Question

[💎IdolシƚɨɲɦEoʋɨ︵²ᵏ♫]

bài 1

a)\(\dfrac{-6}{11}\):(\(\dfrac{3}{5}\)x\(\dfrac{4}{11}\))              

b)\(\dfrac{7}{12}\)+\(\dfrac{5}{12}\):6-\(\dfrac{11}{36}\)

bài 2

a)x+\(\dfrac{1}{3}\)=\(\dfrac{7}{26}\)x\(\dfrac{-13}{6}\)

b)\(\dfrac{x}{150}\)=\(\dfrac{5}{6}\)x\(\dfrac{-7}{25}\)

c)\(x\)x\(\dfrac{3}{5}\)=\(\dfrac{2}{5}\)

mng trả lời nhanh giúp mik vs.

Answer 1

[ミ★Zero ❄ ( Hoàng Nhật )]

Bài 1 

a, \(-\dfrac{6}{11}:\left(\dfrac{3}{5}.\dfrac{4}{11}\right)=-\dfrac{6}{11}:\dfrac{12}{55}=-\dfrac{6}{11}.\dfrac{55}{12}=-\dfrac{5}{2}\)

b, \(\dfrac{7}{12}+\dfrac{5}{12}:6-\dfrac{11}{36}=\dfrac{7}{12}+\dfrac{5}{72}-\dfrac{11}{36}=\dfrac{42+5-22}{72}=\dfrac{25}{72}\)

Bài 2 

a, \(x+\dfrac{1}{3}=\dfrac{7}{26}.\left(-\dfrac{13}{6}\right)\)

\(\Leftrightarrow x+\dfrac{1}{3}=-\dfrac{7}{12}\Leftrightarrow x=-\dfrac{7}{12}-\dfrac{1}{3}=\dfrac{-7-4}{12}=-\dfrac{11}{12}\)

b, \(\dfrac{x}{150}=\dfrac{5}{6}.\left(-\dfrac{7}{25}\right)\)

\(\Leftrightarrow\dfrac{x}{150}=-\dfrac{7}{30}\Leftrightarrow x=\left(-\dfrac{7}{30}\right).150=-35\)

c, \(x.\dfrac{3}{5}=\dfrac{2}{5}\Leftrightarrow x=\dfrac{2}{5}:\dfrac{3}{5}=\dfrac{2}{5}.\dfrac{5}{3}=\dfrac{2}{3}\)