Tìm x
A. 2/3 + x = 5/7 + 7/17 : 49 /34
B. X : 6/7 + 2/3 = 7/3
Giúp mình ><
K
Khách
Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
Những câu hỏi liên quan
20 tháng 7 2017
a) 31 - 2 ( x + 3 ) = 21
2 ( x + 3 ) = 31 - 21
2 ( x + 3 ) = 10
x + 3 = 10 : 2
x + 3 = 5
x = 5 - 3
x = 2
20 tháng 7 2017
b) ( x - 11 ) : 7 + 5 = 7
( x - 11 ) : 7 = 7 - 5
( x - 11 ) : 7 = 2
( x - 11 ) = 2 x 7
x - 11 = 14
x = 14 + 11
x = 25
ND
Nguyễn Đăng Nhân
CTVHS
20 tháng 9 2023
a) \(\left(x-1\right)^3=8=2^3\)
\(x-1=2\)
\(x=2+1=3\)
b) \(7^{2x-6}=49=7^2\)
\(2x-6=2\)
\(2x=6+2=8\)
\(x=8:2=4\)
c) \(\left(2x-14\right)^7=128=2^7\)
\(2x-14=2\)
\(2x=14+2=16\)
\(x=16:2=8\)
d) \(x^4\cdot x^5=5^3\cdot5^6=5^4\cdot5^5\)
\(x=5\)
e) \(3\cdot\left(x+2\right):7\cdot4=120\)
\(x+2=120:3\cdot7:4\)
\(x+2=70\)
\(x=70-2=68\)
AH
Akai Haruma
Giáo viên
20 tháng 9 2023
Lời giải:
a. $(x-1)^3=8=2^3$
$\Rightarrow x-1=2$
$\Rightarrow x=3$
b. $7^{2x-6}=49=7^2$
$\Rightarrow 2x-6=2$
$\Rightarrow 2x=8$
$\Rightarrow x=4$
c. $(2x-14)^7=128=2^7$
$\Rightarrow 2x-14=2$
$\Rightarrow 2x=16$
$\Rightarrow x=18$
d.
$x^4.x^5=5^3.5^6$
$x^9=5^9$
$\Rightarrow x=5$
e.
$3(x+2):7=120:4=30$
$3(x+2)=30.7=210$
$x+2=210:3=70$
$x=70-2=68$
15 tháng 7 2015
Tìm x:
\(a.\frac{2}{3}+x=\frac{5}{7}+\frac{7}{17}\div\frac{49}{34}\)
\(\frac{2}{3}+x=1\)
\(x=1-\frac{2}{3}\)
\(x=\frac{1}{3}.\)
\(b.x-\frac{4}{6}+\frac{5}{9}=\frac{28}{45}\)
\(x-\frac{4}{6}=\frac{28}{45}-\frac{5}{9}\)
\(x-\frac{4}{6}=\frac{1}{15}\)
\(x=\frac{1}{15}+\frac{4}{6}\)
\(x=\frac{11}{15}.\)
\(c.x\div\frac{6}{7}+\frac{2}{3}=\frac{7}{3}\)
\(x\div\frac{6}{7}=\frac{7}{3}-\frac{2}{3}\)
\(x\div\frac{6}{7}=\frac{5}{3}\)
\(x=\frac{5}{3}\times\frac{6}{7}\)
\(x=\frac{30}{21}.\)
\(d.\frac{15}{21}\div x=\frac{3}{7}+\frac{2008}{2009}\times\frac{2000}{2008}+\frac{9}{2008}\times\frac{2008}{2009}\)
\(\frac{5}{7}\div x=\frac{10}{7}\)
\(x=\frac{10}{7}\times\frac{5}{7}\)
\(x=\frac{50}{49}.\)
31 tháng 3 2021
Bài 1:
a) Ta có: \(\dfrac{2}{5}\cdot x+\dfrac{1}{3}=\dfrac{1}{5}\)
\(\Leftrightarrow\dfrac{2}{5}\cdot x=\dfrac{1}{5}-\dfrac{1}{3}=\dfrac{-2}{15}\)
\(\Leftrightarrow x=\dfrac{-2}{15}:\dfrac{2}{5}=\dfrac{-2}{15}\cdot\dfrac{5}{2}\)
hay \(x=-\dfrac{1}{3}\)
Vậy: \(x=-\dfrac{1}{3}\)
b) Ta có: \(\dfrac{1}{5}+\dfrac{5}{3}:x=\dfrac{1}{2}\)
\(\Leftrightarrow\dfrac{5}{3}:x=\dfrac{1}{2}-\dfrac{1}{5}=\dfrac{3}{10}\)
\(\Leftrightarrow x=\dfrac{5}{3}:\dfrac{3}{10}=\dfrac{5}{3}\cdot\dfrac{10}{3}\)
hay \(x=\dfrac{50}{9}\)
Vậy: \(x=\dfrac{50}{9}\)
c) Ta có: \(\dfrac{4}{9}-\dfrac{5}{3}\cdot x=-2\)
\(\Leftrightarrow\dfrac{5}{3}x=\dfrac{4}{9}+2=\dfrac{22}{9}\)
\(\Leftrightarrow x=\dfrac{22}{9}:\dfrac{5}{3}=\dfrac{22}{9}\cdot\dfrac{3}{5}\)
hay \(x=\dfrac{22}{15}\)
Vậy: \(x=\dfrac{22}{15}\)
d) Ta có: \(\dfrac{5}{7}:x-3=\dfrac{-2}{7}\)
\(\Leftrightarrow\dfrac{5}{7}:x=\dfrac{-2}{7}+3=\dfrac{19}{21}\)
\(\Leftrightarrow x=\dfrac{5}{7}:\dfrac{19}{21}=\dfrac{5}{7}\cdot\dfrac{21}{19}\)
hay \(x=\dfrac{15}{19}\)
Vậy:\(x=\dfrac{15}{19}\)
A: 2/3+x = 5/7+7/17: 49/34
2/3+x=5/7+2/7
2/3+x=1
x =1-2/3
x =1/3
B: X:6/7+2/3=7/3
X:6/7 =7/3-2/3
X:6/7 =5/3
X =5/3.6/7
X =10/7
k nhé bn ơi!