{[ 27x11 - (x + 12) x8]x3 - 79}:5=100
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TU
2
DC
21 tháng 5 2017
{[27x11-(x+12)x8]x3-79}:5=100
[27x11-(x+12)x8]x3-79=100x5=500
[27x11-(x+12)x8]x3=500+79=579
27x11-(x+12)x8=579:3=193
27x11-(x+12)=193:8=24,125
x+12=27x11-24,125
x+12=297-24,125
x+12=272,875
x=272,875-12
x=260,875.
Vay x=260,875.
LN
21 tháng 5 2017
{[27x11-(x+12)x8]x3-79}:5=100
[297 -(x+12)x8]x3-79 =100x5
[297 -(x+12)x8]x3-79 =500
[297 -(x+12)x8]x3 =500+79
[297 -(x+12)x8]x3 =579
297 -(x+12)x8 =579:3
297 -(x+12)x8 =193
(x+12)x8 =297-193
(x+12)x8 =104
x+12 =104:8
x+12 =13
x =13-12
x =1
Thử lại: {[27x11-(1+12)x8]x3-79}:5=100
7 tháng 6 2018
dấu " \(.\) " là dấu nhân
\(\left\{\left[27.11-\left(x+12\right).8\right].3-79\right\}:5=100\)
=>\(\left[297-8.x+12.8\right].3-79=100.5\)
=> \(\left[297-8.x+96\right].3-79=500\)
=> \(\left[297-8.x+96\right].3=500+79\)
=> \(\left[\left(297+96\right)-8.x\right].3=579\)
=> \(393-8.x=579:3\)
=> \(393-8.x=193\)
=> \(8.x=393-193\)
=> \(8.x=200=>x=200:8=25\)
Vậy \(x=25\)
Chúc bạn Hk tốt!!!!
6 tháng 6 2017
1) \(x^2-7x+6=x^3+1-7x-7=\left(x^3+1\right)-7\left(x+1\right)=\left(x+1\right)\left(x^2-x-6\right)\)
2) \(x^3-9x^2+6x+16\)
\(\left(x^3+1\right)-\left[\left(9x^2-6x+1\right)-16\right]\)
\(=\left(x^3+1\right)-\left[\left(3x-1\right)^2-16\right]=\left(x^3+1\right)-\left(3x-1+4\right)\left(3x-1-4\right)\)\(=\left(x^3+1\right)-3\left(3x-5\right)\left(x+1\right)\)\(=\left(x+1\right)\left[x^2-x+1-9x+15\right]=\left(x+1\right)\left(x^2-10x+16\right)\)
\(=\left(x+1\right)\left[x\left(x-2\right)-8\left(x-2\right)\right]\)\(\left(x+1\right)\left(x-2\right)\left(x-8\right)\)
3) \(x^3-6x^2-x+30\)
\(=x^3-5x^2-x^2+5x-6x+30\)
\(=x^2\left(x-5\right)-x\left(x-5\right)-6\left(x-5\right)\)
\(=\left(x-5\right)\left(x^2-x-1\right)\)
4) \(2x^3-x^2+5x+3=\left(2x^3+x^2\right)-\left(2x^2+x\right)+\left(6x+3\right)\)
\(=x^2\left(2x+1\right)-x\left(2x+1\right)+3\left(2x+1\right)\)
\(=\left(2x+1\right)\left(x^2-x+3\right)\)
5) \(27x^3-27x^2+18x-4=\left(27x^3-1\right)-\left(27x^2-18x+3\right)\)
\(=\left(3x-1\right)\left(9x^2+3x+1\right)-3\left(9x^2-6x+1\right)\)
\(=\left(3x-1\right)\left(9x^2+3x+1\right)-3\left(3x-1\right)^2\)
\(=\left(3x-1\right)\left(9x^2+3x+1-9x+3\right)=\left(3x-1\right)\left(9x^2-6x+4\right)\)
gửi phần này trước còn lại làm sau !!! tk mk nka !!!
DH
6 tháng 6 2017
a,\(x^3-7x+6\)
\(=x^3-2x^2+2x^2-4x-3x+6\)
\(=\left(x^3-2x^2\right)+\left(2x^2-4x\right)-\left(3x-6\right)\)
\(=x^2.\left(x-2\right)+2x.\left(x-2\right)-3.\left(x-2\right)\)
\(=\left(x-2\right).\left(x^2+2x-3\right)\)
\(=\left(x-2\right).\left(x^2-x+3x-3\right)\)
\(=\left(x-2\right).\left[\left(x^2-x\right)+\left(3x-3\right)\right]\)
\(=\left(x-2\right).\left[x.\left(x-1\right)+3.\left(x-1\right)\right]\)
\(=\left(x-2\right).\left(x-1\right).\left(x+3\right)\)
b,\(x^3-9x^2+6x+16\)
\(=x^3-8x^2-x^2+8x-2x+16\)
\(=\left(x^3-8x^2\right)-\left(x^2-8x\right)-\left(2x-16\right)\)
\(=x^2.\left(x-8\right)-x.\left(x-8\right)-2.\left(x-8\right)\)
\(=\left(x-8\right).\left(x^2-x-2\right)\)
\(=\left(x-8\right).\left(x^2+x-2x-2\right)\)
\(=\left(x-8\right).\left[\left(x^2+x\right)-\left(2x+2\right)\right]\)
\(=\left(x-8\right).\left[x.\left(x+1\right)-2.\left(x+1\right)\right]\)
\(=\left(x-8\right).\left(x+1\right).\left(x-2\right)\)
c,\(x^3-6x^2-x+30\)
\(=x^3-5x^2-x^2+5x-6x+30\)
\(=\left(x^3-5x^2\right)-\left(x^2-5x\right)-\left(6x-30\right)\)
\(=x^2.\left(x-5\right)-x.\left(x-5\right)-6.\left(x-5\right)\)
\(=\left(x-5\right).\left(x^2-x-6\right)\)
\(=\left(x-5\right).\left(x^2+2x-3x-6\right)\)
\(=\left(x-5\right).\left[\left(x^2+2x\right)-\left(3x+6\right)\right]\)
\(=\left(x-5\right).\left[x.\left(x+2\right)-3.\left(x+2\right)\right]\)
\(=\left(x-5\right).\left(x+2\right).\left(x-3\right)\)
Chúc bạn học tốt!!!
