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\(a.\dfrac{3}{2}+\dfrac{-1}{3}< \dfrac{x}{6}< \dfrac{1}{9}+\dfrac{31}{18}\)
\(\Leftrightarrow\dfrac{7}{6}< \dfrac{x}{6}< \dfrac{11}{6}\)
\(\Leftrightarrow7< x< 11\)
\(\Leftrightarrow x\in\left\{8;9;10\right\}\)
\(b.\dfrac{-5}{12}+\dfrac{7}{12}+\dfrac{-1}{12}< \dfrac{x}{12}< \dfrac{2}{15}+\dfrac{1}{5}\)
\(\Leftrightarrow\dfrac{1}{12}< \dfrac{x}{12}< \dfrac{1}{3}\)
\(\Leftrightarrow\dfrac{1}{12}< \dfrac{x}{12}< \dfrac{4}{12}\)
\(\Leftrightarrow1< x< 4\)
\(\Leftrightarrow x\in\left\{2;3\right\}\)
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a: \(\Leftrightarrow\dfrac{x}{-4}=\dfrac{21}{y}=\dfrac{z}{-80}=\dfrac{3}{4}\)
=>x=-3; y=28; z=-60
b: 5/12=x/-72
=>x=-72*5/12=-6*5=-30
c: =>x+3=-5
=>x=-8
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a. -13 - (5-x) = -10
-13 - 5 + x = -10
x = -10 + 13 + 5
x = 8
Vậy x = 8
b, -3x - 15 = 2x - 20
-3x - 2x = -20 + 15
-5x = -5
x = -5 : (-5)
x = 1
Vậy x = 1
c, 5 - (x-3)^2 = 20
(x-3)^2 = 5 - 20
(x-3)^2 = -15 ( vô lí )
Vậy không có giá trị x thỏa mãn
d. | x - 12 | - (-5) = 12
| x - 12 | = 12 + (-5)
| x - 12 | = 7
x - 12 = + - 7
(+) x - 12 = 7 (+) x - 12 = -7
x = 7 + 12 x = -7 + 12
X = 19 x = 5
Vậy x thuộc { 19 ; 5 }
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Trả lời:
1) \(0< x-1\le2\)
\(\Rightarrow x-1\in\left\{1;2\right\}\)
\(\Rightarrow x\in\left\{2;3\right\}\)
#Huyền Anh
2) \(3\le x-2< 5\)
\(\Rightarrow x-2\in\left\{3;4\right\}\)
\(\Rightarrow x\in\left\{5;6\right\}\)
#Huyền Anh
![](https://rs.olm.vn/images/avt/0.png?1311)
\(-12\left(x-5\right)+7\left(3-x\right)=15\)
\(\Rightarrow-12x+60+21-7x=15\)
\(\Rightarrow-12x-7x=15-21-60\)
\(\Rightarrow-19x=-66\)
\(\Rightarrow x=\frac{66}{19}\)
\(\left|2x-5\right|=12\)
\(\Leftrightarrow\orbr{\begin{cases}2x-5=12\\2x-5=-12\end{cases}}\)
\(\Leftrightarrow\orbr{\begin{cases}2x=17\\2x=-7\end{cases}}\)
\(\Leftrightarrow\orbr{\begin{cases}x=\frac{17}{2}\left(t/m\right)\\x=-\frac{7}{2}\left(t/m\right)\end{cases}}\)
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|-5| . |x| = | -20 |
= 5 . x = 20
=) x = 20 : 5 = 4
|x| < -5
=) x \(\in\left\{-6;-7;-8;-9;-10;....\right\}\)
đăng kí kênh của v-i-s nha !
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a)15-5(x+4)=-12-3 b)|x+2|=0<=>x+2=0
15-5(x+4)=-15 =>x=-2
5(x+4)=15-(-15)
5(x+4)=30
x+4 =30:5
x+4 =6
x =2
c)|x-3|=7-(-2)
|x-3|=9
<=>x-3=-9=>x=-6
Hay:x-3=9=>x=12