M=(x^2-3xy+2y^2)(x-2y)-4y^2.(2x-y) tại x=1,y=-3598
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a: \(N=\dfrac{3x^5-4x^4+6x^3}{-2x^2}=-\dfrac{3}{2}x^3+2x^2-3x\)
b: \(N=\dfrac{\left(6x^4y^5-3x^3y^4+\dfrac{1}{2}x^4y^3z\right)}{-\dfrac{1}{3}x^2y^3}=-18x^2y^2+9xy-\dfrac{3}{2}x^2z\)
c: \(\Leftrightarrow N\cdot\left(y-x\right)=\left(x-y\right)^3\)
\(\Leftrightarrow N=\dfrac{\left(x-y\right)^3}{y-x}=-\left(y-x\right)^2\)
d: \(\Leftrightarrow N\cdot\left(y^2-x^2\right)=\left(y^2-x^2\right)^2\)
hay \(N=y^2-x^2\)
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a: \(A=2\left(x+y\right)+3xy\left(x+y\right)+5x^2y^2\left(x+y\right)=0\)
b: \(B=3xy\left(x+y\right)+2x^2y\left(x+y\right)=0\)
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mik ko bít
I don't now
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`a, -xy(x^2+xy-y^2)`
`= -x^3y - x^2y^2 + xy^3`.
`b, 5x^2y(2y^2-xy)`
`= 10x^2y^3 - 5x^3y^2`.
`c, (-2x^3 - 1/4y - 4y^2).8xy^2`.
`= -16x^4y^2 - 2xy^3 - 32xy^4`.
`d, (2x^3 - 3xy + 12x)(-1/6xy)`
`= -2/3x^4y + 1/2x^2y^2 - 2x^2y`.
\(M=\left(x^2-3xy+2y^2\right).\left(x-2y\right)-4y^2.\left(2x-y\right)\)
\(\Rightarrow M=-4y^3+8xy^2-5x^2y+x^3-8xy^2+4y^3\)
\(\Rightarrow M=x^3-5x^2y\)
Ta thay \(x=1,y=-3598\) vào M:
\(M=1^3-5.1^2.\left(-3598\right)=17991\)