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a: Ư(11)={1;-1;11;-11}
Ư(18)={1;-1;2;-2;3;-3;6;-6;9;-9;18;-18}
Ư(54)={1;-1;2;-2;3;-3;6;-6;9;-9;18;-18;27;-27;54;-54}
b: Ư(50)={1;-1;2;-2;5;-5;10;-10;25;-25;50;-50}
Ư(60)={1;-1;2;-2;3;-3;4;-4;5;-5;6;-6;10;-10;12;-12;15;-15;20;-20;30;-30;60;-60}
ƯC(50;60)=Ư(10)={1;-1;2;-2;5;-5;10;-10
c: 16;24;32;...;96
d:
18=3^2*2
24=2^3*3
=>BCNN(18;24)=2^3*3^2=72
BC(18;24) có 2 chữ số chỉ có 72 thôi
\(a,A\cap B=\left\{1;4\right\}\)
\(b,A=\left\{0;6;12;18;24;30;36\right\}\\ B=\left\{0;9;18;27;36\right\}\\ A\cap B=\left\{0;18;36\right\}\)
a) \(A\cap B=A=\left\{1;4\right\}\)
b)
\(A=\left\{0;6;12;18;24;30;36\right\}\\ B=\left\{0;9;18;27;36\right\}\)
\(\Rightarrow A\cap B=\left\{0;18;36\right\}\)
a: UCLN(24;40)=8
UC(24;40)={1;2;4;8}
b: UCLN(42;98)=14
UC(42;98)={1;2;7;14}
Bài 3:
a: \(\dfrac{11}{15}+\dfrac{9}{10}=\dfrac{110+135}{150}=\dfrac{245}{150}=\dfrac{49}{30}\)
b: \(\dfrac{5}{6}+\dfrac{7}{9}+\dfrac{11}{12}=\dfrac{30+28+33}{36}=\dfrac{91}{36}\)
a) A = {0; 48; 96; 144, 192;...}
* Nhận xét: Tập hợp BC(12, 16) chính là tập hợp A.
b)
i. 24 = 23.3; 30 = 2.3.5
=> BCNN(24,30) = 23. 3.5= 120
=> BC(24, 30) = B(120) = {0; 120; 240; 360;...}
ii. 42 = 2.3.7; 60 = 22.3.5
=> BCNN(42, 60) = 420
=> BC(42, 60) = B(420) = {0; 420, 840; 1260;…}.
iii. 60 = 22.3.5
150 = 2.3.52
=> BCNN(60, 150) = 22.3.52 = 300
=> BC(60, 150) = B(300) = {0; 300, 600, 900, 1200;...}.
iv. 28 = 22.7; 35 = 5.7
=> BCNN(28, 35) = 22.5.7 = 140
=> BC(28, 35) = B(140) = {0; 140; 280; 420, 560;...}.
a)
Ta có:
\(24=2^3.3\)
\(30=2.3.5\)
\(\RightarrowƯCLN\left(24;30\right)=2.3=6\)
\(\RightarrowƯC\left(24;30\right)=Ư\left(6\right)=\left\{1;2;3;6\right\}\)
b)
Ta có:
\(42=2.3.7\)
\(98=2.7^2\)
\(\RightarrowƯCLN\left(42;98\right)=2.7=14\)
\(\RightarrowƯC\left(42;98\right)=Ư\left(14\right)=\left\{1;2;7;14\right\}\)
c)
Ta có:
\(180=2^2.3^2.5\)
\(234=2.3^2.13\)
\(\RightarrowƯCLN\left(180;234\right)=2.3^2=18\)
\(\RightarrowƯC\left(180;234\right)=Ư\left(18\right)=\left\{1;2;3;6;9;18\right\}\)
a. ƯCLN(24;30) = 6
ƯC(24, 30) = {1; 2; 3; 6}
b. UCLN( 42 ; 98)= 14
ƯC(42;98) = \(\left\{1;2;7;14\right\}\)
c.UCLN( 180 ; 234 ) = 18
ƯC(180;234) = \(\left\{1;2;;6;9;18\right\}\)
Bài 1:
60= 22.3.5 ; 88 = 23.11
ƯCLN(60;88)= 22 = 4
ƯC(60;88)=Ư(4)={1;2;4}
Bài 2:
24= 23.3 ; 30=2.3.5 ; 40 = 23.5
BCNN(24;30;40)=23.3.5= 120
BC(24;30;40)=B(120)={0;120;240;360;...}