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Lời giải:
$\frac{22}{15}:(11-x)+\frac{2}{3}=\frac{7}{5}$
$\frac{22}{15}:(11-x)=\frac{7}{5}-\frac{2}{3}=\frac{11}{15}$
$11-x=\frac{22}{15}: \frac{11}{15}=2$
$x=11-2=9$
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22 x 47 + 2 x 38 x 11 + 15 x 22
= 22 x 47 + 22 x 38 + 15 x 22
= 22 x (47 + 38 + 15 )
= 22 x 100
= 2200
Mk cx hâm mộ conan ng lâ rùi ko đọc, ko bít Ran và Shinichi bây h ra sao nữa
2x47+2x38x11+15x22
=22x47+22x38+22x15
=22x(47+38+15)
=22x100
=2200
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a. $\dfrac{14}{15}+\dfrac{2}{11}+\dfrac{1}{15}+\dfrac{4}{11}+\dfrac{10}{22}$
$=(\dfrac{14}{15}+dfrac{1}{15})+(\dfrac{2}{11}+\dfrac{4}{11}+\dfrac{10}{22})$
$=1+1=2$
b. $74\times43-43+27\times43$
$=(74-1+27)\times43$
$=100\times43=4300$
\(a)\dfrac{14}{15}+\dfrac{2}{11}+\dfrac{1}{15}+\dfrac{4}{11}+\dfrac{10}{22}\)
\(=\left(\dfrac{14}{15}+\dfrac{1}{15}\right)+\dfrac{2}{11}+\dfrac{4}{11}+\dfrac{5}{11}\)
\(=1+1=2\)
\(b)74\times43-43+27\times43\)
\(=43\times\left(74-1+27\right)\)
\(=43\times100=4300\)
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\(\dfrac{\dfrac{22}{15}}{11-x}\) + \(\dfrac{2}{3}\) = \(\dfrac{7}{5}\)
\(\dfrac{\dfrac{22}{15}}{11-x}\) = \(\dfrac{7}{5}\) - \(\dfrac{2}{3}\)
\(\dfrac{\dfrac{22}{15}}{11-x}\) = \(\dfrac{11}{15}\)
11 - \(x\) = \(\dfrac{22}{15}\) : \(\dfrac{11}{15}\)
11 - \(x\) = 2
\(x\) = 11 - 2
\(x\) = 9
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\(\frac{15}{8}\)+\(\frac{7}{12}\)-\(\frac{13}{3}\)x\(\frac{3}{8}\)
=\(\frac{45}{24}\)+\(\frac{14}{24}\)-\(\frac{13}{8}\)
=\(\frac{59}{24}\)-\(\frac{39}{24}\)
=\(\frac{20}{24}\)=\(\frac{5}{6}\)
\(\frac{11}{5}\)+\(\frac{5}{22}\):2+\(\frac{5}{6}\)
=\(\frac{11}{5}\)+\(\frac{5}{44}\)+\(\frac{5}{6}\)
=\(\frac{484}{220}\)+\(\frac{25}{220}\)+\(\frac{5}{6}\)
=\(\frac{509}{220}\)+\(\frac{5}{6}\)
=\(\frac{1527}{660}\)+\(\frac{550}{660}\)
=\(\frac{2077}{660}\)
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= ( 14/15 + 1/15 ) + ( 3/11 + 3/11 + 10/22 )
= 15/15 + ( 6/22 + 6/22 + 10/22 )
= 1 + 22/22
= 1 + 1
= 2
Tk nha !!
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14/15 + 6/11 + 1/15 + 5/11 + 22/11
=(14/15 +1/15)+(6/11 + 5/11 + 22/11)
=1+3
=4
\(2-\left(\frac{15}{22}+\frac{2}{11}\right)\)
\(=2-\left(\frac{15}{22}+\frac{4}{22}\right)\)
\(=2-\frac{19}{22}\)
\(=\frac{44}{22}-\frac{19}{22}\)
\(=\frac{25}{22}\)
\(=2-\frac{15}{22}-\frac{2}{11}\)
\(=\frac{44}{22}-\frac{15}{22}-\frac{4}{22}\)
\(=\frac{25}{22}\)