a) Tính 7 + 5.
b) Tính 7 + 6.
K
Khách
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QT
Quoc Tran Anh Le
Giáo viên
1 tháng 12 2023
Đúng(0)
Những câu hỏi liên quan
6 tháng 3 2023
Bài 5:
a: =1/3+2/5
=5/15+6/15
=11/15
b: =6/21+12/21=18/21=6/7
c: =16/24+10/24
=26/24
=13/12
d: =4/12+3/12+10/12
=17/12
e: =19/24-9/24
=10/24
=5/12
f: =8/9-3/9=5/9
g: =9/3+1/3=10/3
k: =15/24+42/24+14/24
=71/24
4 tháng 3 2019
1. a) \(\frac{6}{11}+\frac{7}{5}=\frac{30}{55}+\frac{77}{55}=\frac{30+77}{55}=\frac{107}{55}\)
b) \(\frac{9}{5}-\frac{6}{7}=\frac{63}{35}-\frac{30}{35}=\frac{63-30}{35}=\frac{33}{35}\)
c) \(\frac{11}{2}-3=\frac{11}{2}-\frac{3}{1}=\frac{11}{2}-\frac{6}{2}=\frac{11-6}{2}=\frac{5}{2}\)
d) \(15+\frac{1}{3}=\frac{15}{1}+\frac{1}{3}=\frac{45}{3}+\frac{1}{3}=\frac{45+1}{3}=\frac{46}{3}\)
4 tháng 3 2019
2. a)\(\frac{3}{7}\cdot\frac{7}{2}=\frac{21}{14}\)
b) \(6\cdot\frac{7}{9}=\frac{42}{9}\)
c) \(\frac{8}{15}\cdot5=\frac{40}{15}\)
d) \(\frac{6}{13}\cdot\frac{26}{2}=\frac{156}{26}\)
Dấu chấm mấy bài trên thay thế cho dấu nhân nhá..
OT
2
21 tháng 2 2022
a: \(=\left(\dfrac{4}{9}+\dfrac{5}{9}\right)+\left(\dfrac{1}{8}+\dfrac{7}{8}\right)=1+1=2\)
b: \(=\left(\dfrac{1}{6}+\dfrac{4}{6}+\dfrac{7}{6}\right)+\left(\dfrac{5}{12}+\dfrac{7}{12}\right)=2+1=3\)
PT
1
CM
22 tháng 10 2017
a) 5 × 7 – 7 = 28
b) 3 × 9 – 18 = 9
c) 5 × 7 + 7 = 42
d) 4 × 6 – 18 = 6
PT
1
CM
4 tháng 4 2017
a, 7×5 + 15 = 35 + 15 = 50
b, 6×5 + 31 = 30 + 31 = 61
c, 22 + 7×4 = 22 + 28 = 50
d, 7×9 + 17 = 63 + 17 = 80
24 tháng 3 2021
\(A,\dfrac{7}{11}+\dfrac{5}{6}-\dfrac{-4}{11}-\dfrac{1}{6}\)
\(= (\dfrac{7}{11}+\dfrac{-4}{11})-(\dfrac{5}{6}-\dfrac{1}{6})\)
\(=\dfrac{3}{11}-\dfrac{2}{3}\)
\(= \dfrac{9}{33}-\dfrac{22}{33}\)
\(= \dfrac{-13}{33}\)
\(B,\dfrac{5}{9}.\dfrac{7}{3}+\dfrac{5}{9}.\dfrac{9}{13}-\dfrac{5}{9}:\dfrac{13}{5}\)
\(=(\dfrac{5}{9}.\dfrac{5}{9}:\dfrac{5}{9}).\dfrac{7}{3}+\dfrac{9}{13}-\dfrac{13}{5}\)
\(=(\dfrac{5}{9}.\dfrac{7}{3})+(\dfrac{9}{13}-\dfrac{13}{5})\)
\(=(\dfrac{5}{9}.\dfrac{21}{9})+(\dfrac{45}{65}-\dfrac{169}{65})\)
