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Đọc tiếp
1.
b) B=8\(\dfrac{1}{5}\).(11\(\dfrac{94}{1591}\)−6\(\dfrac{38}{1517}\)):8\(\dfrac{11}{43}\)
c) C=10101.(\(\dfrac{5}{111111}\)+\(\dfrac{5}{222222}\)−\(\dfrac{4}{3.7.11.13.37}\))
K
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NL
Nguyễn Lê Phước Thịnh
12 tháng 7 2023
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Những câu hỏi liên quan
12 tháng 7 2023
b: \(=8.2\left(11+\dfrac{94}{1591}-6-\dfrac{38}{1517}\right):\left(8+\dfrac{11}{43}\right)\)
\(=\dfrac{41}{5}\cdot\left(5+\dfrac{60}{1763}\right):\dfrac{355}{43}\)
\(=\dfrac{41}{5}\cdot\dfrac{8875}{1763}\cdot\dfrac{43}{355}\)
\(=5\)
c: \(=10101\cdot\left(\dfrac{10+5}{222222}-\dfrac{4}{111111}\right)\)
\(=10101\cdot\dfrac{7}{222222}=\dfrac{7}{22}\)
O
1 tháng 4 2018
\(N=8\dfrac{1}{5}\left(11\dfrac{94}{1591}-6\dfrac{38}{1517}\right):8\dfrac{11}{43}\)
\(N=\dfrac{41}{5}\left(\dfrac{17595}{1591}-\dfrac{9140}{1517}\right):\dfrac{355}{43}\)
\(N=\dfrac{41}{5}.\dfrac{8875}{1763}:\dfrac{355}{43}\)
\(N=\dfrac{1775}{43}:\dfrac{355}{43}\)
\(N=5.\)
KL
23 tháng 8 2017
1. \(\dfrac{16.17-5}{16.16-1}:\left(x-\dfrac{2}{3}\right)=\dfrac{1}{3}\)
<=> \(\dfrac{272-5}{256-1}:\left(x-\dfrac{2}{3}\right)=\dfrac{1}{3}\)
<=> \(\dfrac{267}{255}:\left(x-\dfrac{2}{3}\right)=\dfrac{1}{3}\)
<=> x - \(\dfrac{2}{3}=\dfrac{267}{85}\)
<=> x = \(\dfrac{971}{255}\)
@Triều Nguyễn Quốc
KL
23 tháng 8 2017
2. a, 8\(\dfrac{1}{5}\left(11\dfrac{94}{1591}-6\dfrac{38}{1517}\right):8\dfrac{11}{13}\)
= \(\dfrac{41}{5}\left(5\dfrac{60}{1763}\right):\dfrac{355}{43}\)
= \(\dfrac{41}{5}.\dfrac{8875}{1763}:\dfrac{355}{43}\)
= \(\dfrac{1775}{43}:\dfrac{355}{43}\)
= 5
@Triều Nguyễn Quốc
31 tháng 7 2017
Trời ơi cái đề bài !!!
Thoy thì làm từng câu vậy
a) \(I=10101.\left(\dfrac{5}{111111}+\dfrac{5}{222222}-\dfrac{4}{111111}\right)\)
\(I=10101.\left(\dfrac{10}{222222}+\dfrac{5}{222222}-\dfrac{8}{222222}\right)\)
\(I=10101.\left(\dfrac{15}{222222}-\dfrac{8}{222222}\right)\)
\(I=10101.\dfrac{7}{222222}\)
\(I=\dfrac{7}{22}\)
PM
2
31 tháng 3 2017
\(10101\cdot\left(\dfrac{5}{111111}+\dfrac{5}{222222}-\dfrac{4}{3\cdot7\cdot11\cdot13\cdot37}\right)\)=\(10101\cdot\left(\dfrac{5}{111111}+\dfrac{5}{222222}-\dfrac{4}{111111}\right)\)
= \(10101\cdot\left(\dfrac{5}{111111}-\dfrac{4}{111111}+\dfrac{5}{222222}\right)\)
= \(10101\cdot\left(\dfrac{1}{111111}+\dfrac{5}{222222}\right)\)
= \(10101\cdot\left(\dfrac{2}{222222}+\dfrac{5}{222222}\right)\)
= \(10101\cdot\dfrac{7}{222222}\)
= \(\dfrac{10101\cdot7}{222222}=\dfrac{10101\cdot7}{10101\cdot22}=\dfrac{7}{22}\)
1 tháng 4 2017
10101.(\(\dfrac{5}{111111}+\dfrac{5}{222222}-\dfrac{4}{3.7.11.13.37}\))
= 10101.(\(\dfrac{5}{111111}+\dfrac{5}{222222}-\dfrac{4}{111111}\))
= 10101.(\(\dfrac{1}{111111}+\dfrac{5}{222222}\))
= 10101. \(\dfrac{7}{222222}\)
= \(\dfrac{10101.7}{222222}\)= \(\dfrac{70707}{22222}\)=\(\dfrac{7}{22}\)
Chúc pạn hok tốt!!!!!!!
PQ
1
LG
6 tháng 7 2017
\(10101.\left(\dfrac{5}{111111}+\dfrac{5}{222222}-\dfrac{4}{3.7.11.13.37}\right)\)
\(=10101.\dfrac{5}{111111}+10101.\dfrac{5}{222222}-10101.\dfrac{4}{3.7.11.13.37}\)
\(=\dfrac{5}{11}+\dfrac{5}{22}-\dfrac{4}{11}\)
\(=\dfrac{7}{22}\)
NT
18 tháng 5 2017
\(M=\dfrac{120-\dfrac{1}{2}.40.5.\dfrac{1}{5}.20.\dfrac{1}{4}-20}{1+5+....+41}\\ =\dfrac{120-20.5-20}{1+5+...+41}\\ =\dfrac{0}{1+5+...+41}\\ =0\)
\(N=10101\left(\dfrac{6}{3.7.11.13.37}+\dfrac{6}{2.3.7.11.13.37}-\dfrac{7}{3.7.11.13.37}\right)\\ =10101\left(-\dfrac{2}{2.3.7.11.13.37}+\dfrac{6}{2.3.7.11.13.37}\right)\\ =3.7.13.37\left(\dfrac{4}{2.3.7.11.13.37}\right)=\dfrac{4}{2.11}=\dfrac{2}{11}\)
