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\(25x^2+90x+81=\left(5x+9\right)^2\)

\(64x^2-48x+9=\left(8x-3\right)^2\)

3 tháng 8 2023

a) 9x4+16y6-24x2y3

=(3x2)2-2.3x2.4y3+(4y3)2

=(3x2-4y3)2

b) 16x2-24xy+9y2

=(4x)2-2.4x.3y+(3y)2

=(4x-3y)2

c) 36x2-(3x-2)2

=(36x-3x+2)(36x+3x-2)

=(33x+2)(39x-2)

d) 27x3+54x2y+36xy2+8y3

=(3x)3+3.(3x)2.2y+3.3x.(2y)2+(2y)3

=(3x+2y)3

e) y9-9x2y6+27x4y3-27x6

=(y3)3-3.(y3)2.3x2+3.y3.(3x2)2-(3x2)3

=(y3-3x2)3

f) 64x3+1

= (4x)3+13

=(4x+1)[(4x)2-4x.1+12]

=(4x+1)(16x2-4x+1)

e) 27x6-8x3  *sửa đề*

=(3x2)3-(2x)3

=(3x2-2x)[(3x)2+3x2.2x+(2x)2]

=(3x2-2x)(9x2+6x3+4x2)

~~~

Bài 2: 

a: \(A=a^2+b^2+c^2+2ab-2ac-2bc+a^2+b^2+c^2-2ab-2bc+2ac\)

\(=2a^2+2b^2+2c^2-4bc\)

\(=2+2\cdot9+2\cdot1-4\cdot3\cdot\left(-1\right)=22+12=34\)

b: \(B=\left(a+b-a+b\right)\left(a+b+a-b\right)=4ab=4\cdot2\cdot5=40\)

2 tháng 8 2021

Trả lời:

5, x2 - y2 + 4x + 4 

= ( x2 + 4x + 4 ) - y2

= ( x + 2 )2 - y2

= ( x + 2 - y ) ( x + 2 + y )

6, x2 + 2x - 4y2 - 4y

= ( x2 - 4y2 ) + ( 2x - 4y )

= ( x - 2y ) ( x + 2y ) + 2 ( x - 2y )

= ( x - 2y ) ( x + 2y + 2 )

7, 3x2 - 4y + 4x - 3y2

= ( 3x2 - 3y2 ) + ( 4x - 4y )

= 3 ( x2 - y2 ) + 4 ( x - y )

= 3 ( x - y ) ( x + y ) + 4 ( x - y )

= ( x - y ) [ 3 ( x + y ) + 4 ]

= ( x - y ) ( 3x + 3y + 4 )

8, x4 - 6x3 + 54x - 81

= ( x4 - 81 ) - ( 6x3 - 54x )

= ( x2 - 9 ) ( x2 + 9 ) - 6x ( x2 - 9 )

= ( x2 - 9 ) ( x2 + 9 - 6x )

= ( x - 3 ) ( x + 3 ) ( x - 3 )2

= ( x - 3 )3 ( x + 3 )

2 tháng 8 2021

a, \(x^2-y^2+4x+4=\left(x+2\right)^2-y^2=\left(x+2-y\right)\left(x+2+y\right)\)

b, \(x^2+2x-4y^2-4y=\left(x-2y\right)\left(x+2y\right)+2\left(x-2y\right)=\left(x-2y\right)\left(x+2+2y\right)\)

c, \(3x^2-4y+4x-3y^2=3\left(x-y\right)\left(x+y\right)-4\left(y-x\right)=\left(x-y\right)\left(3x+3y+4\right)\)

d, \(x^4-6x^3+54x-81=\left(x^2+9\right)\left(x-3\right)\left(x+3\right)-6x\left(x^2-9\right)\)

\(=\left(x-3\right)\left(x+3\right)\left(x^2-6x+9\right)=\left(x-3\right)^3\left(x+3\right)\)

31 tháng 7 2021

\(1,x^2-y^2+4x-4y\)

\(\left(x-y\right)\left(x+y\right)+4\left(x-y\right)\)

\(\left(x-y\right)\left(x+y+4\right)\)

\(x^2+2x-4y^2-4y\)