\(=\dfrac{35}{27}+\dfrac{-124}{65}\)
\(=\dfrac{2275}{1755}+\dfrac{-3348}{1755}\)
\(=\dfrac{-1073}{1755}\)
NA
Nguyễn An Ninh
VIP
25 tháng 4 2023
a\()\) 1/2 x 2/3 : 5/6 x 5/6
=2/6 : 35/36
=1/3 x 36/35
=36/105=12/35
b\()\)11x15x56/6x35x38
=165x56/6x35x38
=9240/6x35x38
=1540x35x38
=53900x38
=2,048,200
c\()\) 2/7 x 7/5 + 2/7 - 2/7 x 6/5
=2/7x\(\left(\dfrac{7}{5}-\dfrac{2}{7}\right)\)+2/7
=2/7 x 39/35 + 2/7
=2/7 x \(\left(\dfrac{39}{35}+1\right)\)
=2/7 x 74
=148/7
NT
Nguyễn Thị Thương Hoài
Giáo viên
VIP
4 tháng 5 2023
a, \(\dfrac{3}{5}\) \(\times\) \(\dfrac{6}{7}\) + \(\dfrac{3}{5}\) : 7 + \(\dfrac{6}{5}\)
= \(\dfrac{3}{5}\) \(\times\) \(\dfrac{6}{7}\) + \(\dfrac{3}{5}\) \(\times\) \(\dfrac{1}{7}\) + \(\dfrac{6}{5}\)
= \(\dfrac{3}{5}\) \(\times\) ( \(\dfrac{6}{7}\) + \(\dfrac{1}{7}\)) + \(\dfrac{6}{5}\)
= \(\dfrac{3}{5}\) + \(\dfrac{6}{5}\)
= \(\dfrac{9}{5}\)
b, 2018 \(\times\) ( \(\dfrac{1}{2}\) + \(\dfrac{1212}{2424}\))
= 2018 \(\times\) ( \(\dfrac{1}{2}\) + \(\dfrac{1}{2}\))
= 2018 \(\times\)1
= 2018
4 tháng 5 2023
a) 3/5 x 6/7 + 3/5 x 1/7 + 6/5
3/5 x ( 6/7 + 1/7 ) + 6/5
3/5 x 7/7 + 6/5
3/5 x 1 + 6/5
3/5 + 6/5
9/5
b) 2018 x ( 1/2 + 1212/ 2424 )
2018 x ( 1/2 + 12/24 )
2018 x ( 1/2 + 1/2 )
2018 x 2/2
2018 x 1
2018
Học tốt
18 tháng 3 2023
\(a,\dfrac{4}{5}+\dfrac{2}{7}=\dfrac{28}{35}+\dfrac{10}{35}=\dfrac{38}{35}.\)
\(b,2-\dfrac{8}{9}=\dfrac{18}{9}-\dfrac{8}{9}=\dfrac{10}{9}.\)
\(c,\dfrac{5}{8}\times3=\dfrac{5\times3}{8}=\dfrac{15}{8}.\)
\(d,5:\dfrac{6}{21}=5\times\dfrac{21}{6}=\dfrac{5\times21}{6}=\dfrac{105}{6}=\dfrac{35}{2}.\)
\(đ,\dfrac{3}{5}\times\dfrac{4}{5}\times\dfrac{6}{7}=\dfrac{3\times4\times6}{5\times5\times7}=\dfrac{72}{175}.\)
Y
18 tháng 3 2023
\(a,\dfrac{4}{5}+\dfrac{2}{7}=\dfrac{28}{35}+\dfrac{10}{35}=\dfrac{38}{35}\)
\(b,2-\dfrac{8}{9}=\dfrac{18}{9}-\dfrac{8}{9}=\dfrac{10}{9}\)
\(c,\dfrac{5}{8}\times3=\dfrac{5\times3}{8\times1}=\dfrac{15}{8}\)
\(d,\dfrac{3}{5}\times\dfrac{4}{5}\times\dfrac{6}{7}=\dfrac{3\times4\times6}{5\times5\times7}=\dfrac{72}{175}\)