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`@` `\text {Ans}`
`\downarrow`
`1/3+6/9+4/5+5/25`
`= 1/3+2/3+4/5+1/5`
`= 1+1`
`= 2`
`4/7*2/5+4/7*3/5-1/7`
`= 4/7*(2/5+3/5)-1/7`
`= 4/7*1-1/7`
`= 4/7-1/7=3/7`
.....................................................
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1/1*2+1/2*3+1/34+1/4*5+1/5*6
=1-1/2+1/2-1/3+1/3-1/4+1/4-1/5+1/5-1/6
=1-1/6
=5/6
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(1 - 1/2) x (1 - 1/3) x (1 - 3/4) x (1 - 4/5)
= 1/2 x 2/3 x 1/4 x 1/5
= (1/2 x 2/3) x (1/4 x 1/5)
= 1/3 x 1/20
= 1/60
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a)
\(=\dfrac{13}{5}+\dfrac{7}{5}\cdot\dfrac{7}{2}\)
\(=\dfrac{13}{5}+\dfrac{49}{10}\\ =\dfrac{26}{10}+\dfrac{49}{10}\\ =\dfrac{15}{2}\)
b)
\(=\dfrac{52}{4}-\dfrac{11}{3}:\dfrac{7}{6}\)
\(=\dfrac{52}{4}-\dfrac{22}{7}\\ =\dfrac{69}{7}\)
a) $2\dfrac35 + 1\dfrac25 . 3\dfrac12$
$= \dfrac{13}5 + \dfrac75.\dfrac72$
$= \dfrac{26}{10} + \dfrac{49}{10}$
$=\dfrac{15}2$.
b) $4\dfrac34 - 3\dfrac23 : 1\dfrac16$
$= \dfrac{19}4 - \dfrac{11}3 : \dfrac76$
$= \dfrac{19}4 - \dfrac{11}3 . \dfrac67$
$= \dfrac{19}4 - \dfrac{22}7$
$= \dfrac{45}{28}$.
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\(D=\frac{5}{1+2+3}+\frac{5}{1+2+3+4}+...+\frac{5}{1+2+...+100}\)
\(\Rightarrow D=5\left(\frac{1}{1+2+3}+\frac{1}{1+2+3+4}+...+\frac{1}{1+2+...+100}\right)\)
\(\Rightarrow D=5\left(\frac{1}{\frac{4.3}{2}}+\frac{1}{\frac{5.4}{2}}+...+\frac{1}{\frac{101.100}{2}}\right)\)
\(\Rightarrow D=5\left(\frac{2}{3.4}+\frac{2}{4.5}+...+\frac{2}{100.101}\right)\)
\(\Rightarrow D=10\left(\frac{1}{3}-\frac{1}{4}+\frac{1}{4}-\frac{1}{5}+...+\frac{1}{100}-\frac{1}{101}\right)\)
\(\Rightarrow D=10\left(\frac{1}{3}-\frac{1}{101}\right)\)
\(\Rightarrow D=\frac{10}{3}-\frac{10}{101}=\frac{980}{303}\)
I don't now
or no I don't
..................
sorry
![](https://rs.olm.vn/images/avt/0.png?1311)
Ta có:
\(\frac{1}{2}\times\frac{2}{3}\times\frac{3}{4}\times...\times\frac{200}{201}\times x=\frac{1}{402}\)
\(\Rightarrow\frac{1}{201}\times x=\frac{1}{402}\Rightarrow x=\frac{1}{402}:\frac{1}{201}=\frac{1}{2}\)
Vậy x = 1/2.
k vs kb cho tớ nha!
1/2 . 2/3 . 3/4 .... . 200/201 . x = 1/402
\(\frac{1.2.3...200}{2.3.4...201}\). x = 1/402
1/201 . x = 1/402
x = 1/402 : 1/201
x = 1/2
\(\frac{1}{4}\)+ \(\frac{3}{5}\):\(\frac{1}{3}\)=
=\(\frac{1}{4}\)+\(\frac{9}{5}\)
=\(\frac{41}{20}\)