DH
6 tháng 6 2017
d,\(2x^3-x^2+5x+3\)
\(=2x^3+x^2-2x^2-x+6x+3\)
\(=\left(2x^3+x^2\right)-\left(2x^2+x\right)+\left(6x+3\right)\)
\(=x^2.\left(2x+1\right)-x.\left(2x+1\right)+3.\left(2x+1\right)\)
\(=\left(2x+1\right).\left(x^2-x+3\right)\)
e, \(27x^3-27x^2+18x-4\)
\(=27x^3-9x^2-18x^2+6x+12x-4\)
\(=\left(27x^2-9x^2\right)-\left(18x^2-6x\right)+\left(12x-4\right)\)
\(=9x^2.\left(3x-1\right)-6x.\left(3x-1\right)+4.\left(3x-1\right)\)
\(=\left(3x-1\right).\left(9x^2-6x+4\right)\)
Chúc bạn học tốt!!!
TM
2
20 tháng 1 2022
2 x 1 x 2 x 3 x 3 x 4 x 4 x 5 x 5 x 6 x 9 x 8 x 1 =
= 2 x 2 x 3 x 3 x 4 x 4 x 5 x 5 x 6 x 9 x 8 x 1
= 4 x 3 x 3 x 4 x 4 x 5 x 5 x 6 x 9 x 8 x 1
= 12 x 3 x 4 x 4 x 5 x 5 x 6 x 9 x 8 x 1
= 36 x 4 x 4 x 5 x 5 x 6 x 9 x 8 x 1
= 144 x 4 x 5 x 5 x 6 x 9 x 8 x 1
= 576 x 5 x 5 x 6 x 9 x 8 x 1
= 2 880 x 5 x 6 x 9 x 8 x 1
= 14 400 x 6 x 9 x 8 x 1
= 86 400 x 9 x 8 x 1
= 777 600 x 8 x 1
= 6 220 800 x 1
= 6 220 800
:)
Y
10 tháng 2 2023
\(7\times11-\left(x+12\right)\times8\times3-79:5=100\)
\(\Rightarrow77-24x-288-15,8-100=0\)
\(\Rightarrow-24x=326,8\)
\(\Rightarrow x=-\dfrac{817}{60}\)
10 tháng 2 2023
=>77-(x+12)*24-79:5=100
=>(x+12)*24=-38,8
=>x+12=-97/60
=>x=-817/60
DN
7
NT
1
MP
3 tháng 7 2018
{ [ 27 * 11 - ( x + 12 ) * 8 ] * 3 - 79 } : 5 = 100
[ 297 - ( x + 12 ) * 8 ] * 3 - 79 = 100 * 5
[ 297 - ( x + 12 ) * 8 ] * 3 - 79 = 500
[ 297 - ( x + 12 ) * 8 ] * 3 = 500 + 79
[ 297 - ( x + 12 ) * 8 ] * 3 = 579
297 - ( x + 12 ) * 8 = 579 : 3
297 - ( x + 12 ) * 8 = 193
( x + 12 ) * 8 = 297 - 193
( x + 12 ) * 8 = 104
x + 12 = 104 : 8
x + 12 = 13
x = 13 - 12
x = 1.^^
{ [ 27 \(\times\) 11 - (\(x\) + 12) \(\times\)8]\(\times\) 3 - 79}: 5 = 100
[ 27 \(\times\) 11 - (\(x+12\)) \(\times\)8] \(\times\) 3 - 79 = 100 \(\times\) 5
[ 27 \(\times\) 11 - (\(x+12\)) \(\times\)8] \(\times\) 3 - 79 = 500
[ 27 \(\times\) 11 - (\(x\) + 12) \(\times\)8] \(\times\) 3 = 500 + 79
[27 \(\times\) 11 - (\(x+12\))\(\times\) 8] \(\times\) 3 = 579
27 \(\times\) 11 - (\(x+12\)) \(\times\) 8 = 579 : 3
27 \(\times\) 11 - (\(x+12\))\(\times\) 8= 193
297 - (\(x+12\)) \(\times\) 8 = 193
( \(x+12\)) \(\times\) 8 = 297 - 193
\(x\) + 12 = 104 : 8
\(x\) + 12 = 13
\(x\) = 13 - 12
\(x\) = 1