A = (1 + 1/2003 ) x ( 1 - 1/2004 ) x ( 1 + 1/2005 ) x ( 1 - 1/2006 ) x ( 1 + 1/2007 ) x ( 1 - 1/2008 )
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NN
13 tháng 11 2020
\(\frac{x+1}{2008}+\frac{x+2}{2007}+\frac{x+3}{2006}=\frac{x+4}{2005}+\frac{x+5}{2004}+\frac{x+6}{2003}\)
\(\Leftrightarrow\frac{x+1}{2008}+\frac{x+2}{2007}+\frac{x+3}{2006}+3=\frac{x+4}{2005}+\frac{x+5}{2004}+\frac{x+6}{2003}+3\)
\(\Leftrightarrow\left(\frac{x+1}{2008}+1\right)+\left(\frac{x+2}{2007}+1\right)+\left(\frac{x+3}{2006}+1\right)=\left(\frac{x+4}{2005}+1\right)\)
\(+\left(\frac{x+5}{2004}+1\right)+\left(\frac{x+6}{2003}+1\right)\)
\(\Leftrightarrow\frac{x+2009}{2008}+\frac{x+2009}{2007}+\frac{x+2009}{2006}=\frac{x+2009}{2005}+\frac{x+2009}{2004}+\frac{x+2009}{2003}\)
\(\Leftrightarrow\frac{x+2009}{2008}+\frac{x+2009}{2007}+\frac{x+2009}{2006}-\frac{x+2009}{2005}-\frac{x+2009}{2004}-\frac{x+2009}{2003}=0\)
\(\Leftrightarrow\left(x+2009\right)\left(\frac{1}{2008}+\frac{1}{2007}+\frac{1}{2006}-\frac{1}{2005}-\frac{1}{2004}-\frac{1}{2003}\right)=0\)(1)
Vì \(\frac{1}{2008}+\frac{1}{2007}+\frac{1}{2006}-\frac{1}{2005}-\frac{1}{2004}-\frac{1}{2003}\ne0\)(2)
Từ (1) và (2) \(\Rightarrow x+2009=0\)\(\Rightarrow x=-2009\)
Vậy \(x=-2009\)
NT
0
L
31 tháng 5 2017
câu 2 :
\(\Leftrightarrow\)\(\frac{x+1}{2008}+\frac{x+2}{2007}+\frac{x+3}{2006}-\frac{x+4}{2005}-\frac{x+5}{2004}-\frac{x+6}{2003}\)=0
\(\Leftrightarrow\frac{x+2009}{2008}+\frac{x+2009}{2007}+\frac{x+2009}{2006}-\frac{x+2009}{2005}-\frac{x+2009}{2004}-\frac{x-2009}{2003}\)=0
\(\Leftrightarrow\left(x+2009\right)\left(\frac{1}{2008}+\frac{1}{2007}+\frac{1}{2006}-\frac{1}{2005}-\frac{1}{2004}-\frac{1}{2003}\right)\)
\(\Rightarrow x+2009=0\)
\(\Rightarrow x=-2009\)
1 tháng 3 2017
1)
\(\frac{1}{2003}\times\left(1-\frac{1}{2004}\right)\times\left(1-\frac{1}{2005}\right)\times\left(1-\frac{1}{2006}\right)\)
\(=\frac{1}{2003}\times\frac{2003}{2004}\times\frac{2004}{2005}\times\frac{2005}{2006}\)
\(=\frac{1\times2003\times2004\times2005}{2003\times2004\times2005\times2006}\)
\(=\frac{1}{2006}\)
1 tháng 3 2017
Ta có:\(\frac{1}{2003}\times\left(1-\frac{1}{2004}\right)\times\left(1-\frac{1}{2005}\right)\left(1-\frac{1}{2006}\right)\)
\(=\frac{1}{2003}.\frac{2003}{2004}.\frac{2004}{2005}.\frac{2005}{2006}\)
\(=\frac{1}{2006}\)
BT
16 tháng 5 2016
a)=1/2*2/3......*19/20
=1/20
b)=3/2*4/3......*2008/2007
=3/2007
NT
2
7 tháng 4 2016
1/2005 x(1-1/2006)x(1-2007)x(1-1/2008)
=1/2005x2005/2006x2006/2007-2007/2008
Rút gọn rồi ta được kết quả
1/2008
26 tháng 8 2017
a. 2006/2005 x 2007/2006 x 2008/2007 x 2009/2008 x 2010/2009'
= 2006 x 2007 x 2008 x 2009 x 2010 / 2005 x 2006 x 2007 x 2008 x 2009
= 2010/2005
= 402/401
N
26 tháng 8 2017
\(\left(1+\frac{1}{2005}\right)x\left(1+\frac{1}{2006}\right)x\left(1+\frac{1}{2007}\right)x\left(1+\frac{1}{2008}\right)x\left(1+\frac{1}{2009}\right)\)
\(=\frac{2006}{2005}x\frac{2007}{2006}x\frac{2008}{2007}x\frac{2009}{2008}x\frac{2010}{2009}\)
\(=\frac{2010}{2005}\)
\(=\frac{402}{401}\)
\(A=\left(1+\frac{1}{2003}\right).\left(1-\frac{1}{2004}\right).\left(1+\frac{1}{2005}\right).\left(1-\frac{1}{2006}\right).\left(1+\frac{1}{2007}\right).\left(1-\frac{1}{2008}\right)\)
\(=\frac{2004}{2003}.\frac{2003}{2004}.\frac{2006}{2005}.\frac{2005}{2006}.\frac{2008}{2007}.\frac{2007}{2008}\)
\(=1\)