\(\left(x-2y\right)\left(x+2y\right)+2\left(x-2y\right)\)

\(\left(x-2y\right)\left(x+2y+2\right)\)

\(3,3x^2-4y+4x-3y^2\)

\(3\left(x^2-y^2\right)-4\left(x-y\right)\)

\(3\left(x-y\right)\left(x+y\right)-4\left(x-y\right)\)

\(\left(x-y\right)\left(3x+3y-4\right)\)

\(x^4-6x^3+54x-81\)

\(x^4+3x^3-9x^3+27x^2-27x^2+81x-27x-81\)

\(\left(x^4+3x^3\right)-\left(9x^3+27x^2\right)+\left(27x^2+81x\right)-\left(27x+81\right)\)

\(x^3\left(x+3\right)-9x^2\left(x+3\right)+27x\left(x+3\right)-27\left(x+3\right)\)

\(\left(x+3\right)\left(x^3-9x^2+27x-27\right)\)

\(\left(x+3\right)\left(x-3\right)^3\)

25 tháng 3 2020

Đề là phân tích thành nhân tử hở bạn

25 tháng 3 2020
https://i.imgur.com/9Kjp6r0.jpg
6 tháng 9 2018

1/ x^2 +4xy +4y^2 = (x +2y)^2

2/ -x^3 +9x^2 -27x+27= - (x^3 -9x^2+27x-27) = - (x-3)^3

3/ 8x^6 +36x^4y+54^2y^2+27y^3 = (2x^2+3y)^3

4/ x^3 - 6x^2y+12xy^2 -8y^3= (x-2y)^3

6 tháng 9 2018

1) x2 + 4xy + 4y2 = ( x + 2y )2

2) - x3 + 9x2 - 27x + 27 = ( 3 - x )2

3) 8x6 + 36x4y + 54x2y2 + 27y3 = ( 2x2 + 3y )3

4) x3 - 6x2y + 12xy2 - 8y3 = ( x - 2y )3

5) x2 + 4y2 +1 - 4xy - 2x + 4y = ( x2 - 2y - 1 )2

6) x2 + y2 + 4 + 2xy + 4x + 4y = ( x + y + 2 )2

12 tháng 9 2015

a)x^2+2x-4y^2-4y

=(x2-4y2)+(2x-4y)

=(x-2y)(x+2y)+2.(x-2y)

=(x-2y)(x+2y+2)

b)x^4-6x^3+54x-81

=(x4-81)+(-6x3+54x)

=(x2-9)(x2+9)-6x.(x2-9)

=(x2-9)(x2+9-6x)

=(x-3)(x+3)(x-3)2

=(x-3)3(x+3)

c)ax^2+ax-bx^2-bx-a+b

=(ax2-bx2)+(ax-bx)+(-a+b)

=x2.(a-b)+x.(a-b)-(a-b)

=(a-b)(x2+x+1)

 

 

1: \(\left(x^2+1\right)^2-4x\left(1-x^2\right)\)

\(=x^4+2x^2+1-4x+4x^3\)

\(=x^4+4x^3+2x^2-4x+1\)

\(=\left(x^2+2x-1\right)^2\)

2: \(\left(x^2-8\right)^2+36\)

\(=x^4-16x^2+64+36\)

\(=x^4-16x^2+100\)

\(=x^4+20x^2+100-36x^2\)

\(=\left(x^2+10\right)^2-\left(6x\right)^2\)

\(=\left(x^2+6x+10\right)\left(x^2-6x+10\right)\)

3: \(x^4+4=x^4+4x^2+4-4x^2\)

\(=\left(x^2+2\right)^2-4x^2\)

\(=\left(x^2+2x+2\right)\left(x^2-2x+2\right)\)

4: \(x^4+64=x^4+16x^2+64-16x^2\)

\(=\left(x^2+8\right)^2-16x^2\)

\(=\left(x^2-4x+8\right)\left(x^2+4x+8\right)\)

5: \(64x^4+1=64x^4+16x^2+1-16x^2\)

\(=\left(8x^2+1\right)^2-16x^2\)

\(=\left(8x^2-4x+1\right)\left(8x^2+4x+1\right)\)