\(65+70\div2\)
K
Khách
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CM
23 tháng 11 2019
65 - 5 = 60 65 - 60 = 5 65 - 65 = 0
70 - 30 = 40 94 - 3 = 91 33 - 30 = 3
21 - 1 = 20 21 - 20 = 1 32 - 10 = 22
LG
9 tháng 12 2021
65 - 5 = 60 65 - 60 = 5 65 - 65 = 0
70 - 30 = 40 94 - 3 = 91 33 - 30 = 3
21 - 1 = 20 21 - 20 = 1 32 - 10 = 22
Toán lớp 1 không có cái này đâu !!!
BB
2
1 tháng 3 2020
\(6\div2\left(1+2\right)=6\div2.3\\ =6\div6\\ =1 \)
\(6\div2\times\left(1+2\right)=3\times\left(1+2\right)\\ =3\times3\\ =9\)
PL
1
3 tháng 3 2022
C=70x(3+9)-12x(65-5) C=70x. 12. - 12x. 60. C=840-720. C=120
22 tháng 12 2020
-420-{-50+[-70+65-(54-49)]}
=-420-{-50+[-70+65-54+49]}
=-420-(-50-70+65-54+49)
=-420+50+70-65+54-49
=-360
HT
4
C
23 tháng 9 2019
\(35\cdot34+70\cdot38+65\cdot75+65\cdot35\)
\(=35\cdot34+35\cdot76+65\cdot\left(75+35\right)\)
\(=35\cdot\left(34+76\right)+65\cdot110\)
\(=35\cdot110+65\cdot110\)
\(=110\cdot\left(65+35\right)\)
\(=110\cdot100=11000\)
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27 tháng 7 2021
a) Ta có: \(8^n:2^n=16^{2011}\)
\(\Leftrightarrow4^n=\left(4^2\right)^{2011}\)
\(\Leftrightarrow n=4022\)
b) Ta có: \(2^n+2^{n+3}=144\)
\(\Leftrightarrow2^n\left(1+2^3\right)=144\)
\(\Leftrightarrow2^n=16\)
hay n=4
27 tháng 7 2021
\(8^n\div2^n=16^{2011}\)
\(\left(8\div2\right)^n=\left(4^2\right)^{2011}\)
\(4^n=4^{4022}\)
\(\Rightarrow n=4022\)
mình nghĩ ý b là
\(2^n+2^{n+3}=144\)
\(2^n+2^n\cdot2^3=144\)
\(2^n\left(1+8\right)=144\)
\(2^n\cdot9=144\)
\(2^n=16\)
\(2^n=2^4\)
\(\Rightarrow n=4\)
2 tháng 1 2016
50 + 55 + 60 + 65 + 70 + 75 + 80 + 85
= ( 50 + 85 ) + ( 55 + 80 ) + ( 60 + 75 ) + ( 65 + 70 ) ------ ( có 4 cặp số )
= 135 x 4 = 540
2 tháng 1 2016
Số các số hạng là (85 - 50)/5 + 1 = 8 (số)
Tổng trên là:
8 * (85 + 50) / 2 = 540
65 + 70 : 2
= 65 + 35
= 100
\(65+70:2\)
= \(65+35\)
\(=100\)