5.22+(x+3)=52
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= 5.4 + ( x+3) = 25
20 + (x+3) = 25
x + 3 = 25 - 20 =5
x = 5 - 3 =2
![](https://rs.olm.vn/images/avt/0.png?1311)
a) 5.22 + (x + 3) = 52
5.4 + (x + 3) = 25
20 + (x + 3) = 25
x + 3 = 25 – 20
x + 3 = 5
x = 5 – 3 = 2
b) 23 + (x – 32) = 53 - 43
8 + (x – 9) = 125 – 64
8 + (x – 9) = 61
x – 9 = 61 – 8
x – 9 = 53
x = 53 + 9 = 62
a) \(5.2^2+\left(x+3\right)=5^2\)
\(x+3=5^2-5.2^2\)
\(x+3=25-20\)
\(x+3=5\)
\(x=2\)
b) \(2^3+\left(x-3^2\right)=5^3-4^3\)
\(8+\left(x-9\right)=125-64\)
\(x-9=53\)
\(x=62\)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(3^2\left(x+4\right)-5^2=5\cdot2^2\\ 9\left(x+4\right)-25=20\\ 9\left(x+4\right)=20+25\\ 9\left(x+4\right)=45\\ x+4=45:9\\ x+4=5\\ x=5-4\\ x=1\)
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a)100:25+7.9=4+16=20
b)84:4+9+1=31
c)29-(16+3.1)=10
d)5.4+98:49=20+2=22
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\(a)\) \(5^{13}:5^{10}-25.2^2=5^3-25.4=125-100=25\)
\(b)\) \(20:2^2+5^9:5^8=20:4+5^1=5+5=10\)
\(c)\) \(100:5^2+7.3^2=100:25+7.9=4+36=40\)
\(d)\) \(84:4+3^9:3^7+5^0=84:4+3^2+1=21+9+1=31\)
\(e)\)
\(29-\left[16+3.\left(51-49\right)\right]=29-\left[16+3.2\right]=29-\left[16+6\right]=29-22=7\)
\(f)\) \(5.2^2+98:7^2=5.4+98:49=20+2=22\)
\(g)\) \(3^{11}:3^9-147:7^2=3^2-147:49=9-3=6\)
\(295-\left(31-2^2.5\right)^2=295-\left(31-4.5\right)^2=295-\left(31-20\right)^2=295-11^2=295-121=174\)
\(7^{18}:7^{16}+2^2.3^2=7^2+4.9=49+36=85\)
a: \(5^{13}:5^{10}-25\cdot2^2\)
\(=5^3-25\cdot4\)
=125-100
=25
b: \(20:2^2+5^9:5^8\)
\(=20:4+5\)
=5+5
=10
![](https://rs.olm.vn/images/avt/0.png?1311)
\(3^2\cdot\left(x+4\right)-5^2=5\cdot22\)
\(\Rightarrow9\cdot\left(x+4\right)-25=110\)
\(\Rightarrow9\cdot\left(x+4\right)=110+25\)
\(\Rightarrow9\cdot\left(x+4\right)=135\)
\(\Rightarrow x+4=\dfrac{135}{9}\)
\(\Rightarrow x+4=15\)
\(\Rightarrow x=15-4\)
\(\Rightarrow x=11\)
`#3107`
\(3^2\cdot\left(x+4\right)-5^2=5\cdot22\\ \Rightarrow3^2\left(x+4\right)=5\cdot22+5^2\\ \Rightarrow9\left(x+4\right)=110+25\\ \Rightarrow9\left(x+4\right)=135\\ \Rightarrow x+4=135\div9\\ \Rightarrow x+4=15\\ \Rightarrow x=15-4\\ \Rightarrow x=11\)
Vậy, `x = 11.`
![](https://rs.olm.vn/images/avt/0.png?1311)
\(a,\)\(25+3\left(x-8\right)=106.\)
\(\Rightarrow25+3x-24=106\)
\(\Rightarrow3x+1=106\)
\(\Rightarrow3x=105\)\(\Rightarrow x=35\)
\(b,3^2\left(x+4\right)-5^2=5.22\)
\(\Rightarrow9\left(x+4\right)-25=110\)
\(\Rightarrow9x+36-25=110\)
\(\Rightarrow9x+11=110\)
\(\Rightarrow9x=99\Leftrightarrow x=11\)
\(a,25:3\left(x-8\right)=106\)
\(\Rightarrow25+3x-24=106\)
\(\Rightarrow3x+1=106\)
\(\Rightarrow x=35\)
\(b,3^2\left(x+4\right)-5^2=5.22\)
\(\Rightarrow9x+36-25=110\)
=\(9x+11=110\)
\(\Rightarrow9x=99\)
\(\Rightarrow x=11\)
![](https://rs.olm.vn/images/avt/0.png?1311)
5 . 22 + ( x + 3 ) = 52
5 . 4 + ( x + 3 ) = 25
20 + ( x + 3 ) = 25
x + 3 = 5
x = 2