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24 tháng 2 2022
a: =1/8-1/8+2/5=2/5
b: =(-1/15-14/15)+(23/27+31/27)=2-1=1
c: \(=\dfrac{3}{7}\left(\dfrac{22}{21}+\dfrac{5}{21}+\dfrac{15}{21}\right)=\dfrac{3}{7}\cdot2=\dfrac{6}{7}\)
d: \(=\dfrac{-8}{9}\cdot\dfrac{3}{2}+\dfrac{1}{9}\cdot\dfrac{-3}{2}=-\dfrac{3}{2}\)
15 tháng 5 2022
1: \(=\dfrac{16}{15}\left(-\dfrac{4}{9}+\dfrac{3}{7}\right)+\dfrac{16}{15}\left(\dfrac{4}{7}-\dfrac{5}{9}\right)\)
\(=\dfrac{16}{15}\left(-\dfrac{4}{9}+\dfrac{3}{7}+\dfrac{4}{7}-\dfrac{5}{9}\right)=0\)
2: \(=\dfrac{29}{9}\left(15+\dfrac{4}{7}-8-\dfrac{1}{7}+\dfrac{15}{7}-\dfrac{1}{7}\right)\)
\(=\dfrac{20}{9}\cdot\left(7\cdot\dfrac{18}{7}\right)=\dfrac{20}{9}\cdot18=40\)
NT
2
VN
Võ Ngọc Phương
CTVHS
VIP
15 tháng 4 2023
\(\dfrac{-2}{9}+\dfrac{8}{15}+1\dfrac{2}{3}-\dfrac{7}{9}+\dfrac{-7}{15}\)
\(=\dfrac{-2}{9}+\dfrac{8}{15}+\dfrac{5}{3}-\dfrac{7}{9}+\dfrac{-7}{15}\)
\(=\left(\dfrac{-2}{9}+\dfrac{-7}{9}\right)+\left(\dfrac{8}{15}+\dfrac{-7}{15}\right)+\dfrac{5}{3}\)
\(=-1+\dfrac{1}{15}+\dfrac{5}{3}\)
\(=\dfrac{-14}{15}+\dfrac{5}{3}\)
\(=\dfrac{11}{15}\)
Chúc bạn học tốt
LM
Lê Minh Vũ
VIP
26 tháng 6 2023
\(-\dfrac{2}{9}+\dfrac{8}{15}+\dfrac{5}{3}-\dfrac{7}{9}+\dfrac{7}{15}\)
\(=-\dfrac{2}{9}-\dfrac{7}{9}+\dfrac{8}{15}+\dfrac{7}{15}+\dfrac{5}{3}\)
\(=-\dfrac{9}{9}+\dfrac{15}{15}+\dfrac{5}{3}\)
\(=-1+1+\dfrac{5}{3}\)
\(=0+\dfrac{5}{3}\)
\(=\dfrac{5}{3}\)
DA
26 tháng 6 2023
-2/9 + 8/15 + 5/3 - 7/9 + 7/15
= -2/9 - 7/9 + 8/15 + 7/15 + 5/3
= -9/9 + 15/15 + 5/3
= -1 + 1 + 5/3
= 0 + 5/3
=5/3
29 tháng 5 2018
\(A=\frac{1}{1\cdot2}+\frac{2}{2\cdot4}+\frac{3}{4\cdot7}+\frac{4}{7\cdot11}+...+\frac{10}{46\cdot56}\)
\(A=1-\frac{1}{2}+\frac{1}{2}-\frac{1}{4}+\frac{1}{4}-\frac{1}{7}+\frac{1}{7}-\frac{1}{11}+...+\frac{1}{46}-\frac{1}{56}\)
\(A=1-\frac{1}{56}\)
\(A=\frac{55}{56}\)
\(B=\frac{4}{3\cdot7}+\frac{4}{7\cdot11}+\frac{4}{11\cdot15}+...+\frac{4}{23\cdot27}\)
\(B=\frac{1}{3}-\frac{1}{7}+\frac{1}{7}-\frac{1}{11}+\frac{1}{11}-\frac{1}{15}+...+\frac{1}{23}-\frac{1}{27}\)
\(B=\frac{1}{3}-\frac{1}{27}\)
\(B=\frac{8}{27}\)
\(C=\frac{4}{3\cdot6}+\frac{4}{6\cdot9}+\frac{4}{9\cdot12}+...+\frac{4}{99\cdot102}\)
\(C=\frac{4}{3}\left(\frac{3}{3\cdot6}+\frac{3}{6\cdot9}+\frac{3}{9\cdot12}+...+\frac{3}{99\cdot102}\right)\)
\(C=\frac{4}{3}\left(\frac{1}{3}-\frac{1}{6}+\frac{1}{6}-\frac{1}{9}+\frac{1}{9}-\frac{1}{12}+...+\frac{1}{99}-\frac{1}{102}\right)\)
\(C=\frac{4}{3}\left(\frac{1}{3}-\frac{1}{102}\right)\)
\(C=\frac{4}{3}\cdot\frac{33}{102}\)
\(C=\frac{22}{51}\)
TM
8 tháng 4 2020
a) 5/9 + 4/9 . 3/7 + 4/9 . 4/7
= 5/9 + 4/9 . (3/7 + 4/7)
= 5/9 + 4/9 . 1
= 5/9 + 4/9
= 1
=-2/9-7/9+8/15+7/15+5/3
=5/3
no pham 1+34 x 321 + fe 43 - NA3= £76.99