8/27 + 4/15 + 19/27 + 11/15
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MN
4 tháng 3 2018
\(\frac{8}{27}+\frac{4}{15}+\frac{19}{27}+\frac{11}{15}\)
\(=\left(\frac{8}{27}+\frac{19}{27}\right)+\left(\frac{4}{15}+\frac{11}{15}\right)\)
\(=\frac{27}{27}+\frac{15}{15}\)
\(=1+1=2\)
4 tháng 3 2018
8/27+4/15+19/27+11/15
=(8/27+19/27)+(4/15+11/5)
=27/27+15/15
=1+1
=2
NT
10
S
4
27 tháng 2 2022
a: =(8/27+19/27)+(4/15+11/15)=1+1=2
b: =(12/13+8/13+6/13)+(2/7+5/7)=2+1=3
KS
8 tháng 4 2022
9/14 .<.. 11/14 4/25 .<.. 4/23 5/6 ..<. 7/8 1 ..>. 14/15
8/9 ..=. 24/27 20/19 ..>. 20/27 8/7 .>.. 9/8 1 .<..15/14
TT
2
14 tháng 3 2018
8/27+4/5+19/27+11/15=(8/27+19/27) + (4/5+11/15)
= 1+ (12/15+11/15)
= 1+ 1/8/15=2/8/15
12/13+2/7+8/13+6/13+5/7=(12/13+8/13+6/13) + (2/7+5/7)
= 2+ 1
=3
Ý a có thể bạn chép nhầm 4/5 rồi
29 tháng 5 2018
\(A=\frac{1}{1\cdot2}+\frac{2}{2\cdot4}+\frac{3}{4\cdot7}+\frac{4}{7\cdot11}+...+\frac{10}{46\cdot56}\)
\(A=1-\frac{1}{2}+\frac{1}{2}-\frac{1}{4}+\frac{1}{4}-\frac{1}{7}+\frac{1}{7}-\frac{1}{11}+...+\frac{1}{46}-\frac{1}{56}\)
\(A=1-\frac{1}{56}\)
\(A=\frac{55}{56}\)
\(B=\frac{4}{3\cdot7}+\frac{4}{7\cdot11}+\frac{4}{11\cdot15}+...+\frac{4}{23\cdot27}\)
\(B=\frac{1}{3}-\frac{1}{7}+\frac{1}{7}-\frac{1}{11}+\frac{1}{11}-\frac{1}{15}+...+\frac{1}{23}-\frac{1}{27}\)
\(B=\frac{1}{3}-\frac{1}{27}\)
\(B=\frac{8}{27}\)
\(C=\frac{4}{3\cdot6}+\frac{4}{6\cdot9}+\frac{4}{9\cdot12}+...+\frac{4}{99\cdot102}\)
\(C=\frac{4}{3}\left(\frac{3}{3\cdot6}+\frac{3}{6\cdot9}+\frac{3}{9\cdot12}+...+\frac{3}{99\cdot102}\right)\)
\(C=\frac{4}{3}\left(\frac{1}{3}-\frac{1}{6}+\frac{1}{6}-\frac{1}{9}+\frac{1}{9}-\frac{1}{12}+...+\frac{1}{99}-\frac{1}{102}\right)\)
\(C=\frac{4}{3}\left(\frac{1}{3}-\frac{1}{102}\right)\)
\(C=\frac{4}{3}\cdot\frac{33}{102}\)
\(C=\frac{22}{51}\)
`#3107.101107`
\(\dfrac{8}{27}+\dfrac{4}{15}+\dfrac{19}{27}+\dfrac{11}{15}\\ =\left(\dfrac{8}{27}+\dfrac{19}{27}\right)+\left(\dfrac{4}{15}+\dfrac{11}{15}\right)\\ =\dfrac{27}{27}+\dfrac{15}{15}\\ =1+1\\ =2\)
\(\dfrac{8}{27}+\dfrac{4}{15}+\dfrac{19}{27}+\dfrac{11}{15}\)
\(=\left(\dfrac{8}{27}+\dfrac{19}{27}\right)+\left(\dfrac{4}{15}+\dfrac{11}{15}\right)\)
\(=\dfrac{27}{27}+\dfrac{15}{15}=1+1=2\)