc x-2/3=-11/15
x= 7/5 x = -1/15
k cho mk nha
\(\left|x-\frac{2}{3}\right|-\frac{2}{5}=\frac{1}{3}\)
\(\Rightarrow\left|x-\frac{2}{3}\right|=\frac{1}{3}+\frac{2}{5}=\frac{11}{15}\)
\(\Rightarrow\orbr{\begin{cases}\Rightarrow x-\frac{2}{3}=\frac{11}{15}\\x-\frac{2}{3}=\frac{-11}{15}\end{cases}}\)
\(\Rightarrow\orbr{\begin{cases}\Rightarrow x=\frac{7}{15}\\x=\frac{-1}{15}\end{cases}}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
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a) \(...\Rightarrow\left\{{}\begin{matrix}x-2=0\\y+3=0\end{matrix}\right.\)
\(\Rightarrow\left\{{}\begin{matrix}x=2\\y=-3\end{matrix}\right.\)
b) \(...\Rightarrow|x-2|=|x+3|\Rightarrow\left[{}\begin{matrix}x-2=x+3\\x-2=-x-3\end{matrix}\right.\)
\(\Rightarrow\left[{}\begin{matrix}0x=5\\2x=-1\end{matrix}\right.\)
\(\Rightarrow\left[{}\begin{matrix}x\in\varnothing\\x=-\dfrac{1}{2}\end{matrix}\right.\)
\(\Rightarrow x=-\dfrac{1}{2}\)
c) \(|x-\dfrac{3}{4}|+|x+\dfrac{5}{4}|=1\)
\(\Rightarrow\left\{{}\begin{matrix}x-\dfrac{3}{4}\le0\\x+\dfrac{5}{4}\ge0\end{matrix}\right.\)
\(\Rightarrow\left\{{}\begin{matrix}x\le\dfrac{3}{4}\\x\ge-\dfrac{5}{4}\end{matrix}\right.\)
\(\Rightarrow-\dfrac{5}{4}\le x\le\dfrac{3}{4}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
? là phần đề thiếu bạn nhé, bạn xem lại đề.
\(\frac{3x}{10}+\frac{5}{2}+\frac{3}{5}=\frac{5}{2}\)
=> \(\frac{3}{10}x=-\frac{3}{5}\)
=>x=-2
\(\left[30\%x+2+\frac{1}{2}\right]+\frac{3}{5}=2+\frac{1}{2}\)
\(\left[30\%x+\frac{5}{2}\right]+\frac{3}{5}=\frac{5}{2}\)
\(30\%+\frac{5}{2}=\frac{5}{2}-\frac{3}{5}\)
\(30\%x+\frac{5}{2}=\frac{19}{10}\)
\(\frac{3}{10}x=\frac{19}{10}-\frac{5}{2}\)
\(\frac{3}{10}x=\frac{-3}{5}\)
\(x=\frac{-3}{5}:\frac{3}{10}\)
\(x=-2\)
Vậy x=-2