3 | + | 3 | + … + | 3 | = | |
1 x 4 | 4 x 7 | 169 x 172 |
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![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
`1, -2/9 xx 15/17 + (-2/9) xx 2/17`
`= -2/9 xx (15/17 + 2/17)`
`= -2/9 xx 17/17`
`=-2/9xx1`
`=-2/9`
__
`-5/3 xx 6/5 + (-7/9) xx 3/10`
`= -30/15 + (-21/90)`
`= -2 + (-7/30)`
`=-60/30 +(-7/30)`
`=-67/30`
__
`15/20 xx 7/5 + (-9/7) xx (-6/4)`
`=3/4 xx7/5 + (-9/7) xx(-6/4)`
`= 21/20 + 54/28`
`= 21/20 + 27/14`
`=417/140`
__
`-25/13 xx 5/19 + (-25/13) xx 14/19`
`=-25/13 xx (5/19 +14/19)`
`=-25/13 xx 19/19`
`= -25/13 xx 1`
`=-25/13`
__
`-7/13 xx 13/5 + (-9/7) xx 5/3`
`=-7/5 +(-15/7)`
`=-124/35`
![](https://rs.olm.vn/images/avt/0.png?1311)
1: =-2/9(15/17+2/17)=-2/9
2: \(=\dfrac{-6}{3}+\dfrac{-21}{90}\)
=-2-7/30=-67/30
3: \(=\dfrac{3}{4}\cdot\dfrac{7}{5}+\dfrac{9}{7}\cdot\dfrac{3}{2}\)
=21/20+27/14=417/140
4: =-25/13(5/19+14/19)=-25/13
5: =-7/5-45/21=-7/5-15/7=-124/35
1: =-2/9(15/17+2/17)=-2/9
2: =−63+−2190=−63+−2190
=-2-7/30=-67/30
3: =34⋅75+97⋅32=34⋅75+97⋅32
=21/20+27/14=417/140
4: =-25/13(5/19+14/19)=-25/13
5: =-7/5-45/21=-7/5-15/7=-124/35
![](https://rs.olm.vn/images/avt/0.png?1311)
1: Ta có: \(\left(x+3\right)^2-\left(x+2\right)\left(x-2\right)=4x+17\)
\(\Leftrightarrow x^2+6x+9-x^2+4-4x=17\)
\(\Leftrightarrow x=2\)
3: Ta có: \(\left(2x+3\right)\left(x-1\right)+\left(2x-3\right)\left(1-x\right)=0\)
\(\Leftrightarrow2x^2-2x+3x-3+2x-2x^2-3+3x=0\)
\(\Leftrightarrow6x=6\)
hay x=1
![](https://rs.olm.vn/images/avt/0.png?1311)
1) -x - 3 = 7
-x = 7 + 3
-x = 10
x = -10
2) x + 5 = -10
x = -10 - 5
x = -15
3) 2x - 7 = 713
2x = 713 + 7
2x = 720
x = 720 : 2
x = 360
4) -129 - (35 - x) = 55
35 - x = -129 - 55
35 - x = -184
x = 35 - (-184)
x = 219
5) 103 - x = 16 - (13 - 8)
103 - x = 16 - 5
103 - x = 11
x = 103 - 11
x = 192
![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
a) \(44+\left(x+3\right)=\left(-5\right)^3.\left(-\dfrac{1}{4}\right)\)
\(\Rightarrow44+x+3=-125.\left(-\dfrac{1}{4}\right)\)
\(\Rightarrow x=\dfrac{125}{4}-47=-\dfrac{63}{4}\)
b) \(8.\left(2-x\right)-6.\left(3-x\right)=0\)
\(\Rightarrow16-8x-18+6x=0\)
\(\Rightarrow-2-2x=0\)
=> 2 + 2x = 0
=> 2x = -2
=> x = -1
a) 44(x-3)=(-5)3.(-1)4
=>44x-132=(-125).1
=> 44x =132-125
=> 44x = 7
=> x =\(\dfrac{7}{44}\)
Vậy \(x=\dfrac{7}{44}\)
b) 8(2-x)-6(3-x)=0
=>16-8x-18+6x=0
=>-2-2x =0
=> -2x =2
=> x =2:-2=1
3/1x4 + 3/4x7 +...+ 3/169x172
=(1/1 - 1/4 + 1/4 - 1/7 +...+ 1/169 - 1/172)
=1/1 - 1/172
=171/172
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