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27 tháng 12 2017

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28 tháng 12 2017

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10 tháng 8 2017

2.Gọi số cần tìm là \(x\left(x\ne0,x>9\right)\)

Ta có:

\(53=mx+2\left(m\in N\right)\\ \Rightarrow51=mx\\ \Rightarrow x\inƯ\left(51\right)\left(1\right)\\ 77=nx+9\left(n\in N\right)\\ \Rightarrow68=nx\\ \Rightarrow x\inƯ\left(68\right)\left(2\right)\)

Từ (1) và (2) ta có:

\(x\inƯC\left(51,68\right)\)

\(51=3\cdot17\\ 68=2^2\cdot17\\ \Rightarrow\text{ƯCLN}\left(51,68\right)=17\\ ƯC\left(51,68\right)=Ư\left(17\right)=\left\{1;17\right\}\)

Vì x > 9 nên x = 17

Vậy số chia là 17

10 tháng 8 2017

3. Làm câu b trước, các câu kia trả lời tương tự hoặc áp dụng điều đã chứng minh

b,

\(a+a^2+a^3+a^4+...+a^{29}+a^{30}\\ =\left(a+a^2\right)+\left(a^3+a^4\right)+...+\left(a^{29}+a^{30}\right)\\ =a\left(1+a\right)+a^3\left(1+a\right)+...+a^{29}\left(1+a\right)\\ =\left(1+a\right)\left(a+a^3+...+a^{29}\right)⋮a+1\)

Vậy \(a+a^2+a^3+a^4+...+a^{29}+a^{30}⋮a+1\) với a thuộc N

17 tháng 10 2016

A=3+32+33...+329+330

A=(3+32+33)+...+(328+329+330)

A=3.(1+3+32)+...+328.(1+3+32)

A=3.13+...+328.13

A=13.(3+...+328) chia hết cho 13

17 tháng 10 2016

A= 3(1+3+3^2)+3^4(1+3+3^2)+3^7(1+3+3^2)+...+3^28.(1+3+3^2)

A=(1+3+3^2)(3+3^4+3^7+...+3^25+3^28)

=13.(3+3^4+3^7+...3^28) vậy A chia hết cho 13

10 tháng 11 2015

1):

Ta có: 51 chia hết cho 3

120 chia hết cho 3

453 chia hết cho 3

=>51a+120b+453c chia hết cho 3

2):

Ta có:

A=5+52+53+...+530

=>A=(5+52)+52(5.52)+...+528(5+52)

=>A=(5+52).(52+54+...+528)

Vì 5+52=30 chia hết cho 6

=>A chia hết cho 6

1 tháng 12 2017

Ta có : A = (51+52+53)+(54+55+56)+...+(528+529530)

          A = 155 + 53.(51+52+53)+...+527.(51+52+53)

          A = 155 + 53. 155+...+527.155

          A = 155.(1+53+...+527)  chia hết cho 155 

Vậy A chia hết cho 155

(5+52+53)+(54+55+56)+...+(528+529+530

= 155 +53(5+52+53)+...+527(5+52+53

=155+53.155+...+527.155 

=155(1+53+..+527) chia hết cho 155

Ta có : A = 5 + 52 + 53 + ..... + 58

=> A = (5 + 52) + (53 + 54) + ..... + (57 + 58)

=> A = (5 + 52) + 52(5 + 52) + ..... + 56(5 + 52)

=> A = 30 + 52.30 + .... + 56.30

=> A = 30(1 + 52 + .... + 56

Vì (1 + 52 + .... + 56) là số nguyên 

Vậy A = 30(1 + 52 + .... + 56) chia hết cho 30 

8 tháng 6 2018

A=5+5^2+5^3+...+5^20

=(5+5^2)+(5^3+5^4)+...+(5^19+5^20)

=(5+5^2)+5^2(5+5^2)+...5^18(5+5^2)

=30+5^2.30+5^4.30+5^6.30+..+5^18.30

=30(1+5^2+5^4+5^6+..+5^18)(chia hết cho 30)

Vậy A là bội của 30

4 tháng 8 2017

a)A=5+52+53+...+58

A= (5+52)+(53+54) + ... + (57+58)

A= 5( 1+5) + 52(5+52)+... + 56(5+52)

A= 30 + 52 . 30 + ... +56.30

A = 30 ( 1 + 52+...+56) chia hết cho 30

=> A chia hết cho 30

4 tháng 8 2017

b)B=3+33+35+37+...+329 

B = (3 + 33 + 35) + (37+39+311) + ... + ( 327+328+329)

B = 273 + 36 (3 + 33 + 35) + ... + 326 (3 + 33 + 35

B = 273 + 36.273 + ... + 326.273

B = 273 ( 1 + 36+...326) chia hết cho 273

=> B chia hết cho 273