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64^xx:16^x=256
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H9
HT.Phong (9A5)
CTVHS
1 tháng 10 2023
a) \(64^x:16^x=256\)
\(\Rightarrow\left(2^6\right)^x:\left(2^4\right)^x=2^8\)
\(\Rightarrow2^{6x}:2^{4x}=2^8\)
\(\Rightarrow2^{6x-4x}=2^8\)
\(\Rightarrow2^{2x}=2^8\)
\(\Rightarrow2x=8\)
\(\Rightarrow x=4\)
b) \(\dfrac{-2401}{7^x}=-7\)
\(\Rightarrow\dfrac{-7^4}{7^x}=-7\)
\(\Rightarrow-7^{4-x}=-7\)
\(\Rightarrow7^{4-x}=7\)
\(\Rightarrow4-x=1\)
\(\Rightarrow x=4-1\)
\(\Rightarrow x=3\)
c) \(\dfrac{64}{\left(-4\right)^x}=-256\)
\(\Rightarrow\left(-4\right)^x=\dfrac{64}{-256}\)
\(\Rightarrow\left(-4\right)^x=-4\)
\(\Rightarrow\left(-4\right)^x=\left(-4\right)^1\)
\(\Rightarrow x=1\)
T
1 tháng 10 2023
\(a) 64^x:16^x=256\\\Rightarrow (64:16)^x=256\\\Rightarrow 4^x=4^4\\\Rightarrow x=4\\---\)
\(b,\dfrac{-2401}{7^x}=-7\)
\(\Rightarrow7^x=-2401:\left(-7\right)\)
\(\Rightarrow7^x=343\)
\(\Rightarrow7^x=7^3\)
\(\Rightarrow x=3\)
\(c,\dfrac{64}{\left(-4\right)^x}=-256\)
\(\Rightarrow\left(-4\right)^x=64:\left(-256\right)\)
\(\Rightarrow\left(-4\right)^x=-\dfrac{1}{4}\)
\(\Rightarrow\left(-4\right)^x=\left(-4\right)^{-1}\)
\(\Rightarrow x=-1\)
#\(Toru\)
29 tháng 12 2018
\(64^x.16^x=256^{12}:1024\)
\(\Rightarrow\) \(\left(4^3\right)^x.\left(4^2\right)^x=\left(4^4\right)^{12}:4^5\)
\(\Rightarrow\) \(4^{3x}.4^{2x}=4^{48}:4^5\)
\(\Rightarrow\) \(4^{3x+2x}=4^{43}\)
\(\Rightarrow\) \(3x+2x=43\)
\(\Rightarrow\) \(\left(3+2\right)x=43\)
\(\Rightarrow\) \(5x=43\)
\(\Rightarrow\) \(x=\frac{43}{5}\)
SS
19 tháng 12 2021
256 x 6=512 x 3
512 x 3=256 x 6
999 x 2>1000
512 x 5>1024
1024<512 x 5
1024=512 x 2
512=256 x 2
256=128 x 2
128=64 x 2
64=32 x 2
32=16 x 2
KU
1
VA
18 tháng 7 2016
Đặt \(A=\frac{1}{8}+\frac{1}{16}+\frac{1}{32}+\frac{1}{64}+\frac{1}{128}+\frac{1}{256}\)
\(A=\frac{1}{2^3}+\frac{1}{2^4}+\frac{1}{2^5}+\frac{1}{2^6}+\frac{1}{2^7}+\frac{1}{2^8}\)
\(2A=\frac{1}{2^2}+\frac{1}{2^3}+\frac{1}{2^4}+\frac{1}{2^5}+\frac{1}{2^6}+\frac{1}{2^7}\)
\(2A-A=\left(\frac{1}{2^2}+\frac{1}{2^3}+\frac{1}{2^4}+\frac{1}{2^5}+\frac{1}{2^6}+\frac{1}{2^7}\right)-\left(\frac{1}{2^3}+\frac{1}{2^4}+\frac{1}{2^5}+\frac{1}{2^6}+\frac{1}{2^7}+\frac{1}{2^8}\right)\)
\(A=\frac{1}{2^2}-\frac{1}{2^8}\)
\(A=\frac{1}{4}-\frac{1}{256}=\frac{63}{256}\)
\(\Rightarrow\frac{63}{256}.x=\frac{1}{512}=\frac{1}{2^9}\)
\(\Rightarrow\frac{63}{2^8}.x=\frac{1}{2^9}\)
\(\Rightarrow x=\frac{1}{2^9}:\frac{63}{2^8}=\frac{1}{2^9}.\frac{2^8}{63}=\frac{1}{2.63}=\frac{1}{126}\)
Ủng hộ mk nha !!! ^_^
PT
1
16 tháng 8 2016
= (64/256 + 32/256 + 16/256 + 8/256 + 4/256 + 2/256) X x =1
= 126 X x = 1
x = 1 : 126
x= 1/126
64\(^x\) : 16\(^x\) = 256
(64: 16)\(x\) = 256
4\(^x\) = 44
\(x\) = 4
Vậy \(x\) = 4