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`1, -2/9 xx 15/17 + (-2/9) xx 2/17`
`= -2/9 xx (15/17 + 2/17)`
`= -2/9 xx 17/17`
`=-2/9xx1`
`=-2/9`
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`-5/3 xx 6/5 + (-7/9) xx 3/10`
`= -30/15 + (-21/90)`
`= -2 + (-7/30)`
`=-60/30 +(-7/30)`
`=-67/30`
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`15/20 xx 7/5 + (-9/7) xx (-6/4)`
`=3/4 xx7/5 + (-9/7) xx(-6/4)`
`= 21/20 + 54/28`
`= 21/20 + 27/14`
`=417/140`
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`-25/13 xx 5/19 + (-25/13) xx 14/19`
`=-25/13 xx (5/19 +14/19)`
`=-25/13 xx 19/19`
`= -25/13 xx 1`
`=-25/13`
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`-7/13 xx 13/5 + (-9/7) xx 5/3`
`=-7/5 +(-15/7)`
`=-124/35`
![](https://rs.olm.vn/images/avt/0.png?1311)
\(\dfrac{9}{17}\times\dfrac{21}{13}+\dfrac{9}{17}\times\dfrac{5}{13}-\dfrac{9}{17}\times2\)
\(=\dfrac{9}{17}\times\left(\dfrac{21}{13}+\dfrac{5}{13}-2\right)\)
\(=\dfrac{9}{17}\times\left(\dfrac{26}{13}-2\right)=\dfrac{9}{17}\times\left(2-2\right)\)
\(=\dfrac{9}{17}\times0=0\)
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1: =-2/9(15/17+2/17)=-2/9
2: \(=\dfrac{-6}{3}+\dfrac{-21}{90}\)
=-2-7/30=-67/30
3: \(=\dfrac{3}{4}\cdot\dfrac{7}{5}+\dfrac{9}{7}\cdot\dfrac{3}{2}\)
=21/20+27/14=417/140
4: =-25/13(5/19+14/19)=-25/13
5: =-7/5-45/21=-7/5-15/7=-124/35
1: =-2/9(15/17+2/17)=-2/9
2: =−63+−2190=−63+−2190
=-2-7/30=-67/30
3: =34⋅75+97⋅32=34⋅75+97⋅32
=21/20+27/14=417/140
4: =-25/13(5/19+14/19)=-25/13
5: =-7/5-45/21=-7/5-15/7=-124/35
![](https://rs.olm.vn/images/avt/0.png?1311)
Bài 2 :
a, \(x=\dfrac{3}{5}-\dfrac{7}{8}=\dfrac{24-30}{40}=-\dfrac{6}{40}=-\dfrac{3}{20}\)
b, \(2x-1=-2\Leftrightarrow x=-\dfrac{1}{2}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
a: =-5/11-6/11+1=-11/11+1=0
b: =-13/17-13/21-4/17=-1-13/21=-34/21
b: \(=-\dfrac{5}{12}\cdot\dfrac{9}{20}\cdot\dfrac{7}{17}=\dfrac{-21}{272}\)
d: \(=\dfrac{13}{17}\left(-\dfrac{4}{5}-\dfrac{3}{4}\right)=\dfrac{13}{17}\cdot\dfrac{-31}{20}=\dfrac{-403}{340}\)
2 . |x-1| - 9 = -13 + 17
2 . |x-1| - 9 = 4
2 . |x-1| = 4 + 9
2 . |x-1| = 13
|x-1| = 13 : 2
|x-1| = 13/2
=> x - 1 = 13 / 2 hoặc x - 1 = -13 / 2
+) x - 1 = 13 / 2
x = 13 / 2 + 1
x = 15 / 2
+) x - 1 = -13 / 2
x = -13 / 2 + 1
x = -11 / 2
Vậy x \(\in\) { 15 / 2 ; -11 / 2 }
\(2\cdot\left|x-1\right|-9=-13+17\)
\(\Leftrightarrow2\cdot\left|x-1\right|-9=5\)
\(\Leftrightarrow2\cdot\left|x-1\right|=5+9\)
\(\Leftrightarrow2\cdot\left|x-1\right|=14\)
\(\Leftrightarrow\left|x-1\right|=\frac{14}{2}\)
\(\Leftrightarrow\left|x-1\right|=7\Leftrightarrow x-1=\pm7\)
TH1:\(x-1=17\)
\(\Leftrightarrow x=17+1=18\)
TH2:\(x-1=-17\)
\(\Leftrightarrow x=-17+1=-16\)
Vậy x=18;-16